Year 9 Mathematics | Victorian Curriculum 2.0
Real numbers and scientific notation
Topic 01 | Number & Algebra | Practice

What you will learn

  • classify numbers as natural, integer, rational, or irrational and explain the hierarchy,
  • represent rational and irrational numbers on the real number line,
  • convert between ordinary notation and scientific notation,
  • perform multiplication and division with numbers in scientific notation,
  • apply scientific notation to real-world contexts involving very large or very small quantities.
Why do we need a 'real number system'?

In earlier years you met whole numbers, then fractions, then negatives, then surds like 2\sqrt{2}2​. Each new type filled a gap on the number line. The real numbers are the complete set — every point on the number line has a real number, and every real number has a point. Understanding this system means you can confidently classify any number you meet and know how it relates to all the others.

Where you'll see this
  • Astronomy: distances between stars are written in scientific notation (e.g. 4.24×10134.24 \times 10^{13}4.24×1013 km to the nearest star).
  • Chemistry: an atom’s diameter is roughly 1×10−101 \times 10^{-10}1×10−10 m — too small for ordinary notation.
  • Computing: floating-point numbers in every programming language use a form of scientific notation internally.
  • Finance: national budgets and GDP figures are often quoted in scientific notation for clarity.
Worked example 0 Real-world example: how far is a light-year?

Light travels at approximately 3×1083 \times 10^83×108 metres per second. A year has about 3.15×1073.15 \times 10^73.15×107 seconds.

  1. Distance = speed ×\times× time = (3×108)×(3.15×107)(3 \times 10^8) \times (3.15 \times 10^7)(3×108)×(3.15×107).
  2. Multiply the decimal parts: 3×3.15=9.453 \times 3.15 = 9.453×3.15=9.45.
  3. Add the exponents: 108×107=101510^8 \times 10^7 = 10^{15}108×107=1015.
  4. Combine: one light-year ≈9.45×1015\approx 9.45 \times 10^{15}≈9.45×1015 m.

Key idea: scientific notation lets us multiply enormous quantities by working with small decimals and adding exponents — no need to write out fifteen zeros.

1. The real number system

Every number you have met so far fits into a hierarchy:

N⊂Z⊂Q⊂R\mathbb{N} \subset \mathbb{Z} \subset \mathbb{Q} \subset \mathbb{R}N⊂Z⊂Q⊂R
  • N\mathbb{N}N — natural numbers: 0,1,2,3,…0, 1, 2, 3, \ldots0,1,2,3,…
  • Z\mathbb{Z}Z — integers: …,−2,−1,0,1,2,…\ldots, -2, -1, 0, 1, 2, \ldots…,−2,−1,0,1,2,…
  • Q\mathbb{Q}Q — rational numbers: any number that can be written as ab\dfrac{a}{b}ba​ with a,b∈Za, b \in \mathbb{Z}a,b∈Z and b≠0b \neq 0b=0. Their decimals either terminate or recur.
  • R\mathbb{R}R — real numbers: all of Q\mathbb{Q}Q together with the irrational numbers (decimals that neither terminate nor recur).
-2-101231/3(rational)√2(irrational)π(irrational)−3/2(rational)
The real number line, showing where rational and irrational numbers sit.
Worked example 1 Classifying numbers

Classify each number as rational or irrational:   711,  36,  π+1,  0.142857‾,  10\;\dfrac{7}{11},\; \sqrt{36},\; \pi + 1,\; 0.\overline{142857},\; \sqrt{10}117​,36​,π+1,0.142857,10​.

  1. 711\dfrac{7}{11}117​ — ratio of integers, so rational.
  2. 36=6\sqrt{36} = 636​=6 — a whole number, so rational.
  3. π+1\pi + 1π+1 — since π\piπ is irrational, adding 111 (rational) still gives an irrational number.
  4. 0.142857‾0.\overline{142857}0.142857 — repeating decimal, so rational (in fact it equals 17\dfrac{1}{7}71​).
  5. 10\sqrt{10}10​ — 101010 is not a perfect square, so 10\sqrt{10}10​ is irrational.
Not every root is irrational

49=7\sqrt{49} = 749​=7 is rational. Only square roots of non-perfect-squares are irrational. Always check whether the number under the root sign is a perfect square first.

2. Scientific notation

Scientific notation writes a number as:

Scientific notation form
a×10n,1≤a<10,n∈Z.a \times 10^n, \qquad 1 \leq a < 10, \quad n \in \mathbb{Z}.a×10n,1≤a<10,n∈Z.

The coefficient aaa has exactly one non-zero digit before the decimal point. The exponent nnn is a positive integer for large numbers and a negative integer for small numbers.

Worked example 2 Converting to scientific notation

Write 47 200 00047\,200\,00047200000 in scientific notation.

  1. Place the decimal after the first non-zero digit: 4.724.724.72.
  2. Count how many places the decimal moved: 777 places to the left.
  3. The exponent is positive because the original number is large: n=7n = 7n=7.

47 200 000=4.72×107.47\,200\,000 = 4.72 \times 10^7.47200000=4.72×107.

Worked example 3 Small numbers in scientific notation

Write 0.000 003 60.000\,003\,60.0000036 in scientific notation.

  1. Place the decimal after the first non-zero digit: 3.63.63.6.
  2. Count how many places the decimal moved: 666 places to the right.
  3. The exponent is negative because the original number is small: n=−6n = -6n=−6.

0.000 003 6=3.6×10−6.0.000\,003\,6 = 3.6 \times 10^{-6}.0.0000036=3.6×10−6.

Worked example 4 Converting from scientific notation to ordinary form

Write 8.05×10−48.05 \times 10^{-4}8.05×10−4 in ordinary notation.

The exponent is −4-4−4, so move the decimal 444 places to the left:

8.05×10−4=0.000 805.8.05 \times 10^{-4} = 0.000\,805.8.05×10−4=0.000805.

3. Operations with scientific notation

When multiplying or dividing numbers in scientific notation, handle the coefficients and powers of ten separately.

Operations in scientific notation

Multiplication
(a×10m)×(b×10n)=(a×b)×10m+n.(a \times 10^m) \times (b \times 10^n) = (a \times b) \times 10^{m+n}.(a×10m)×(b×10n)=(a×b)×10m+n.

Adjust if a×b≥10a \times b \geq 10a×b≥10.

Division
a×10mb×10n=ab×10m−n.\dfrac{a \times 10^m}{b \times 10^n} = \dfrac{a}{b} \times 10^{m-n}.b×10na×10m​=ba​×10m−n.

Adjust if ab<1\dfrac{a}{b} < 1ba​<1.

Worked example 5 Multiplying in scientific notation

Calculate (4.5×106)×(2×103)(4.5 \times 10^6) \times (2 \times 10^3)(4.5×106)×(2×103).

  1. Multiply coefficients: 4.5×2=94.5 \times 2 = 94.5×2=9.
  2. Add exponents: 106×103=10910^6 \times 10^3 = 10^9106×103=109.
  3. Result: 9×1099 \times 10^99×109.

Since 1≤9<101 \leq 9 < 101≤9<10, no adjustment needed.

Worked example 6 Multiplying with adjustment

Calculate (6×104)×(5×107)(6 \times 10^4) \times (5 \times 10^7)(6×104)×(5×107).

  1. Multiply coefficients: 6×5=306 \times 5 = 306×5=30.
  2. Add exponents: 104×107=101110^4 \times 10^7 = 10^{11}104×107=1011.
  3. Preliminary result: 30×101130 \times 10^{11}30×1011.
  4. Adjust: 30=3.0×10130 = 3.0 \times 10^130=3.0×101, so the answer is 3.0×10123.0 \times 10^{12}3.0×1012.
Worked example 7 Dividing in scientific notation

Calculate 8.4×1092.1×103\dfrac{8.4 \times 10^9}{2.1 \times 10^3}2.1×1038.4×109​.

  1. Divide coefficients: 8.4÷2.1=48.4 \div 2.1 = 48.4÷2.1=4.
  2. Subtract exponents: 109−3=10610^{9-3} = 10^6109−3=106.
  3. Result: 4×1064 \times 10^64×106.

Practice

Fluency

Tier 1: basic skills

    1. Classify as rational or irrational: 58\dfrac{5}{8}85​.
    2. Classify: 50\sqrt{50}50​.
    3. Classify: −81-\sqrt{81}−81​.
    4. Classify: 0.36‾0.\overline{36}0.36.
    5. Write 93 000 00093\,000\,00093000000 in scientific notation.
    6. Write 0.000 0720.000\,0720.000072 in scientific notation.
    7. Write 5.03×1055.03 \times 10^55.03×105 in ordinary notation.
    8. Write 1.7×10−31.7 \times 10^{-3}1.7×10−3 in ordinary notation.
    9. Calculate (3×104)×(2×105)(3 \times 10^4) \times (2 \times 10^5)(3×104)×(2×105). Give your answer in scientific notation.
    10. Calculate 9.6×1083.2×102\dfrac{9.6 \times 10^8}{3.2 \times 10^2}3.2×1029.6×108​. Give your answer in scientific notation.
Reasoning

Tier 2: mixed practice

    1. Place 5\sqrt{5}5​, 73\dfrac{7}{3}37​, and π\piπ on a number line. Which is the largest?
    2. Show that 2+2\sqrt{2} + \sqrt{2}2​+2​ is irrational.
    3. The mass of the Earth is approximately 5.97×10245.97 \times 10^{24}5.97×1024 kg and the mass of the Moon is approximately 7.35×10227.35 \times 10^{22}7.35×1022 kg. How many times heavier is the Earth than the Moon? Give your answer to the nearest whole number.
    4. A human hair is about 7×10−57 \times 10^{-5}7×10−5 m wide. Express this in micrometres (1  μm=10−61\;\mu\text{m} = 10^{-6}1μm=10−6 m).
    5. Calculate (7.2×10−3)×(4×105)(7.2 \times 10^{-3}) \times (4 \times 10^5)(7.2×10−3)×(4×105) and give the result in scientific notation.
    6. Explain why the sum of a rational number and an irrational number is always irrational.
    7. Between which two consecutive tenths does 18\sqrt{18}18​ lie? Use squaring to justify.
    8. The distance from the Sun to Neptune is 4.5×10124.5 \times 10^{12}4.5×1012 m. Light travels at 3×1083 \times 10^83×108 m/s. How many seconds does sunlight take to reach Neptune?
Reasoning

Tier 3: explain and apply

    1. Is 2×8\sqrt{2} \times \sqrt{8}2​×8​ rational or irrational? Justify your answer.
    2. A nanotechnology lab measures objects on the scale of 10−910^{-9}10−9 m. Express 4.2×10−74.2 \times 10^{-7}4.2×10−7 m in terms of nanometres.
    3. Find two irrational numbers whose product is rational. Explain why this does not contradict the definition of irrational numbers.
    4. The Australian national debt is approximately $9 \times 10^11.Ifthepopulationis. If the population is .Ifthepopulationis2.6 \times 10^7$, estimate the debt per person. Give your answer in ordinary notation to the nearest dollar.
    5. Explain why 0.9‾=10.\overline{9} = 10.9=1 and what this tells us about the boundary between rational and irrational numbers.

Challenge

Reasoning

Harder reasoning

    1. Prove that if rrr is rational and xxx is irrational, then r+xr + xr+x is irrational. (Hint: assume the opposite and derive a contradiction.)
    2. The observable universe has a radius of approximately 4.4×10264.4 \times 10^{26}4.4×1026 m. Estimate its volume in cubic metres using V=43πr3V = \dfrac{4}{3}\pi r^3V=34​πr3, and express your answer in scientific notation to two significant figures.
    3. Simplify (2.4×105)26×103\dfrac{(2.4 \times 10^5)^2}{6 \times 10^3}6×103(2.4×105)2​ and give the answer in scientific notation.
    4. A computer performs 3.6×10123.6 \times 10^{12}3.6×1012 operations per second. How many operations can it perform in one year (3.15×1073.15 \times 10^73.15×107 seconds)? If each operation processes 8×10−98 \times 10^{-9}8×10−9 seconds of audio, how many hours of audio can the computer process per year?
Year 9 Mathematics study companion | Practice