Year 9 Mathematics | Victorian Curriculum 2.0
Function transformations
Topic 07 | Number & Algebra | Practice

What you will learn

  • describe how the graph of y=x2y = x^2y=x2 changes when a constant is added or subtracted,
  • explain the effect of multiplying by a constant (vertical stretch/compression),
  • recognise a reflection in the xxx-axis from a negative coefficient,
  • identify horizontal translations of the form y=(x−h)2y = (x - h)^2y=(x−h)2,
  • connect algebraic parameters to graphical features (vertex, orientation, width).
Why study transformations?

Every curved graph you meet in science, economics, or engineering is a transformed version of a simpler “parent” function. Learning the four basic moves — translate, stretch, compress, reflect — lets you sketch any parabola (or later, any function) quickly without plotting dozens of points. It also builds the foundation for modelling real situations where quantities rise, fall, or change direction.

Where you'll see this
  • Physics: the trajectory of a ball is a transformed parabola y=−ax2+bx+cy = -ax^2 + bx + cy=−ax2+bx+c.
  • Business: profit curves shift up or down as costs change.
  • Architecture: parabolic arches and cables are positioned by translating and scaling a base parabola.
  • Data science: adjusting model curves to fit data relies on stretching and shifting.
Worked example 0 Real-world example: adjusting a fountain arc

A water fountain follows the path y=−x2+4y = -x^2 + 4y=−x2+4. The designer wants the jet to peak 222 m higher.

  1. The current peak is at y=4y = 4y=4 (when x=0x = 0x=0).
  2. Adding 222 to the whole function gives y=−x2+6y = -x^2 + 6y=−x2+6.
  3. The new peak is at y=6y = 6y=6, exactly 222 m higher.
  4. Every point on the arc has moved up by 222 units — a vertical translation.

Key idea: adding a constant kkk to a function shifts its entire graph up by kkk units.

1. The parent function y=x2y = x^2y=x2

The simplest parabola has its vertex at the origin (0,0)(0, 0)(0,0), opens upward, and is symmetric about the yyy-axis.

Oxyy = x²
The parent parabola y = x squared, with vertex at the origin.

All transformations below modify this parent graph.

2. Vertical translation: y=x2+ky = x^2 + ky=x2+k

Vertical translation
y=x2+ky = x^2 + ky=x2+k
  • k>0k > 0k>0: graph shifts up kkk units.
  • k<0k < 0k<0: graph shifts down ∣k∣|k|∣k∣ units.

The vertex moves from (0,0)(0, 0)(0,0) to (0,k)(0, k)(0,k). Shape and width stay the same.

Worked example 1 Shifting up and down

Sketch y=x2+3y = x^2 + 3y=x2+3 and y=x2−2y = x^2 - 2y=x2−2 relative to y=x2y = x^2y=x2.

  1. y=x2+3y = x^2 + 3y=x2+3: every yyy-value increases by 333. Vertex at (0,3)(0, 3)(0,3).
  2. y=x2−2y = x^2 - 2y=x2−2: every yyy-value decreases by 222. Vertex at (0,−2)(0, -2)(0,−2).
  3. Both parabolas have the same width and open upward.

3. Vertical stretch and compression: y=ax2y = ax^2y=ax2

Vertical stretch / compression
y=ax2y = ax^2y=ax2
  • ∣a∣>1|a| > 1∣a∣>1: graph is narrower (stretched vertically).
  • 0<∣a∣<10 < |a| < 10<∣a∣<1: graph is wider (compressed vertically).
  • a=1a = 1a=1: unchanged parent graph.

The vertex remains at (0,0)(0, 0)(0,0); only the steepness changes.

Worked example 2 Comparing widths

Compare y=3x2y = 3x^2y=3x2 and y=12x2y = \tfrac{1}{2}x^2y=21​x2 with the parent.

  1. At x=2x = 2x=2: parent gives y=4y = 4y=4; y=3x2y = 3x^2y=3x2 gives y=12y = 12y=12 (steeper); y=12x2y = \tfrac{1}{2}x^2y=21​x2 gives y=2y = 2y=2 (flatter).
  2. y=3x2y = 3x^2y=3x2 is a narrower parabola.
  3. y=12x2y = \tfrac{1}{2}x^2y=21​x2 is a wider parabola.
  4. Both still have vertex at (0,0)(0, 0)(0,0) and open upward.

4. Reflection: y=−f(x)y = -f(x)y=−f(x)

Reflection in the x-axis
y=−x2y = -x^2y=−x2

Multiplying the function by −1-1−1 flips every point across the xxx-axis. The parabola now opens downward.

Combining reflection with stretch

y=−2x2y = -2x^2y=−2x2 reflects and stretches. The parabola opens downward and is narrower than y=x2y = x^2y=x2.

Worked example 3 Reflection

Describe the graph of y=−x2+5y = -x^2 + 5y=−x2+5.

  1. Start with y=x2y = x^2y=x2: vertex at (0,0)(0, 0)(0,0), opens upward.
  2. Reflect: y=−x2y = -x^2y=−x2 opens downward, vertex still (0,0)(0, 0)(0,0).
  3. Translate up 555: y=−x2+5y = -x^2 + 5y=−x2+5, vertex at (0,5)(0, 5)(0,5), opens downward.
  4. The graph’s maximum value is y=5y = 5y=5.

5. Horizontal translation: y=(x−h)2y = (x - h)^2y=(x−h)2

Horizontal translation
y=(x−h)2y = (x - h)^2y=(x−h)2
  • h>0h > 0h>0: graph shifts right hhh units.
  • h<0h < 0h<0: graph shifts left ∣h∣|h|∣h∣ units.

The vertex moves from (0,0)(0, 0)(0,0) to (h,0)(h, 0)(h,0).

The sign trap

In y=(x−3)2y = (x - 3)^2y=(x−3)2 the vertex is at x=3x = 3x=3 (positive three, not negative). The subtraction inside the bracket means “shift right”. For a shift left, you write y=(x+2)2=(x−(−2))2y = (x + 2)^2 = (x - (-2))^2y=(x+2)2=(x−(−2))2, so h=−2h = -2h=−2.

Worked example 4 Horizontal shift

State the vertex and sketch y=(x−4)2+1y = (x - 4)^2 + 1y=(x−4)2+1.

  1. Horizontal shift: h=4h = 4h=4, so the vertex moves 444 units right.
  2. Vertical shift: k=1k = 1k=1, so the vertex moves 111 unit up.
  3. Vertex is at (4,1)(4, 1)(4,1). The parabola opens upward with the same width as y=x2y = x^2y=x2.

Summary of transformations

General vertex form
y=a(x−h)2+ky = a(x - h)^2 + ky=a(x−h)2+k
ParameterEffect
a>0a > 0a>0Opens upward
a<0a < 0a<0Opens downward (reflection)
∣a∣>1\lvert a \rvert > 1∣a∣>1Narrower (vertical stretch)
0<∣a∣<10 < \lvert a \rvert < 10<∣a∣<1Wider (vertical compression)
hhhHorizontal shift (vertex at x=hx = hx=h)
kkkVertical shift (vertex at y=ky = ky=k)

Vertex: (h,k)(h, k)(h,k). Axis of symmetry: x=hx = hx=h.

Worked example 5 Identifying all transformations

Describe the transformations that turn y=x2y = x^2y=x2 into y=−2(x+1)2+3y = -2(x + 1)^2 + 3y=−2(x+1)2+3.

  1. Write in standard form: a=−2a = -2a=−2, h=−1h = -1h=−1, k=3k = 3k=3.
  2. ∣a∣=2>1|a| = 2 > 1∣a∣=2>1: vertical stretch (narrower).
  3. a<0a < 0a<0: reflection in the xxx-axis (opens downward).
  4. h=−1h = -1h=−1: shift 111 unit left.
  5. k=3k = 3k=3: shift 333 units up.
  6. Vertex at (−1,3)(-1, 3)(−1,3); the parabola opens downward and is narrower than the parent.

Practice

Fluency

Tier 1: identify the transformation

    1. State the vertex of y=x2+7y = x^2 + 7y=x2+7.
    2. State the vertex of y=x2−4y = x^2 - 4y=x2−4.
    3. Is y=5x2y = 5x^2y=5x2 narrower or wider than y=x2y = x^2y=x2?
    4. Is y=0.3x2y = 0.3x^2y=0.3x2 narrower or wider than y=x2y = x^2y=x2?
    5. Does y=−x2y = -x^2y=−x2 open upward or downward?
    6. State the vertex of y=(x−6)2y = (x - 6)^2y=(x−6)2.
    7. State the vertex of y=(x+2)2−1y = (x + 2)^2 - 1y=(x+2)2−1.
    8. Write the equation of y=x2y = x^2y=x2 shifted 555 units down.
    9. Write the equation of y=x2y = x^2y=x2 shifted 333 units right and 444 units up.
Reasoning

Tier 2: mixed practice

    1. Match each equation to its vertex: (a) y=(x−1)2+2y = (x - 1)^2 + 2y=(x−1)2+2, (b) y=(x+3)2−5y = (x + 3)^2 - 5y=(x+3)2−5, (c) y=−x2+4y = -x^2 + 4y=−x2+4. Vertices: (0,4)(0, 4)(0,4), (1,2)(1, 2)(1,2), (−3,−5)(-3, -5)(−3,−5).
    2. A parabola has vertex (2,−3)(2, -3)(2,−3) and opens upward with the same width as y=x2y = x^2y=x2. Write its equation.
    3. Describe two different transformations that could move the vertex of y=x2y = x^2y=x2 to (0,9)(0, 9)(0,9).
    4. The graph of y=ax2y = ax^2y=ax2 passes through (1,6)(1, 6)(1,6). Find aaa.
    5. Arrange from widest to narrowest: y=4x2y = 4x^2y=4x2, y=x2y = x^2y=x2, y=14x2y = \tfrac{1}{4}x^2y=41​x2, y=2x2y = 2x^2y=2x2.
    6. A parabola opens downward, is narrower than y=x2y = x^2y=x2, and has vertex at (1,5)(1, 5)(1,5). Write a possible equation.
Reasoning

Tier 3: explain and apply

    1. Explain why replacing xxx with (x−h)(x - h)(x−h) shifts the graph to the right rather than the left.
    2. Sam says ”y=−(x−2)2y = -(x - 2)^2y=−(x−2)2 has vertex at (−2,0)(-2, 0)(−2,0).” Identify and correct the error.
    3. A ball’s height is modelled by y=−5(x−1)2+8y = -5(x - 1)^2 + 8y=−5(x−1)2+8, where xxx is time in seconds. State the maximum height and when it occurs.
    4. Two parabolas have equations y=2(x−3)2+1y = 2(x - 3)^2 + 1y=2(x−3)2+1 and y=2(x−3)2−4y = 2(x - 3)^2 - 4y=2(x−3)2−4. How are they related? What is the vertical distance between their vertices?

Challenge

Reasoning

Harder reasoning

    1. Find the equation in vertex form of a parabola that opens downward, passes through (0,0)(0, 0)(0,0) and (4,0)(4, 0)(4,0), and has a maximum value of 888.
    2. The graph of y=a(x−h)2+ky = a(x - h)^2 + ky=a(x−h)2+k passes through (0,5)(0, 5)(0,5) and (6,5)(6, 5)(6,5) and has a minimum value of −4-4−4. Find aaa, hhh, and kkk.
    3. A parabola y=a(x−h)2+ky = a(x - h)^2 + ky=a(x−h)2+k has vertex (3,7)(3, 7)(3,7) and passes through (5,−1)(5, -1)(5,−1). Find the values of aaa, hhh, and kkk, and state whether the parabola opens upward or downward.
    4. Explain why the graph of y=(x−p)(x−q)y = (x - p)(x - q)y=(x−p)(x−q) has its axis of symmetry at x=p+q2x = \dfrac{p + q}{2}x=2p+q​, and find the vertex coordinates in terms of ppp and qqq.
Year 9 Mathematics study companion | Practice