Year 9 Science | Victorian Curriculum 2.0
Atomic model evolution & radioactivity
Topic 04 | Chemical sciences | Practice

What you will learn

  • trace how the atomic model changed through the work of Dalton, Thomson, Rutherford, Bohr, and quantum physicists,
  • describe the structure of an atom in terms of protons, neutrons, and electrons,
  • define isotope and use mass number / atomic number notation,
  • describe alpha, beta, and gamma radioactive decay and write decay equations,
  • use the half-life formula N=N0(12)t/t1/2N = N_0 \left(\dfrac{1}{2}\right)^{t/t_{1/2}}N=N0​(21​)t/t1/2​ for simple calculations.
Why did the model keep changing?

Science does not deliver final answers — it builds the best model consistent with current evidence. Each experiment (cathode rays, gold foil, spectral lines) revealed something the old atomic model could not explain, and a new model was proposed. When evidence later contradicted that model, it too was revised. This is how science works: contestable, refined, replicated. The quantum model we use today will likely be refined again as better experiments arrive.

Where you'll see this
  • Medicine: PET scans and radiotherapy use specific radioactive isotopes.
  • Archaeology: carbon-14 dating estimates the age of organic remains.
  • Energy: nuclear power stations use controlled decay of uranium-235.
  • Smoke alarms: americium-241 emits alpha particles that ionise air in the detector.
  • Industry: thickness gauges, food sterilisation, tracer studies in pipelines.
Worked example 0 Real-world example: smoke alarm in your ceiling

A household smoke alarm contains a tiny amount of americium-241, an alpha emitter with half-life about 432 years.

  1. Alpha particles ionise air molecules in a small chamber, allowing a tiny current to flow.
  2. Smoke particles disrupt the ionisation and reduce the current — the alarm triggers.
  3. Because the half-life is long, the source’s activity barely changes over the alarm’s 10-year lifetime.
  4. Alpha particles travel only a few cm in air and are stopped by the plastic case, so external exposure is negligible.

Key idea: the right isotope for a job matches the type of radiation, the activity, and the half-life to the application.

1. How the model of the atom changed

YearScientistModelKey evidence
1803Daltonsolid indivisible sphereconstant proportions in compounds
1897Thomson”plum pudding” — electrons in a positive cloudcathode-ray tube showed negatively charged particles
1911Rutherfordtiny dense positive nucleus, electrons around itgold-foil experiment: most alpha particles passed through, a few deflected
1913Bohrelectrons in fixed circular orbits (shells)hydrogen line spectrum
1920s+Schrodinger / quantumelectrons in orbitals (probability clouds)wave-particle duality, Heisenberg uncertainty
Daltonsolid sphereThomsonplum puddingRutherfordnuclearBohrshells
Four key atomic models in sequence. Each was the best fit to the evidence of its time, and each was later revised when new evidence appeared.

2. Structure of an atom

ParticleChargeRelative massLocation
Proton+1+1+11nucleus
Neutron0001nucleus
Electron−1-1−111836≈0\dfrac{1}{1836} \approx 018361​≈0orbitals around nucleus

Notation: ZAX^{A}_{Z}\text{X}ZA​X, where ZZZ is the atomic number (protons) and AAA is the mass number (protons + neutrons).

  • Number of neutrons =A−Z= A - Z=A−Z.
  • Neutral atom: number of electrons === number of protons.

3. Isotopes

Isotopes are atoms of the same element (same ZZZ) with different numbers of neutrons (different AAA).

  • Carbon-12 (612C^{12}_{6}\text{C}612​C): 6 protons, 6 neutrons — stable.
  • Carbon-14 (614C^{14}_{6}\text{C}614​C): 6 protons, 8 neutrons — radioactive.

All isotopes of an element have the same chemistry (because chemistry depends on electrons) but different nuclear properties.

Worked example 1 Identifying particles

For 92238U^{238}_{92}\text{U}92238​U, state the number of protons, neutrons, and electrons (neutral atom).

  1. Protons: Z=92Z = 92Z=92.
  2. Neutrons: A−Z=238−92=146A - Z = 238 - 92 = 146A−Z=238−92=146.
  3. Electrons: 92 (neutral).

4. Radioactive decay

Unstable (radioactive) nuclei spontaneously emit radiation and become more stable. Three common decay types.

Types of radioactive decay

Alpha decay ($\alpha$)

A helium-4 nucleus is emitted; ZZZ decreases by 2, AAA decreases by 4.

ZAX→ Z−2A−4Y+ 24α^{A}_{Z}\text{X} \to \,^{A-4}_{Z-2}\text{Y} + \,^{4}_{2}\alphaZA​X→Z−2A−4​Y+24​α
Beta decay ($\beta^{-}$)

A neutron converts to a proton + electron; the electron is emitted. ZZZ increases by 1, AAA is unchanged.

ZAX→ Z+1AY+ −10β^{A}_{Z}\text{X} \to \,^{A}_{Z+1}\text{Y} + \,^{0}_{-1}\betaZA​X→Z+1A​Y+−10​β
Gamma emission ($\gamma$)

A high-energy photon is released, often after alpha or beta decay. AAA and ZZZ are unchanged.

Penetration and shielding:

RadiationChargeStopped by
Alpha+2+2+2a sheet of paper or a few cm of air
Beta−1-1−1a few mm of aluminium
Gamma000dense lead or thick concrete
Worked example 2 Writing a decay equation

Uranium-238 undergoes alpha decay. Write the nuclear equation and identify the daughter nucleus.

  1. Alpha decay: AAA drops by 4, ZZZ drops by 2.
  2. 92238U→ 90234Th+ 24α^{238}_{92}\text{U} \to \,^{234}_{90}\text{Th} + \,^{4}_{2}\alpha92238​U→90234​Th+24​α.
  3. Daughter: thorium-234.
Worked example 3 Beta decay of carbon-14

Carbon-14 undergoes beta-minus decay. Write the equation.

  1. AAA unchanged, ZZZ increases by 1.
  2. 614C→ 714N+ −10β^{14}_{6}\text{C} \to \,^{14}_{7}\text{N} + \,^{0}_{-1}\beta614​C→714​N+−10​β.
  3. Daughter: nitrogen-14.

Key idea: check that mass numbers and atomic numbers balance on both sides.

5. Half-life

The half-life t1/2t_{1/2}t1/2​ of a radioactive isotope is the time for half of the nuclei in a sample to decay. It is a constant for each isotope.

Remaining nuclei after time $t$
N=N0(12)t/t1/2N = N_0 \left(\dfrac{1}{2}\right)^{t / t_{1/2}}N=N0​(21​)t/t1/2​

where N0N_0N0​ is the initial number, NNN is the number after time ttt, and t1/2t_{1/2}t1/2​ is the half-life.

Worked example 4 Counting half-lives

Iodine-131 has a half-life of 8 days. A hospital has 240 mg of I-131. How much remains after 24 days?

  1. Number of half-lives: 248=3\dfrac{24}{8} = 3824​=3.
  2. Remaining: 240×(12)3=240×18=30240 \times \left(\dfrac{1}{2}\right)^3 = 240 \times \dfrac{1}{8} = 30240×(21​)3=240×81​=30 mg.
Worked example 5 Carbon dating

A wooden artefact has 14\dfrac{1}{4}41​ of the carbon-14 of a living sample. Estimate its age. (t1/2t_{1/2}t1/2​ for C-14 =5730= 5730=5730 years.)

  1. 14=(12)2\dfrac{1}{4} = \left(\dfrac{1}{2}\right)^241​=(21​)2, so t=2×t1/2=2×5730=11 460t = 2 \times t_{1/2} = 2 \times 5730 = 11\,460t=2×t1/2​=2×5730=11460 years.
  2. The artefact is about 11 460 years old.

Key idea: exponential decay means repeated halving. Each half-life cuts the amount to half of what was there.

Half-life is not "how long it lasts"

After one half-life, 50%50\%50% remains. After two, 25%25\%25%. After ten half-lives, about 0.1%0.1\%0.1% remains — very small but not exactly zero. Strictly, the sample never reaches zero, but after many half-lives it becomes negligible.


Practice: Year 9

Fluency

Atoms and isotopes

    1. List the atomic models in order and name the scientist most associated with each.
    2. Describe Rutherford’s gold-foil experiment and the conclusion he drew.
    3. For 1735Cl^{35}_{17}\text{Cl}1735​Cl, state the number of protons, neutrons, and electrons.
    4. Define isotope. Give one example.
    5. Why do isotopes of the same element have the same chemistry?
    6. Write the symbol for: (a) 6 protons, 7 neutrons; (b) 20 protons, 22 neutrons.
Fluency

Decay equations

    1. Write the alpha decay equation for radium-226 (88226Ra^{226}_{88}\text{Ra}88226​Ra).
    2. Write the beta-minus decay equation for strontium-90 (3890Sr^{90}_{38}\text{Sr}3890​Sr).
    3. Americium-241 decays by alpha emission. Write the equation and name the daughter.
    4. State which radiation (alpha, beta, gamma) is (a) stopped by paper, (b) an electron, (c) a photon.
    5. A nucleus loses 2 alpha and 1 beta particle. How do AAA and ZZZ change overall?
Reasoning

Half-life

    1. A sample starts with 1600 atoms. After 3 half-lives, how many remain?
    2. Technetium-99m has half-life 6 hours. Starting with 80 mg, how much remains after 24 hours?
    3. A sample has dropped to 116\dfrac{1}{16}161​ of its original activity. How many half-lives have passed?
    4. Cobalt-60 has half-life 5.27 years. Starting with 100 g, how much remains after 10.54 years?
    5. A patient is injected with 40 MBq of an isotope with half-life 2 hours. What is the activity after 6 hours?
Problem solving

Applications and reasoning

    1. Why is a long half-life (thousands of years) suitable for radioactive dating but unsuitable for medical imaging?
    2. An archaeologist finds that a bone contains 18\dfrac{1}{8}81​ of the C-14 in a living bone. Estimate the age. (t1/2=5730t_{1/2} = 5730t1/2​=5730 y.)
    3. Explain why gamma radiation is used in cancer radiotherapy but alpha sources are not used externally.
    4. Suggest a reason Bohr’s model, though successful for hydrogen, failed to predict the spectra of larger atoms.

Challenge

Reasoning

Harder reasoning

    1. Rutherford’s team fired alpha particles at a thin gold foil. Most passed straight through, but a tiny fraction bounced back. Using this evidence, argue why the “plum pudding” model had to be replaced.
    2. A decay chain: 92238U^{238}_{92}\text{U}92238​U eventually becomes 82206Pb^{206}_{82}\text{Pb}82206​Pb via multiple alpha and beta decays. If the total change in AAA is −32-32−32 and in ZZZ is −10-10−10, how many alpha and how many beta-minus decays are involved? Show your working.
    3. A patient receives a technetium-99m scan with activity 800 MBq at injection. If the effective half-life in the body is 4 hours, what activity remains after 16 hours? Comment on why Tc-99m is chosen for imaging.
    4. The number NNN of undecayed nuclei follows N=N0(1/2)t/t1/2N = N_0 (1/2)^{t/t_{1/2}}N=N0​(1/2)t/t1/2​. Rearrange to express ttt in terms of NNN, N0N_0N0​, and t1/2t_{1/2}t1/2​, and use this to estimate the age of a rock in which NN0=0.3\dfrac{N}{N_0} = 0.3N0​N​=0.3 for an isotope with half-life 1.3×1091.3 \times 10^91.3×109 years.
Year 9 Science study companion | Practice