Year 8 Mathematics | Victorian Curriculum 2.0
Pythagoras' theorem
Topic 13 | Measurement & Space | Practice

What you will learn

  • identify the hypotenuse in a right-angled triangle,
  • apply Pythagoras’ theorem to find the hypotenuse when the two legs are given,
  • apply it in reverse to find a leg when the hypotenuse and one leg are known,
  • recognise common Pythagorean triples,
  • use it in real contexts - ladders, navigation, screen diagonals.
Why does a² + b² = c² work?

Pythagoras’ theorem is not just a formula to memorise — it describes a real geometric fact. If you draw a square on each side of a right-angled triangle, the area of the square on the hypotenuse exactly equals the combined areas of the other two squares. The right angle creates this rigid constraint. No other angle does it. That is why right angles are so important in construction, navigation and design: they lock the relationship between the three sides.

Where you'll see this
  • Construction: carpenters square a frame by checking a 333-444-555 triangle.
  • Navigation: straight-line distance between two waypoints on a grid.
  • Screens: a ”555555 inch TV” measures the diagonal, not the width.
  • Surveying: measuring a distance across an obstacle using two perpendicular legs.
Worked example 0 Real-world example: is the gate square?

A carpenter builds a rectangular gate 1.21.21.2 m wide and 0.90.90.9 m tall. She measures the diagonal to check it is perfectly rectangular.

1.2 m0.9 m1.5 m ?
  1. Expected diagonal: d2=1.22+0.92=1.44+0.81=2.25d^2 = 1.2^2 + 0.9^2 = 1.44 + 0.81 = 2.25d2=1.22+0.92=1.44+0.81=2.25.
  2. d=2.25=1.5d = \sqrt{2.25} = 1.5d=2.25​=1.5 m.
  3. She measures corner-to-corner: if her tape reads 1.51.51.5 m, the gate is perfectly square. If not, the frame is skewed and needs adjusting.

Key idea: the 333-444-555 triple (scaled to 0.90.90.9-1.21.21.2-1.51.51.5) is used daily in construction to verify right angles without a protractor.

1. The theorem

In a right-angled triangle with legs aaa and bbb and hypotenuse ccc (the side opposite the right angle, and the longest):

b (leg)a(leg)c (hypotenuse)
A right-angled triangle: legs a and b meet at the right angle; c (the hypotenuse) is opposite the right angle.
Pythagoras' theorem
a2+b2=c2.a^2 + b^2 = c^2.a2+b2=c2.

Geometrically, the theorem says the square built on the hypotenuse has the same area as the two squares built on the legs, put together.

4² = 1643² = 935² = 25c = 5
The classic picture: the big square on the hypotenuse equals the sum of the two smaller squares on the legs. Here 3² + 4² = 5², or 9 + 16 = 25.
Which side is the hypotenuse?

The hypotenuse is always opposite the right angle, and always the longest side.

Mental checkpoint

Before moving on: can you state Pythagoras’ theorem from memory? Which side is always the hypotenuse?

2. Find the hypotenuse

Worked example E Very easy: 3-4-5 triangle

A right triangle has legs 333 cm and 444 cm. Find the hypotenuse.

c2=32+42=9+16=25,c=25=5 cm.c^2 = 3^2 + 4^2 = 9 + 16 = 25, \qquad c = \sqrt{25} = 5 \text{ cm}.c2=32+42=9+16=25,c=25​=5 cm.

This is the most famous Pythagorean triple. Memorise it.

Worked example 1 Scaled triple: 6-8-10

Legs 666 cm and 888 cm. Find the hypotenuse.

c2=62+82=36+64=100,c=100=10 cm.c^2 = 6^2 + 8^2 = 36 + 64 = 100, \qquad c = \sqrt{100} = 10 \text{ cm}.c2=62+82=36+64=100,c=100​=10 cm.

Notice this is the 333-444-555 triple doubled.

Worked example 2 Irrational result

Legs 222 and 333. Find the hypotenuse exactly and to 2 dp.

c2=4+9=13,c=13≈3.61.c^2 = 4 + 9 = 13, \qquad c = \sqrt{13} \approx 3.61.c2=4+9=13,c=13​≈3.61.
Don't split the square root

9+16=25=5\sqrt{9 + 16} = \sqrt{25} = 59+16​=25​=5, NOT 9+16=3+4=7\sqrt{9} + \sqrt{16} = 3 + 4 = 79​+16​=3+4=7. You must add first, then take the root.

Check your answer

The hypotenuse is ALWAYS the longest side, opposite the right angle. If your answer is shorter than one of the legs, something is wrong.

3. Find a leg (reverse)

Worked example 3 Find a leg

Hypotenuse 131313; one leg 555. Find the other leg.

52+b2=132  ⟹  b2=169−25=144,b=12.5^2 + b^2 = 13^2 \;\Longrightarrow\; b^2 = 169 - 25 = 144, \qquad b = 12.52+b2=132⟹b2=169−25=144,b=12.

Check: 5,12,135, 12, 135,12,13 is a Pythagorean triple.

Finding a leg means subtract

When finding a leg, subtract: a2=c2−b2a^2 = c^2 - b^2a2=c2−b2. Don’t add — that gives you a number bigger than the hypotenuse.

4. Common Pythagorean triples

These integer-sided right triangles are worth recognising:

(3,4,5),(5,12,13),(8,15,17),(7,24,25),(9,40,41),(20,21,29).(3,4,5), \quad (5,12,13), \quad (8,15,17), \quad (7,24,25), \quad (9,40,41), \quad (20,21,29).(3,4,5),(5,12,13),(8,15,17),(7,24,25),(9,40,41),(20,21,29).

Any multiple of a triple is also a triple: (6,8,10)(6, 8, 10)(6,8,10), (9,12,15)(9, 12, 15)(9,12,15), etc.

5. Real contexts

Worked example 4 The ladder problem

A 555 m ladder leans against a wall with its foot 1.51.51.5 m from the base of the wall. How high up the wall does it reach?

1.5 mh = ?5 m
The ladder is the hypotenuse; the wall and the ground are the legs.

Let the height be hhh. The ladder is the hypotenuse.

h2+1.52=52  ⟹  h2=25−2.25=22.75,h≈4.77 m.h^2 + 1.5^2 = 5^2 \;\Longrightarrow\; h^2 = 25 - 2.25 = 22.75, \qquad h \approx 4.77 \text{ m}.h2+1.52=52⟹h2=25−2.25=22.75,h≈4.77 m.
Worked example 5 Screen diagonal

A TV is advertised as “40 inch” (the diagonal). If the screen is 353535 inches wide, how tall is it?

height2=402−352=1600−1225=375,height≈19.4 in.\text{height}^2 = 40^2 - 35^2 = 1600 - 1225 = 375, \qquad \text{height} \approx 19.4 \text{ in}.height2=402−352=1600−1225=375,height≈19.4 in.

Practice: Year 8 core

Fluency

Find the hypotenuse

    1. Legs 3,43, 43,4.
    2. Legs 5,125, 125,12.
    3. Legs 6,86, 86,8.
    4. Legs 9,409, 409,40.
    5. Legs 2,22, 22,2. Give the exact value and the decimal.
    6. Legs 1,31, \sqrt{3}1,3​. Give the exact hypotenuse.
Fluency

Find a leg

    1. Hypotenuse 252525, leg 777.
    2. Hypotenuse 171717, leg 888.
    3. Hypotenuse 151515, leg 999.
    4. Hypotenuse 505050, leg 303030.
    5. Hypotenuse 20\sqrt{20}20​, leg 222. Give the exact value.
Fluency

Is it a right triangle?

    A triangle with sides a,b,ca, b, ca,b,c (largest ccc) is right-angled if and only if a2+b2=c2a^2 + b^2 = c^2a2+b2=c2.

    1. 6,8,106, 8, 106,8,10 - right-angled?
    2. 4,5,64, 5, 64,5,6 - right-angled?
    3. 7,24,257, 24, 257,24,25 - right-angled?
    4. 5,12,145, 12, 145,12,14 - right-angled?
Reasoning

Explain and spot the mistake

    1. Lee writes 52+122=175^2 + 12^2 = 1752+122=17. Explain the error.
    2. Explain why the hypotenuse must always be longer than either leg.
    3. A triangle has sides 9,12,159, 12, 159,12,15. Is it right-angled? Is the triangle similar to any triple you recognise?
    4. Sam says 7,24,267, 24, 267,24,26 is a Pythagorean triple because the numbers “look similar” to 7,24,257, 24, 257,24,25. Is Sam right? Justify.
Problem solving

Real contexts

    1. A ladder 666 m long is placed with its foot 222 m from a wall. How high does it reach?
    2. A rectangular field is 303030 m by 404040 m. How far is the diagonal?
    3. A guy wire supports a pole and is attached 888 m from the foot of the pole, 151515 m up. How long is the wire?
    4. A TV has a 50-inch diagonal and is 454545 inches wide. Is it taller than 202020 inches? Justify.
    5. A ship sails 888 km east and then 666 km north. How far is it from its starting point?

Challenge

Reasoning

Harder triangles

    1. A right-angled isosceles triangle has legs of length aaa. Show that the hypotenuse is a2a\sqrt{2}a2​.
    2. A rectangular prism measures 333 cm by 444 cm by 121212 cm. Find the length of the longest internal diagonal.
    3. A rhombus has diagonals 101010 cm and 242424 cm. Find the side length.
    4. An equilateral triangle has side 101010 cm. Find its height, to one decimal place.
Year 8 Mathematics study companion | Practice