Topic 08 | Physical sciences

Simple machines

Year 7 (Levels 7-8 band): the six simple machines (lever, inclined plane, wedge, pulley, screw, wheel and axle) and how they change the direction or size of a force.

40-60 min Printable practice Answer key Challenge included
How to use this page

Read the explanation, work through the examples, then complete the core practice before printing.

Study progress: Not started

What you will learn

Worked example 0 Real-world example: a crowbar lifting a heavy crate

A crate weighs 600600 N. You use a 2.02.0 m crowbar and place the pivot (fulcrum) 0.200.20 m from the crate. How much force do you need at the far end?

  1. The lever rule: load arm × load force = effort arm × effort force. FLdL=FEdEF_L \, d_L = F_E \, d_E.
  2. Load arm dL=0.20d_L = 0.20 m. Effort arm dE=2.00.20=1.80d_E = 2.0 - 0.20 = 1.80 m.
  3. 600×0.20=FE×1.80600 \times 0.20 = F_E \times 1.80.
  4. FE=1201.80=66.7F_E = \dfrac{120}{1.80} = 66.7 N.

You only need about 6767 N — roughly the weight of a 77 kg bag — to lift a 6060 kg crate.

Key idea: the longer the effort arm compared to the load arm, the smaller the effort force needed. But you have to move the effort end further.

1. The six simple machines

Every complicated machine (a bicycle, a crane, a piano) is built from combinations of these.

2. Levers and the lever rule

LoadEffortFulcrumload armeffort arm
A first-class lever. Load and effort are on opposite sides of the fulcrum.

Lever rule

Balance condition
FLdL=FEdEF_L \, d_L = F_E \, d_E

FLF_L = load force, dLd_L = distance from load to fulcrum, FEF_E = effort force, dEd_E = distance from effort to fulcrum.

Three classes of lever:

  1. Class 1 — fulcrum in the middle. Examples: see-saw, crowbar, scissors.
  2. Class 2 — load in the middle. Examples: wheelbarrow, bottle-opener.
  3. Class 3 — effort in the middle. Examples: tweezers, fishing rod, human forearm.
Worked example 1 Balancing a see-saw

A 4040 kg child sits 22 m from the fulcrum. Where should a 6060 kg child sit to balance?

  1. Weights: 40×10=40040 \times 10 = 400 N and 60×10=60060 \times 10 = 600 N.
  2. Balance: 400×2=600×d400 \times 2 = 600 \times d.
  3. d=800/600=1.33d = 800/600 = 1.33 m.

The heavier child must sit closer to the fulcrum.

3. Mechanical advantage

Mechanical advantage (MA) measures how many times a machine multiplies your effort.

Mechanical advantage
MA=load forceeffort force=FLFE\text{MA} = \dfrac{\text{load force}}{\text{effort force}} = \dfrac{F_L}{F_E}

An MA of 44 means you can lift a 400400 N load with only 100100 N of effort.

Worked example 2 Mechanical advantage of a crowbar

In the crowbar worked example above, load was 600600 N and effort was about 6767 N.

MA=600679.\text{MA} = \dfrac{600}{67} \approx 9.

The crowbar multiplied the effort by about 99 times.

4. Inclined planes and wedges

A ramp lets you trade force for distance. A 33 m ramp rising 11 m in height moves 33 m of distance for every 11 m of lift — and needs about a third of the vertical lifting force.

Worked example 3 Pushing a barrel up a ramp

A 300300 N barrel must be lifted onto a truck 1.01.0 m high. A ramp of length 3.03.0 m is used.

  1. Work done lifting straight up: 300 N×1.0 m=300300 \text{ N} \times 1.0 \text{ m} = 300 J.
  2. Pushing along the ramp, same work done over 3.03.0 m (in an ideal ramp): force =300/3.0=100= 300/3.0 = 100 N.
  3. MA =300/100=3= 300/100 = 3.

You push with one-third of the direct force, but move three times the distance.

Key idea: a machine never reduces the work required (in the ideal case). It only changes the balance between force and distance.

A wedge is a moving inclined plane — axes and knives use wedges to split wood or food.

5. Pulleys

A single fixed pulley changes the direction of a force but not the size. Using two ropes to support a load (a movable pulley system) halves the effort force — but you must pull twice as much rope.

Worked example 4 Pulley to lift a bucket

A single fixed pulley is used to lift a 200200 N bucket from a well. You pull down on the rope.

  1. Effort needed: 200200 N (same as the weight).
  2. Direction: you pull downward; the bucket goes upward.

Now with two ropes supporting the bucket (block and tackle):

  1. Each rope supports half the weight, so effort =100= 100 N.
  2. You must pull 22 m of rope for every 11 m the bucket rises.
  3. MA =2= 2.

Key idea: pulleys can change direction, size, or both — depending on how the ropes are configured.

6. Wheel and axle; screws

A wheel and axle (e.g. a tap or a doorknob) uses a large wheel turned by a small force to turn a small axle with a larger force. The larger the wheel vs the axle, the bigger the mechanical advantage.

A screw is an inclined plane wrapped around a cylinder. Turning the screw converts a rotation (a small force over many turns) into a powerful forward push through wood or metal.


Practice: Year 7

Fluency

Tier 1: recall and identify

    1. Name the six simple machines.
    2. State the lever rule in symbols.
    3. For a wheelbarrow, identify: fulcrum, effort, load. Which class of lever is it?
    4. What is mechanical advantage?
    5. A force of 5050 N lifts a 200200 N load. Find the MA.
    6. A lever has load 300300 N at 0.50.5 m from the fulcrum, effort applied at 1.51.5 m. Find the effort force.
    7. A ramp 44 m long is used to lift a 100100 N box 11 m high. What force is needed, ideally?
    8. Give an everyday example of a class-3 lever.
    9. What does a single fixed pulley change: direction, size, or both?
    10. A screw is equivalent to what other simple machine wrapped around a cylinder?
Reasoning

Tier 2: explain and reason

    1. Explain why pushing a 100100 kg piano up a ramp is easier than lifting it straight up.
    2. Why must the effort arm of a lever be longer than the load arm to give MA greater than 11?
    3. A pulley system has MA =3= 3. Explain what that means for the effort force and the length of rope pulled.
    4. Two people sit on a see-saw. Explain why the heavier person moves closer to the fulcrum to balance.
    5. Why is no simple machine 100%100\% efficient in the real world?
    6. A carpenter uses the claw end of a hammer to pull out a nail. Explain how this works as a lever.
Problem solving

Tier 3: apply to a novel context

    1. A 6060 kg child sits at one end of a 44 m see-saw with the fulcrum in the middle. Where should a 4040 kg child sit to balance?
    2. A ramp is used to roll a 500500 N barrel into a truck 1.21.2 m high. If the effort needed is 150150 N (ideal), how long is the ramp?
    3. A block and tackle has MA =4= 4 and is used to lift a 600600 N load 22 m. What force is needed? How much rope is pulled?
    4. A nutcracker has its hinge at one end, nut in the middle, and hands at the other end. Which class of lever is it? Explain.

Challenge

Reasoning

Harder reasoning

    1. A bicycle uses gears — a variable wheel-and-axle system. Explain why a low gear is chosen for climbing a hill and a high gear for flat roads, using the idea of trading force for distance.
    2. A 22 m lever with fulcrum in the middle balances a 5050 N weight on one end with a 5050 N weight on the other. A student slides both weights to within 0.20.2 m of the fulcrum (on opposite sides). Does the lever still balance? Justify.
    3. A real ramp has friction that absorbs 20%20\% of the work. A 400400 N box is lifted 11 m using a 44 m ramp. Calculate the ideal effort, the actual effort, and the efficiency.
    4. Pulleys used in construction can have MA of 88 or more. Explain why workers do not simply use a crane (lever system) instead, and what trade-offs matter on a real building site.
Answers

Answer key

Attempt the practice first. When you're ready to check, expand the answers below.

Show the full answer key

Year 7 answers

Fluency

Tier 1: recall and identify

    1. Lever, inclined plane, wedge, screw, pulley, wheel and axle.
    2. FLdL=FEdEF_L d_L = F_E d_E.
    3. Fulcrum: the wheel at the front. Effort: handles (lifted by person). Load: weight of material in tray. Class 2 (load between fulcrum and effort).
    4. The ratio of the load force to the effort force — how many times the machine multiplies your effort.
    5. MA=200/50=4\text{MA} = 200/50 = 4.
    6. 300×0.5=FE×1.5FE=150/1.5=100300 \times 0.5 = F_E \times 1.5 \Rightarrow F_E = 150/1.5 = 100 N.
    7. 100×1=FE×4FE=25100 \times 1 = F_E \times 4 \Rightarrow F_E = 25 N.
    8. Tweezers, fishing rod, human forearm lifting a weight, a broom.
    9. Direction only.
    10. An inclined plane.
Reasoning

Tier 2: explain and reason

    1. A ramp lets you apply a smaller force over a longer distance. The work done (force × distance) is about the same either way, but the smaller force is achievable by one person.
    2. The lever rule FLdL=FEdEF_L d_L = F_E d_E can be rearranged to FE=FL×dL/dEF_E = F_L \times d_L/d_E. For FE<FLF_E < F_L (that is, MA > 1), the denominator must be larger, so dE>dLd_E > d_L.
    3. MA = 3 means the effort is 1/31/3 of the load. In return, the rope pulled is 33 times the distance the load moves.
    4. The lever rule requires FLdL=FEdEF_L d_L = F_E d_E. If the weights are fixed, a heavier load must sit at a shorter distance from the fulcrum to balance the lighter person at a longer distance.
    5. Friction at the fulcrum, along ramps, and in pulley bearings converts some of the input work to heat. Real MA is always slightly less than ideal MA.
    6. The nail is the load, the hammer’s head is the fulcrum, and your hand on the handle applies the effort. The long handle and short claw give a large effort arm : load arm ratio — high MA.
Reasoning

Tier 3: apply to a novel context

    1. Weights: 60×10=60060 \times 10 = 600 N and 40×10=40040 \times 10 = 400 N. Let dd be distance for the 4040 kg child. 600×2=400×dd=3600 \times 2 = 400 \times d \Rightarrow d = 3 m. But the see-saw is only 44 m long with the fulcrum in the middle — 22 m each side. So balance is impossible unless the fulcrum is moved. (Good — forces students to notice infeasibility.)
    2. Ideal: work in = work out. 500×1.2=150×LL=600/150=4500 \times 1.2 = 150 \times L \Rightarrow L = 600/150 = 4 m.
    3. Effort: 600/4=150600/4 = 150 N. Rope pulled: 4×2=84 \times 2 = 8 m.
    4. Class 2 lever — the load (nut) is between the fulcrum (hinge) and the effort (hands).
Reasoning

Challenge

    1. Low gear (small front ring + large rear ring) gives a high MA: your pedal force at the chain is multiplied at the wheel, so climbing a hill needs less effort per pedal stroke, but you pedal more times for each wheel turn. High gear is the reverse: less force multiplication but the wheel turns further per pedal stroke — useful at speed on flat roads.
    2. Yes — balance depends only on torque ratio, not absolute distances. 50×0.2=50×0.250 \times 0.2 = 50 \times 0.2. It still balances.
    3. Ideal effort: 400×1/4=100400 \times 1 / 4 = 100 N. With 20%20\% loss, work in = 400400 J / 0.8=5000.8 = 500 J. Actual effort =500/4=125= 500/4 = 125 N. Efficiency = 400/500=80%400/500 = 80\%.
    4. Pulley systems scale well with large MA in a small footprint and are safer than levers for tall buildings. Crane levers require long rigid arms and huge counterweights. Pulleys also allow workers to stand safely away from the load. Trade-offs: pulleys can jam, need strong ropes, and have more friction; cranes lift faster.

Prefer paper? Print the answer key as a separate booklet: open print view ->