Year 8 Mathematics | Victorian Curriculum 2.0
Rates
Topic 12 | Measurement & Space | Practice

What you will learn

  • distinguish a ratio (same unit) from a rate (different units),
  • write a rate as a unit rate (e.g. km per hour),
  • use the speed-distance-time triangle,
  • compare prices, fuel consumption, exchange rates, and pay rates,
  • solve multi-step problems that combine rates and percentages.
Why do rates need their own concept?

A ratio compares two quantities of the same kind (3 cups flour to 2 cups sugar). A rate compares quantities of different kinds — kilometres and hours, dollars and kilograms. The division creates a new “per” quantity (km/h, $/kg) that tells you how one thing changes for each unit of the other. Rates are how we measure speed, price efficiency, flow, productivity — anything where two different units interact.

Where you'll see this
  • Driving: speed in km/h and fuel use in L/100 km are rates.
  • Shopping: unit pricing ($/100 g) lets you compare different package sizes.
  • Travel money: exchange rates convert one currency into another.
  • Work & pay: hourly wage times hours worked gives total pay.
Worked example 0 Real-world example: road trip fuel cost

Your family is driving Melbourne to Adelaide (730730730 km). The car uses 7.27.27.2 L per 100100100 km and petrol costs $1.85/L. What will the fuel cost?

  1. Fuel needed: 730100×7.2=7.3×7.2=52.56\dfrac{730}{100} \times 7.2 = 7.3 \times 7.2 = 52.56100730​×7.2=7.3×7.2=52.56 L.
  2. Cost: 52.56×1.85=97.2452.56 \times 1.85 = 97.2452.56×1.85=97.24 dollars.
  3. Budget about $100 for fuel each way.

Key idea: two rates interact here — fuel consumption (L/100 km) and fuel price ($/L). Multiplying them in the right order gives dollars per distance.

1. Rate vs ratio

A ratio compares two quantities of the same kind (both times, both amounts of money, both lengths).

A rate compares two quantities of different kinds and keeps the units: km/h, $/kg, L/min.

Unit rate
unit rate=amount of Aamount of B, per 1 unit.\text{unit rate} = \dfrac{\text{amount of A}}{\text{amount of B, per 1 unit}}.unit rate=amount of B, per 1 unitamount of A​.
Worked example 1 Speed as a unit rate

A car covers 240240240 km in 333 hours. Its average speed is

240 km3 h=80 km/h.\dfrac{240 \text{ km}}{3 \text{ h}} = 80 \text{ km/h}.3 h240 km​=80 km/h.

2. Speed, distance, time

Speed-distance-time

Three forms
speed=distancetime,distance=speed×time,time=distancespeed.\text{speed} = \dfrac{\text{distance}}{\text{time}}, \quad \text{distance} = \text{speed} \times \text{time}, \quad \text{time} = \dfrac{\text{distance}}{\text{speed}}.speed=timedistance​,distance=speed×time,time=speeddistance​.
Units must match

If speed is in km/h, time must be in hours and distance in km. Convert first if the units do not match.

Worked example 2 Distance from speed and time

A cyclist rides at 181818 km/h for 222 h 303030 min. How far?

  1. Time in hours: 2.52.52.5.
  2. Distance: 18×2.5=4518 \times 2.5 = 4518×2.5=45 km.
Worked example 3 Time from speed and distance

A train travels 350350350 km at 808080 km/h. How long does it take?

t=35080=4.375 h=4 h 22 min 30 s.t = \dfrac{350}{80} = 4.375 \text{ h} = 4 \text{ h } 22 \text{ min } 30 \text{ s}.t=80350​=4.375 h=4 h 22 min 30 s.

3. Other common rates

  • Density: massvolume\dfrac{\text{mass}}{\text{volume}}volumemass​ (g/cm3^33 or kg/m3^33).
  • Pay rate: $/hour.
  • Fuel consumption: L/100 km.
  • Exchange rate: units of currency A per 1 unit of currency B.
  • Interest rate (simple): $ per $100 per year, i.e. a percentage.
Worked example 4 Fuel consumption

A car uses 777 L per 100100100 km. On a 450450450 km trip, how much fuel is used?

7100×450=31.5 L.\dfrac{7}{100} \times 450 = 31.5 \text{ L}.1007​×450=31.5 L.
Worked example 5 Currency conversion

The exchange rate is 111 AUD = 0.650.650.65 USD. Convert $240 AUD to USD, then $600 USD back to AUD.

  • AUD → USD: 240×0.65=156240 \times 0.65 = 156240×0.65=156 USD.
  • USD → AUD: 6000.65≈923.08\dfrac{600}{0.65} \approx 923.080.65600​≈923.08 AUD.

Practice: Year 8 core

Fluency

Unit rates

    1. A car goes 240240240 km in 444 h. Find the average speed.
    2. A tap fills a tank at 600600600 L in 202020 min. Find the rate in L/min.
    3. A worker earns $540 for 202020 hours. Find the hourly rate.
    4. A mass of 180180180 g has volume 202020 cm3^33. Find the density.
    5. A printer prints 606060 pages in 444 minutes. Find pages per minute.
Fluency

Speed, distance, time

    1. Distance from 656565 km/h × 333 h.
    2. Time to cover 300300300 km at 505050 km/h.
    3. Speed of 200200200 m in 252525 seconds (in m/s).
    4. Convert 727272 km/h to m/s.
    5. How long to cover 120120120 km at 808080 km/h?
    6. A train covers 400400400 km in 222 h 303030 min. Find its speed.
Fluency

Fuel, pay, exchange

    1. A car uses 888 L/100100100 km. Fuel for 350350350 km?
    2. A worker earns $22/h. Find pay for 36.536.536.5 hours.
    3. Exchange rate 111 AUD =0.85= 0.85=0.85 NZD. Convert $150 AUD to NZD.
    4. 111 USD =1.50= 1.50=1.50 AUD. Convert $200 USD to AUD.
    5. Simple interest: $1000 at 4%4\%4% for 333 years. How much interest?
Reasoning

Explain and spot the mistake

    1. Sam writes “the speed is 505050 km in 111 hour, so 505050 per hour, so 505050 km”. What units are missing? What is the correct way to report speed?
    2. Two cars: A does 606060 km in 111 hour; B does 303030 km in 303030 minutes. Are they the same speed? Show working.
    3. Explain why a “rate” and a “unit rate” are slightly different ideas. Give an example of each.
    4. Without calculating, compare: a pool fills at 101010 L/min for 202020 min, or at 444 L/min for 606060 min - which delivers more water?
Problem solving

Real contexts

    1. A road trip is 160016001600 km. If the driver averages 100100100 km/h (including breaks in planned driving time), how long does the trip take?
    2. A swimming pool holds 120 000120\,000120000 L. A hose delivers 120120120 L/min. How long to fill (hours)?
    3. A box of 242424 pens costs $7.20. A single pen costs $0.40. Which is better value, and by how much per pen?
    4. Two phone plans: A is $25/month + $0.10/min; B is $35/month with unlimited calls. For what usage does B beat A?
    5. An alloy uses 555 kg of copper for every 333 kg of tin. For a 404040 kg alloy, how much of each?

Challenge

Reasoning

Harder problems

    1. A car averages 808080 km/h for 222 hours and then 606060 km/h for 333 hours. What is its average speed for the whole trip?
    2. A shopkeeper buys tea at $12/kg and sells it at $15/kg. What percentage profit is this?
    3. A tap fills a tank at 888 L/min while a drain removes water at 333 L/min. The tank holds 600600600 L; it starts empty. How long to fill?
    4. Currency arbitrage: $1 AUD == = $0.65 USD; $1 USD == = $0.80 EUR; $1 EUR == = $1.60 AUD. Is there a profit in converting $100 AUD → USD → EUR → AUD? If so, how much?
Year 8 Mathematics study companion | Practice