Year 8 Mathematics | Victorian Curriculum 2.0
Four operations with rationals
Topic 04 | Number & Algebra | Practice

Start here: the only new thing is the sign

You already know 3×4=123 \times 4 = 123×4=12. The Year 8 question is: what about (−3)×4(-3) \times 4(−3)×4, or (−3)×(−4)(-3) \times (-4)(−3)×(−4)?

The numbers are the same — you always multiply 333 by 444 and get 121212. The only new skill is deciding whether the answer is positive or negative. That’s it.

Try mentally first

One short rule: even number of negatives, positive answer; odd number of negatives, negative answer. You can ignore the signs while multiplying, count the minuses at the end, and decide.

What you will learn

  • multiply and divide integers using the sign rules,
  • extend the four operations to negative fractions and decimals,
  • apply the order of operations (BIDMAS) with signed rational numbers,
  • estimate and check the reasonableness of results.

1. Multiplying and dividing integers

In Year 7 you compared, ordered, added and subtracted integers. In Year 8, multiplication and division of integers become part of the core toolkit.

Worked example E Very easy: just two factors

Work out (−3)×4(-3) \times 4(−3)×4.

  • Multiply the numbers: 3×4=123 \times 4 = 123×4=12.
  • Count negatives: one. Odd, so the answer is negative.
  • Answer: −12-12−12.

Try another: (−3)×(−4)(-3) \times (-4)(−3)×(−4).

  • Multiply the numbers: 3×4=123 \times 4 = 123×4=12.
  • Count negatives: two. Even, so the answer is positive.
  • Answer: +12+12+12.

Sign rules for × and ÷

Same signs give positive
(+)×(+)=+,(−)×(−)=+.(+)\times(+) = +, \qquad (-)\times(-) = +.(+)×(+)=+,(−)×(−)=+.
Different signs give negative
(+)×(−)=−,(−)×(+)=−.(+)\times(-) = -, \qquad (-)\times(+) = -.(+)×(−)=−,(−)×(+)=−.
Division follows the same pattern
++=+,−−=+,+−=−,−+=−.\frac{+}{+} = +, \quad \frac{-}{-} = +, \quad \frac{+}{-} = -, \quad \frac{-}{+} = -.++​=+,−−​=+,−+​=−,+−​=−.
Count the negatives

An even number of negative factors gives a positive product; an odd number gives a negative product.

Negative times negative is positive

(−3)×(−2)=+6(-3) \times (-2) = +6(−3)×(−2)=+6, not −6-6−6. Think of it as reversing a reversal — you end up back where you started.

Worked example 1 A mixed product

Evaluate   (−3)×4×(−2)×(−5)\;(-3) \times 4 \times (-2) \times (-5)(−3)×4×(−2)×(−5).

  1. Multiply magnitudes: 3×4×2×5=1203 \times 4 \times 2 \times 5 = 1203×4×2×5=120.
  2. Count negatives: three. Odd, so the answer is negative.
(−3)×4×(−2)×(−5)=−120.(-3) \times 4 \times (-2) \times (-5) = -120.(−3)×4×(−2)×(−5)=−120.

2. Operations with negative rationals

The same sign rules apply to fractions and decimals.

Try this first

Before reading on, try these in your head: (−1)×12(-1) \times \tfrac{1}{2}(−1)×21​, and   12+14\;\tfrac{1}{2} + \tfrac{1}{4}21​+41​. If both feel easy, skip Example E2.

Worked example E2 Very easy: a simple fraction sum

Evaluate   12+14\;\dfrac{1}{2} + \dfrac{1}{4}21​+41​.

  • Common denominator is 444: rewrite as 24+14=34\dfrac{2}{4} + \dfrac{1}{4} = \dfrac{3}{4}42​+41​=43​.
Worked example 2 Negative fraction times fraction

Evaluate   (−34)×29\;\left(-\dfrac{3}{4}\right) \times \dfrac{2}{9}(−43​)×92​.

  1. Magnitudes: 34×29=636=16\dfrac{3}{4} \times \dfrac{2}{9} = \dfrac{6}{36} = \dfrac{1}{6}43​×92​=366​=61​.
  2. Sign: one negative factor; answer is negative.
(−34)×29=−16.\left(-\dfrac{3}{4}\right) \times \dfrac{2}{9} = -\dfrac{1}{6}.(−43​)×92​=−61​.
Dividing fractions: flip the right one

When dividing fractions, flip the second fraction (the divisor), not the first.   ab÷cd=ab×dc\;\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c}ba​÷dc​=ba​×cd​.

Worked example 3 Dividing with a negative

Evaluate   −38÷94\;-\dfrac{3}{8} \div \dfrac{9}{4}−83​÷49​.

  1. Keep, change, flip: −38×49-\dfrac{3}{8} \times \dfrac{4}{9}−83​×94​.
  2. Magnitudes: 1272=16\dfrac{12}{72} = \dfrac{1}{6}7212​=61​.
  3. Sign: one negative; answer is negative.
−38÷94=−16.-\dfrac{3}{8} \div \dfrac{9}{4} = -\dfrac{1}{6}.−83​÷49​=−61​.
Worked example 4 Signed decimals

Evaluate   −2.4×0.5\;-2.4 \times 0.5−2.4×0.5.

−2.4×0.5=−1.2.-2.4 \times 0.5 = -1.2.−2.4×0.5=−1.2.

(One negative ⇒\Rightarrow⇒ negative; magnitudes 2.4×0.5=1.22.4 \times 0.5 = 1.22.4×0.5=1.2.)

3. Order of operations with signed rationals

BIDMAS still applies: Brackets, Indices, Division & Multiplication (left to right), Addition & Subtraction (left to right).

Try this first

Evaluate   4+3×(−2)\;4 + 3 \times (-2)4+3×(−2) in your head. If you got −2-2−2, you are ready. If you got −14-14−14, revisit BIDMAS before continuing.

Order of operations: powers before multiplication

Powers (indices) are evaluated before multiplication, and multiplication before addition. Always work through BIDMAS step by step: −2+3×42=−2+3×16=−2+48=46-2 + 3 \times 4^2 = -2 + 3 \times 16 = -2 + 48 = 46−2+3×42=−2+3×16=−2+48=46, not −2+122-2 + 12^2−2+122.

Worked example 5 Mixed operations

Evaluate   −12+34×(−2)2\;-\dfrac{1}{2} + \dfrac{3}{4} \times (-2)^2−21​+43​×(−2)2.

  1. Indices: (−2)2=4(-2)^2 = 4(−2)2=4.
  2. Multiplication: 34×4=3\dfrac{3}{4} \times 4 = 343​×4=3.
  3. Addition: −12+3=52-\dfrac{1}{2} + 3 = \dfrac{5}{2}−21​+3=25​.
The power trap again

(−5)2=25(-5)^2 = 25(−5)2=25, but −52=−25-5^2 = -25−52=−25. The brackets decide whether the minus sign is squared.

Common mistake: dividing a negative by a negative

A negative divided by a negative is positive, just like multiplication. −20÷−4=+5-20 \div -4 = +5−20÷−4=+5, not −5-5−5. Read it aloud as “minus twenty, divided by minus four” and count the negatives (two = even = positive).


Practice: Year 8 core

Fluency

Integer × and ÷

    1. Evaluate (−1)×5(-1) \times 5(−1)×5.
    2. Evaluate (−2)×(−3)(-2) \times (-3)(−2)×(−3).
    3. Evaluate (−6)×7(-6) \times 7(−6)×7.
    4. Evaluate (−8)×(−5)(-8) \times (-5)(−8)×(−5).
    5. Evaluate 9×(−4)9 \times (-4)9×(−4).
    6. Evaluate (−3)3(-3)^3(−3)3.
    7. Evaluate (−2)4(-2)^4(−2)4.
    8. Evaluate (−42)÷6(-42) \div 6(−42)÷6.
    9. Evaluate (−72)÷(−8)(-72) \div (-8)(−72)÷(−8).
    10. Evaluate (−2)×(−3)×(−4)(-2) \times (-3) \times (-4)(−2)×(−3)×(−4).
    11. Evaluate (−1)100(-1)^{100}(−1)100.
    12. Evaluate (−100)÷(−25)(-100) \div (-25)(−100)÷(−25).
Fluency

Negative fractions and decimals

    1. Evaluate −12+13-\dfrac{1}{2} + \dfrac{1}{3}−21​+31​.
    2. Evaluate −25−310-\dfrac{2}{5} - \dfrac{3}{10}−52​−103​.
    3. Evaluate −49×38-\dfrac{4}{9} \times \dfrac{3}{8}−94​×83​.
    4. Evaluate −56÷(−109)-\dfrac{5}{6} \div \left(-\dfrac{10}{9}\right)−65​÷(−910​).
    5. Evaluate −0.25×8-0.25 \times 8−0.25×8.
    6. Evaluate −1.6+0.4-1.6 + 0.4−1.6+0.4.
    7. Evaluate −3.2÷(−0.8)-3.2 \div (-0.8)−3.2÷(−0.8).
    8. Evaluate (−0.5)2(-0.5)^2(−0.5)2.
Reasoning

Order of operations

    1. Evaluate −3+2×(−4)-3 + 2 \times (-4)−3+2×(−4).
    2. Evaluate (−6)2−10(-6)^2 - 10(−6)2−10.
    3. Evaluate −14×8+5-\dfrac{1}{4} \times 8 + 5−41​×8+5.
    4. Evaluate −12+4−2\dfrac{-12 + 4}{-2}−2−12+4​.
    5. Evaluate −2×(3−7)2-2 \times (3 - 7)^2−2×(3−7)2.
    6. Evaluate −34−12×(−4)-\dfrac{3}{4} - \dfrac{1}{2} \times (-4)−43​−21​×(−4).
Reasoning

Explain and spot the mistake

    1. Sam says −32=9-3^2 = 9−32=9. Explain what is wrong and give the correct value.
    2. Without calculating, decide whether (−17)×(−19)×(−2)(-17) \times (-19) \times (-2)(−17)×(−19)×(−2) is positive or negative. Explain.
    3. Explain in plain words why dividing a negative by a negative gives a positive.
    4. Lee writes −6+2−2=−4−2=2\dfrac{-6 + 2}{-2} = \dfrac{-4}{-2} = 2−2−6+2​=−2−4​=2. Verify whether this is right.
Problem solving

Applications

    1. A hot-air balloon rises at 2.52.52.5 m/s for 202020 seconds, then descends at 1.81.81.8 m/s for 303030 seconds. What is its net change in altitude?
    2. Temperatures in a week were −4,−1,3,5,2,−2,−3-4, -1, 3, 5, 2, -2, -3−4,−1,3,5,2,−2,−3 (°C). Find the mean temperature.
    3. A share price drops 4%4\%4% one day and then rises 4%4\%4% the next. Is it back to the original price? Justify with a specific starting value.
    4. A student’s score on four tests are −3,+5,+2,−4-3, +5, +2, -4−3,+5,+2,−4 (changes from the class average). What is the student’s total deviation from the average?

Challenge

Reasoning

Harder reasoning

    1. Evaluate (−2)3×(−3)2(−6)\dfrac{(-2)^3 \times (-3)^2}{(-6)}(−6)(−2)3×(−3)2​.
    2. Solve for xxx: −23x=8-\dfrac{2}{3} x = 8−32​x=8.
    3. A number nnn satisfies (−n)3=−27(-n)^3 = -27(−n)3=−27. Find nnn.
    4. Simplify −35(109−23)-\dfrac{3}{5} \left( \dfrac{10}{9} - \dfrac{2}{3} \right)−53​(910​−32​).
Year 8 Mathematics study companion | Practice