Year 8 Science | Victorian Curriculum 2.0
Electrical circuits - voltage & current
Topic 09 | Physical sciences | Practice

What you will learn

  • what electric current and voltage mean, and their units,
  • how to read and draw simple circuit diagrams with standard symbols,
  • the difference between series and parallel circuits,
  • how voltmeters and ammeters are connected in a circuit,
  • how to use Ohm’s law, V=IRV = IRV=IR, for simple calculations.
Why do circuits matter?

Almost every machine you rely on — phones, lights, fridges, cars — runs on electrical circuits. A circuit is simply a closed path through which charged particles can flow, carrying energy from a source (battery or power station) to components that use it. Understanding just two quantities, voltage and current, lets you reason about any circuit at Year 8 level.

Where you'll see this
  • Home wiring: every power point is part of a parallel circuit.
  • Phones and laptops: batteries provide a fixed voltage; components draw different currents.
  • Christmas lights: old-style strings were in series (one breaks, all go out); modern ones are in parallel.
  • Cars: 12 V circuits run everything from headlights to the radio.
Worked example 0 Real-world example: a torch

A torch has a 333 V battery and a small bulb. When the switch is closed, the bulb lights. Explain what is happening in terms of voltage and current.

  1. The battery provides 333 V of “push” (voltage) between its terminals.
  2. Closing the switch completes a closed loop.
  3. Charged particles (electrons) flow around the loop — this is the current.
  4. As the current passes through the bulb, electrical energy is transformed into light and heat.

Key idea: a circuit needs a closed loop, a voltage source, and something to carry the current.

1. Current and voltage

Current (III) is the flow of charge through a wire. Unit: ampere (A). Measured with an ammeter.

  • 111 A === a lot of electrons passing a point every second.

Voltage (VVV) is the electrical “push” that drives current. Unit: volt (V). Measured with a voltmeter.

  • A 999 V battery provides more push than a 1.51.51.5 V battery.

Resistance (RRR) is how much a component opposes current flow. Unit: ohm (Ω\OmegaΩ).

  • A thin wire or a bulb filament has high resistance; a thick copper wire has low resistance.

Ohm's law

Three forms of V = IR
V=IR,I=VR,R=VI.V = IR, \qquad I = \dfrac{V}{R}, \qquad R = \dfrac{V}{I}.V=IR,I=RV​,R=IV​.
Units

Voltage in volts (V), current in amperes (A), resistance in ohms (Ω\OmegaΩ).

Worked example 1 Applying Ohm's law

A 121212 V battery drives current through a resistor of 444 Ω\OmegaΩ. Find the current.

I=VR=124=3 A.I = \dfrac{V}{R} = \dfrac{12}{4} = 3 \text{ A}.I=RV​=412​=3 A.
Worked example 2 Finding resistance

A bulb runs at 666 V and draws 0.50.50.5 A. Find its resistance.

R=VI=60.5=12 Ω.R = \dfrac{V}{I} = \dfrac{6}{0.5} = 12 \text{ }\Omega.R=IV​=0.56​=12 Ω.

2. Circuit diagrams and symbols

Real circuits are drawn as tidy diagrams using standard symbols.

Common circuit symbolscellbatterybulbresistorswitchAammeterVvoltmeterSimple cell-bulb circuit
Common circuit symbols: cell, battery, bulb, resistor, switch, ammeter (A) in series, voltmeter (V) in parallel.

A cell provides one voltage (e.g. 1.5 V). A battery is two or more cells joined together (e.g. a “9 V” battery has six 1.5 V cells in series).

3. Measuring: ammeters and voltmeters

  • An ammeter measures current. It is connected in series — the current flows through it. It should have very low resistance so it does not disturb the circuit.
  • A voltmeter measures voltage across a component. It is connected in parallel — placed across the component, not inside the loop. It should have very high resistance so almost no current goes through it.
Never connect an ammeter in parallel with the battery

An ammeter has near-zero resistance. Placing one straight across a battery creates a short circuit — huge current, dangerous heat, possibly a fire. Always in series, never directly across a power source.

4. Series vs parallel circuits

Series — components are connected end-to-end on the same loop.

  • Current is the same at every point: I1=I2=I3I_1 = I_2 = I_3I1​=I2​=I3​.
  • Voltage is shared among components: Vtotal=V1+V2+V3V_{\text{total}} = V_1 + V_2 + V_3Vtotal​=V1​+V2​+V3​.
  • If one breaks, the whole circuit is broken (like old Christmas lights).

Parallel — components sit on separate branches.

  • Voltage is the same across every branch: V1=V2=VtotalV_1 = V_2 = V_{\text{total}}V1​=V2​=Vtotal​.
  • Current splits between branches: Itotal=I1+I2+I3I_{\text{total}} = I_1 + I_2 + I_3Itotal​=I1​+I2​+I3​.
  • If one branch breaks, the others keep working (like house wiring).
Worked example 3 Series voltage sharing

Two identical bulbs are in series with a 666 V battery. What voltage is across each bulb?

  1. Total voltage is shared equally between identical bulbs.
  2. V1+V2=6V_1 + V_2 = 6V1​+V2​=6 V, so each gets 333 V.

Each bulb will therefore glow less brightly than it would alone on 666 V.

Worked example 4 Parallel current splitting

A 121212 V battery drives two parallel bulbs. Each bulb has resistance 666 Ω\OmegaΩ. Find the current through each branch and the total current from the battery.

  1. In parallel, each branch has the full 121212 V.
  2. Each branch current: I=V/R=12/6=2I = V/R = 12/6 = 2I=V/R=12/6=2 A.
  3. Total current: 2+2=42 + 2 = 42+2=4 A.

Key idea: in parallel, adding another bulb does not reduce the others — each one still sees the full voltage.

5. What components do

  • Bulbs convert electrical energy into light and heat.
  • Resistors convert electrical energy into heat; they limit current.
  • Switches open or close a circuit.
  • Motors convert electrical energy into movement.
  • Buzzers / speakers convert electrical energy into sound.

Designing a useful circuit means choosing the right components and arrangement for the job.


Practice: Year 8

Fluency

Definitions and units

    1. Give the units for (a) current, (b) voltage, (c) resistance.
    2. Name the instrument used to measure (a) current, (b) voltage.
    3. How is an ammeter connected? How is a voltmeter connected?
    4. What is the difference between a “cell” and a “battery”?
    5. Name two useful components that transform electrical energy.
Fluency

Ohm's law

    1. Find III when V=12V = 12V=12 V and R=3R = 3R=3 Ω\OmegaΩ.
    2. Find VVV when I=0.5I = 0.5I=0.5 A and R=20R = 20R=20 Ω\OmegaΩ.
    3. Find RRR when V=9V = 9V=9 V and I=0.3I = 0.3I=0.3 A.
    4. A 240240240 V kettle draws 101010 A. Find its resistance.
    5. A 1.51.51.5 V AA cell drives 0.10.10.1 A through a small bulb. Find the bulb’s resistance.
Fluency

Series and parallel

    1. Three identical bulbs share a 999 V battery in series. What voltage is across each?
    2. In a parallel circuit with a 121212 V battery, what voltage is across each branch?
    3. If one bulb in a series string fails (breaks the circuit), what happens to the rest?
    4. If one bulb in a parallel circuit fails, what happens to the others?
    5. Why is house wiring in parallel rather than series?
Reasoning

Explain

    1. Explain why a voltmeter has very high resistance.
    2. Explain why you should not use an ammeter in parallel with a battery.
    3. Explain why two bulbs in series are dimmer than the same bulbs in parallel (on the same battery).
    4. Draw (describe) a simple circuit diagram with a cell, switch, bulb, and ammeter.
Problem solving

Applied contexts

    1. A phone charger outputs 555 V. The phone takes 222 A while charging. What resistance does this correspond to?
    2. A lamp rated 240240240 V draws 0.250.250.25 A. Find its resistance. At this voltage, how much power is it using (use P=VIP = VIP=VI)?
    3. Two bulbs, each 444 Ω\OmegaΩ, are in parallel with a 121212 V battery. Find (a) current through each, (b) total current.
    4. Explain why a 999 V smoke alarm still works when one bulb on a series of Christmas lights elsewhere in the house fails.

Challenge

Reasoning

Harder reasoning

    1. Three resistors (222 Ω\OmegaΩ, 333 Ω\OmegaΩ, 444 Ω\OmegaΩ) are connected in series across a 999 V battery. Find (a) total resistance, (b) current through the circuit, (c) voltage across the 444 Ω\OmegaΩ resistor.
    2. A car headlight runs at 121212 V and 555 A. Find its resistance. If both headlights are on simultaneously (in parallel), find the total current supplied by the battery.
    3. Explain why a short circuit (a wire accidentally connecting the two terminals of a battery) can cause a fire, using Ohm’s law.
    4. Design a circuit that lets one switch turn on two bulbs independently of a third bulb. Describe your arrangement in words (or sketch mentally) and explain why it behaves as required.
Year 8 Science study companion | Practice