Topic 11 | Measurement & Space

3D objects

Year 7 core: naming prisms and pyramids, drawing and interpreting nets, and two-dimensional representations of three-dimensional objects.

35-45 min Printable practice Answer key Extension included
How to use this page

Learn the core, work through the examples, finish the core practice, then move to extension if you still have time and focus.

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Year 7 core

By the end of this topic you should be able to:

1. Prisms and pyramids

triangular prismapexsquare pyramid
A triangular prism (two triangular ends joined by rectangles) and a square pyramid (a square base with triangular side-faces meeting at an apex).

A prism has two identical, parallel end-faces (the bases) joined by rectangular side-faces. It is named after the shape of its base.

PrismBase shape
Triangular prismtriangle
Rectangular prism (cuboid)rectangle
Pentagonal prismpentagon
Cubesquare

A pyramid has a polygon base and triangular side-faces that meet at a single point (the apex).

PyramidBase shape
Triangular pyramid (tetrahedron)triangle
Square pyramidsquare
Pentagonal pyramidpentagon

2. Faces, edges, vertices

SolidFacesEdgesVertices
Cube66121288
Rectangular prism66121288
Triangular prism559966
Square pyramid558855
Triangular pyramid (tetrahedron)446644

3. Nets

A net is a flat pattern that folds up to form a 3D shape. There are 1111 different nets for a cube (all made from six squares arranged so they fold into a closed box).

net of a cube
A net of a cube: six squares laid flat that fold up into a cube. Eleven different nets work; this is one.
Worked example 1 Triangular prism net

A triangular prism has 22 triangular end-faces and 33 rectangular side-faces. Its net has:

  • 22 triangles matching the two ends,
  • 33 rectangles whose widths match the sides of the triangles.

Laid out in order, the three rectangles form a single long strip with the two triangles attached to one side.

4. Two-dimensional representations

Solid objects can be drawn in 2D in several useful ways:


Practice: Year 7 core

Fluency

Naming, faces, edges, vertices

    1. How many faces, edges, and vertices does a cube have?
    2. How many faces, edges, and vertices does a triangular prism have?
    3. How many faces, edges, and vertices does a square pyramid have?
    4. Name the solid with 44 triangular faces and 44 vertices.
    5. Name the solid with a hexagonal base and 66 rectangular side-faces.
    6. How many rectangular faces does a pentagonal prism have?
    7. How many triangular faces does a square pyramid have?
Fluency

Nets

    1. How many different nets fold into a cube?
    2. List the shapes in a net of a triangular prism.
    3. List the shapes in a net of a rectangular prism with dimensions 3×2×43 \times 2 \times 4.
    4. Draw (or describe) a net for a square pyramid with base side 44 cm and slant height 55 cm.
    5. A net of six squares in one long straight row - can this fold into a cube? Explain.
Reasoning

Explain and spot the mistake

    1. Maya says: “every pyramid has a triangular base”. Is this true? Explain.
    2. Sam counts the faces of a triangular prism as 66. Where could Sam’s error be?
    3. Is a cylinder a prism? Explain using the definition of a prism.
    4. You see the isometric drawing of an object but cannot tell whether the left side is longer than the front side. Describe one extra drawing that would resolve the ambiguity.
Problem solving

Real-world problems

    1. A cereal box is a rectangular prism 30×20×830 \times 20 \times 8 cm. Find its total surface area and its volume.
    2. A Toblerone box is a triangular prism with equilateral cross-section (side 66 cm) and length 2424 cm. Describe the net (number and size of each shape).
    3. A square pyramid has base 88 cm and slant height 55 cm. Find its total surface area. (Base area +4×+ 4 \times triangular side area.)
    4. A shipping crate is a 11 m cube. What is the total length of all its edges?

Extension

Counting formulas and Euler

Prism with an n-sided base
V=2n,E=3n,F=n+2.V = 2n, \quad E = 3n, \quad F = n + 2.

A triangular prism (n=3n = 3) has V=6V = 6, E=9E = 9, F=5F = 5.

Pyramid with an n-sided base
V=n+1,E=2n,F=n+1.V = n + 1, \quad E = 2n, \quad F = n + 1.

A square pyramid (n=4n = 4) has V=5V = 5, E=8E = 8, F=5F = 5.

Euler's formula (every convex polyhedron)
VE+F=2.V - E + F = 2.

Practice: Extension

Reasoning

Using the formulas

    1. A prism has a 77-sided base. Find VV, EE, FF.
    2. A pyramid has a hexagonal base. Find VV, EE, FF.
    3. A solid has V=20V = 20, E=30E = 30. Use Euler’s formula to find FF.
    4. A solid has V=6V = 6, F=8F = 8. Find EE.
    5. A solid has 88 triangular faces. Give its name.
Answers

Answer key

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Year 7 core - answers

Fluency

Naming, faces, edges, vertices

    1. Cube: F=6F = 6, E=12E = 12, V=8V = 8.
    2. Triangular prism: F=5F = 5, E=9E = 9, V=6V = 6.
    3. Square pyramid: F=5F = 5, E=8E = 8, V=5V = 5.
    4. Triangular pyramid (tetrahedron).
    5. Hexagonal prism.
    6. 55 rectangular faces (plus 22 pentagonal ends).
    7. 44 triangular faces.
Fluency

Nets

    1. 1111.
    2. 22 triangles and 33 rectangles.
    3. 66 rectangles: two 3×23 \times 2, two 3×43 \times 4, two 2×42 \times 4.
    4. A 44 cm square with four isosceles triangles attached to each side, each triangle with base 44 cm and slant height 55 cm.
    5. No. Six squares in a single row overlap when folded - they cannot form a closed cube.
Reasoning

Explain and spot the mistake

    1. Not true. A pyramid’s side-faces are always triangles, but the base can be any polygon (square, pentagon, etc.). “Triangular pyramid” is one particular type.
    2. A triangular prism has 55 faces: 22 triangular ends and 33 rectangular sides. Sam probably mixed faces with edges (which total 99) or counted the same face twice.
    3. Strictly no - a prism has a polygon base joined by flat rectangular sides. A cylinder has a circular base and a curved surface, not a polygon. (It is often informally called a circular prism because the volume formula V=base area×heightV = \text{base area} \times \text{height} still applies.)
    4. A top view (plan) or a side elevation would resolve the ambiguity, since those show lengths directly without the isometric distortion.
Problem solving

Real-world problems

    1. Surface area 20002000 cm^2; volume 48004800 cm^3. Method: SA =2(30×20+30×8+20×8)=2(600+240+160)=2000= 2(30 \times 20 + 30 \times 8 + 20 \times 8) = 2(600 + 240 + 160) = 2000; V=30×20×8V = 30 \times 20 \times 8.
    2. 22 equilateral triangles (side 66 cm) and 33 rectangles (66 cm by 2424 cm).
    3. 144144 cm^2. Method: base 82=648^2 = 64; four triangles each 12×8×5=20\tfrac{1}{2} \times 8 \times 5 = 20; total =64+4×20= 64 + 4 \times 20.
    4. 1212 m. Method: a cube has 1212 edges, each 11 m.

Extension - answers

Reasoning

Using the formulas

    1. V=14V = 14, E=21E = 21, F=9F = 9. Method: n=7n = 7; V=2nV = 2n, E=3nE = 3n, F=n+2F = n + 2.
    2. V=7V = 7, E=12E = 12, F=7F = 7. Method: n=6n = 6; V=n+1V = n + 1, E=2nE = 2n, F=n+1F = n + 1.
    3. F=12F = 12. Method: VE+F=2V - E + F = 2.
    4. E=12E = 12. Method: 6E+8=26 - E + 8 = 2, so E=12E = 12.
    5. Regular octahedron.

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