Year 8 Science | Victorian Curriculum 2.0
Household energy & energy audits
Topic 08 | Physical sciences | Practice

What you will learn

  • the units of electrical energy: watts, kilowatts, kilowatt-hours,
  • how to calculate the energy used by an appliance,
  • how to read an electricity bill and estimate the cost of running a device,
  • how energy rating labels compare appliances,
  • how to plan and carry out a simple home energy audit.
Why understand your own energy use?

Electricity bills are not magic. They come from a simple formula: power (kW) times time (hours) times price ($/kWh). Once you can do that calculation, you can predict which appliance costs most to run, spot waste, and make real choices about saving money and reducing emissions. It is one of the most practical pieces of science you can learn.

Where you'll see this
  • Household bills: quarterly electricity and gas bills list kWh used.
  • Shopping: energy rating stickers (stars) on fridges, washers, TVs.
  • Sustainability: solar panel decisions depend on household kWh demand.
  • Climate policy: emissions targets are built on kWh-level data.
Worked example 0 Real-world example: cost of running a heater

A 200020002000 W electric heater is left on for 444 hours each evening during winter (909090 days). Electricity costs $0.30 per kWh. Estimate the total cost for winter.

  1. Convert to kilowatts: 200020002000 W =2= 2=2 kW.
  2. Energy per evening: 2 kW×4 h=82 \text{ kW} \times 4 \text{ h} = 82 kW×4 h=8 kWh.
  3. Energy for winter: 8×90=7208 \times 90 = 7208×90=720 kWh.
  4. Cost: 720×0.30=216720 \times 0.30 = 216720×0.30=216 dollars.

Key idea: one high-power appliance used every day dominates a whole bill. The family could consider a more efficient heater or warmer clothing.

1. Power and energy — watts and kilowatt-hours

  • Power is how fast energy is used. Measured in watts (W) or kilowatts (kW). 111 kW =1000= 1000=1000 W.
  • Energy used is power ×\times× time. Electricity companies measure energy in kilowatt-hours (kWh).

Energy used and cost

Energy (kWh)
E (kWh)=P (kW)×t (h).E \text{ (kWh)} = P \text{ (kW)} \times t \text{ (h)}.E (kWh)=P (kW)×t (h).
Cost
cost=E×price per kWh.\text{cost} = E \times \text{price per kWh}.cost=E×price per kWh.
What is a kWh?

One kilowatt-hour is the energy used by a 111 kW appliance running for 111 hour. A 100100100 W bulb for 101010 hours is also 111 kWh (0.10.10.1 kW ×10\times 10×10 h).

Worked example 1 Energy for a fridge

A fridge has a power rating of 150150150 W and runs 242424 hours a day. Find the daily energy use in kWh.

  1. Convert to kW: 150150150 W =0.15= 0.15=0.15 kW.
  2. Energy: E=0.15×24=3.6E = 0.15 \times 24 = 3.6E=0.15×24=3.6 kWh.
  3. If electricity costs $0.30/kWh, daily cost =3.6×0.30=1.08= 3.6 \times 0.30 = 1.08=3.6×0.30=1.08 dollars.
Worked example 2 Cost of a kettle boil

A 2.42.42.4 kW kettle boils for 333 minutes. At $0.30/kWh, find the cost of one boil.

  1. Time in hours: 333 min =0.05= 0.05=0.05 h.
  2. Energy: E=2.4×0.05=0.12E = 2.4 \times 0.05 = 0.12E=2.4×0.05=0.12 kWh.
  3. Cost: 0.12×0.30=0.0360.12 \times 0.30 = 0.0360.12×0.30=0.036 dollars ≈3.6\approx 3.6≈3.6 cents.

2. Reading an electricity bill

A typical bill contains:

  • Meter reading start / end — the kWh counter at the start and end of the billing period.
  • Usage (kWh) — the difference, i.e. what was actually used.
  • Tariff — price per kWh (sometimes different for peak / off-peak / shoulder).
  • Supply charge — a fixed daily cost for being connected.
  • Total cost — usage charge + supply charge + GST.
Worked example 3 Simple bill calculation

A household reads 24 51024\,51024510 kWh at the start of the quarter and 25 36025\,36025360 kWh at the end. Tariff is $0.28/kWh; the daily supply charge is $1.20 for 909090 days.

  1. Usage =25 360−24 510=850= 25\,360 - 24\,510 = 850=25360−24510=850 kWh.
  2. Usage cost =850×0.28=238= 850 \times 0.28 = 238=850×0.28=238 dollars.
  3. Supply charge =90×1.20=108= 90 \times 1.20 = 108=90×1.20=108 dollars.
  4. Subtotal =238+108=346= 238 + 108 = 346=238+108=346 dollars.
  5. Adding 10%10\%10% GST: 346×1.10=380.60346 \times 1.10 = 380.60346×1.10=380.60 dollars.

3. Energy rating labels

Australian appliances carry a star rating (1 to 10 stars) comparing their efficiency to similar models. More stars = less electricity for the same job.

The label also prints an annual energy use (kWh/year) number. This is what you multiply by the tariff to estimate the running cost.

Worked example 4 Comparing fridges

Fridge A is rated 320320320 kWh/year, fridge B is rated 480480480 kWh/year. At $0.30/kWh, how much more does fridge B cost to run over 10 years?

  1. Annual difference: 480−320=160480 - 320 = 160480−320=160 kWh.
  2. Annual cost difference: 160×0.30=48160 \times 0.30 = 48160×0.30=48 dollars.
  3. Over 101010 years: 48×10=48048 \times 10 = 48048×10=480 dollars.

Key idea: a fridge lives in your home for a decade. A cheaper “label price” can easily be wiped out by higher running cost.

4. Building design, season and climate

How much energy a home uses depends on more than the appliances plugged in:

  • Insulation — roof, wall and floor insulation cut heating and cooling losses.
  • Orientation — north-facing windows (in Australia) let in winter sun for free heat.
  • Shading — eaves and trees block summer sun.
  • Windows — double glazing dramatically reduces heat loss.
  • Climate — a house in Darwin (tropical) uses more for cooling; one in Hobart more for heating.
  • Season — heating and cooling dominate winter/summer, while lighting and appliances are roughly constant.

5. The energy audit

An energy audit is a systematic check of where energy is being used and where it is wasted. Simple steps for a classroom or household audit:

  1. List major appliances. For each, note the power rating (often on a sticker).
  2. Estimate daily use (hours/day).
  3. Calculate daily and annual kWh (P×t×365P \times t \times 365P×t×365).
  4. Rank the biggest users.
  5. Look for waste: standby power, lights left on, old appliances, draughts.
  6. Recommend actions: swap incandescents for LEDs, turn off at the wall, add insulation, replace an old inefficient appliance.
Worked example 5 A quick audit

A family lists: hot water (250025002500 kWh/yr), fridge (400400400 kWh/yr), TV (200200200 kWh/yr), lighting (300300300 kWh/yr), computer (150150150 kWh/yr). Identify the biggest user and suggest one action.

  1. Hot water is by far the biggest at 250025002500 kWh/yr (∼70%\sim 70\%∼70% of this list).
  2. Switching to a heat-pump or solar hot-water system could cut this by 606060-80%80\%80%, saving far more than LED bulbs would.

Key idea: tackle the biggest user first. Small gains on small users rarely beat a modest gain on the biggest one.


Practice: Year 8

Fluency

Watts, kW and kWh

    1. Convert: (a) 800800800 W to kW, (b) 2.42.42.4 kW to W, (c) 150015001500 W to kW.
    2. A 100100100 W bulb runs for 101010 hours. Energy used in kWh?
    3. A 222 kW heater runs for 333 hours. Energy used in kWh?
    4. A 505050 W fan runs for 888 hours. Energy used in kWh?
    5. At $0.30/kWh, find the cost of running a 1.51.51.5 kW appliance for 222 hours.
Fluency

Reading a bill

    1. A meter starts at 10 23410\,23410234 kWh and reads 10 85910\,85910859 kWh at the end of the quarter. Find the usage.
    2. A household used 720720720 kWh at $0.28/kWh. What is the usage cost?
    3. A daily supply charge is $1.10 for 919191 days. What is the total supply charge?
    4. Add 10%10\%10% GST to a subtotal of $440.
    5. Give three things an electricity bill typically shows.
Fluency

Efficiency labels

    1. Appliance A uses 400400400 kWh/yr, appliance B uses 500500500 kWh/yr. At $0.30/kWh, what is the annual running cost of each?
    2. A fridge has 4 stars and another has 2 stars. Which costs less to run?
    3. Why are “kWh per year” labels more useful than just “watts”?
    4. A 10-year old fridge uses 600600600 kWh/yr, a new one 300300300 kWh/yr. How much is saved over 5 years at $0.30/kWh?
Reasoning

Audit thinking

    1. A family wants to reduce their bill. Should they replace their 606060 W LEDs or their 200020002000 W electric heater? Explain.
    2. Why might standby power (TV, microwave clocks) still matter?
    3. Insulating a roof is expensive. How could you decide whether it is worth it?
    4. Explain why hot-water heating is often the biggest single part of a household’s energy bill.
Problem solving

Applied contexts

    1. A 200200200 W computer is left on overnight (121212 hours) 200200200 nights a year. At $0.30/kWh, find the annual cost.
    2. A family runs a 350035003500 W air conditioner 555 hours a day for 606060 summer days. At $0.30/kWh, estimate the cost.
    3. A household is considering a rooftop solar system that generates 500050005000 kWh/yr. If their bill is $0.30/kWh, how much money would they avoid spending in the first year?
    4. A home uses 180018001800 kWh in winter and 900900900 kWh in summer. Suggest why the winter figure is higher and predict two effective actions.

Challenge

Reasoning

Harder reasoning

    1. A household has a 300300300 L electric storage hot-water system rated at 3.63.63.6 kW. It runs for about 333 hours a day. Find the annual cost at $0.30/kWh, and suggest a lower-cost alternative with reasoning.
    2. Two houses in the same street have identical appliances. House A pays $600 less per year for electricity. List three design or behaviour factors that could explain the difference.
    3. A family installs LED lighting (saving 400400400 kWh/yr) and a solar hot-water system (saving 180018001800 kWh/yr) at a combined cost of $6000. Electricity is $0.30/kWh. Find the payback time in years.
    4. Explain how a simple energy audit can lead to reductions in both household bills and Australia’s overall CO2_22​ emissions.
Year 8 Science study companion | Practice