Year 8 Mathematics | Victorian Curriculum 2.0
Percentages in context
Topic 05 | Number & Algebra | Practice

What you will learn

  • increase and decrease a quantity by a percentage in one step,
  • solve reverse problems (“find the original after a 20%20\%20% rise”),
  • work with profit, loss, mark-ups, discounts, and GST,
  • calculate percentage error between an estimate and an actual value,
  • recognise when percentages compound rather than simply adding.
Why percentages instead of plain numbers?

“A shop raised prices by $10” — is that a lot? On a $20 item, yes. On a $2000 laptop, barely noticeable. Percentages scale every comparison to 100100100, so a ”5%5\%5% increase” means the same relative jump regardless of the starting price. That is why news, finance and science report changes as percentages — they make different-sized quantities comparable.

Where you'll see this
  • Shopping: sale discounts, mark-ups, and GST added at the register.
  • Finance: interest rates, investment returns, inflation figures.
  • Science: percentage error when comparing a measurement to a known value.
  • News: “house prices rose 8%8\%8%” or “unemployment fell 0.3%0.3\%0.3%.”
Worked example 0 Real-world example: sale price with GST

A jacket is marked $120, on sale for 25%25\%25% off. After the discount, 10%10\%10% GST is added. What do you actually pay?

  1. Discount: 120×0.75=90120 \times 0.75 = 90120×0.75=90 dollars.
  2. Add GST: 90×1.10=9990 \times 1.10 = 9990×1.10=99 dollars.
  3. You pay $99, not $120 with ”25%−10%=15%25\% - 10\% = 15\%25%−10%=15% off.”

Key idea: the discount and GST apply to different bases ($120 then $90), so you cannot just subtract the percentages. Percentage changes compound — they must be applied one step at a time.

1. Percentage increase and decrease

Percentage change in one step

Increase by p percent
new=A×(1+p100).\text{new} = A \times \left(1 + \dfrac{p}{100}\right).new=A×(1+100p​).
Decrease by p percent
new=A×(1−p100).\text{new} = A \times \left(1 - \dfrac{p}{100}\right).new=A×(1−100p​).
Reverse problem: find the original

If the new value is given after a change of p%p\%p%, divide by the bracket:

A=new1±p100.A = \dfrac{\text{new}}{1 \pm \dfrac{p}{100}}.A=1±100p​new​.

Use +++ for an increase, −-− for a decrease.

Worked example 1 Straightforward increase

A bike costs $320 and its price rises 5%5\%5%. Find the new price.

320×1.05=336.320 \times 1.05 = 336.320×1.05=336.

New price: $336.

Worked example 2 Reverse: find the original

A shirt is sold for $42 after a 20%20\%20% mark-up. Find the original cost.

A=421.20=35.A = \dfrac{42}{1.20} = 35.A=1.2042​=35.

Original cost: $35.

2. Profit, loss, mark-ups, discounts

  • Mark-up (profit): add a percentage to the cost price to get the selling price.
  • Discount: subtract a percentage from the marked price.
  • Profit = selling price − cost price. Loss = cost price − selling price when the cost exceeds the selling price.
Worked example 3 Profit as a percentage

A shopkeeper buys a chair for $80 and sells it for $100. Find the profit and express it as a percentage of the cost.

  • Profit: 100−80=20100 - 80 = 20100−80=20 dollars.
  • Percentage profit: 2080×100=25%\dfrac{20}{80} \times 100 = 25\%8020​×100=25%.

3. GST (Goods and Services Tax)

In Australia, GST is 10%10\%10% added to most sales. To find the GST-included price:

GST-inc.=pre-GST×1.10.\text{GST-inc.} = \text{pre-GST} \times 1.10.GST-inc.=pre-GST×1.10.

To pull GST out of a GST-included price:

pre-GST=GST-inc.1.10,GST=GST-inc.11.\text{pre-GST} = \dfrac{\text{GST-inc.}}{1.10}, \qquad \text{GST} = \dfrac{\text{GST-inc.}}{11}.pre-GST=1.10GST-inc.​,GST=11GST-inc.​.
Worked example 4 GST in reverse

A receipt shows a total of $66 (GST included). Find the GST.

GST=6611=6 dollars.\text{GST} = \dfrac{66}{11} = 6 \text{ dollars}.GST=1166​=6 dollars.

(Pre-GST would be 606060; then 60×1.10=6660 \times 1.10 = 6660×1.10=66.)

4. Percentage error

When an estimate or a measurement is compared with an actual (or accepted) value, the percentage error describes the relative size of the gap.

Percentage error
error %=∣estimate−actual∣actual×100.\text{error }\% = \dfrac{|\text{estimate} - \text{actual}|}{\text{actual}} \times 100.error %=actual∣estimate−actual∣​×100.

Absolute value so the error is always positive.

Worked example 5 Estimate vs actual

A student estimates a fence is 252525 m long. The true length is 282828 m. Find the percentage error.

∣25−28∣28×100=328×100≈10.7%.\dfrac{|25 - 28|}{28} \times 100 = \dfrac{3}{28} \times 100 \approx 10.7\%.28∣25−28∣​×100=283​×100≈10.7%.
Compounding, not adding

A 20%20\%20% increase followed by a 20%20\%20% decrease is not the same as no change. Starting from 100100100: 100→120→96100 \to 120 \to 96100→120→96. The decrease applies to the larger (post-increase) amount, not the original.


Practice: Year 8 core

Fluency

Increase and decrease

    1. Increase 808080 by 25%25\%25%.
    2. Decrease $150 by 12%12\%12%.
    3. Increase $85 by 20%20\%20%.
    4. Decrease 250250250 by 6%6\%6%.
    5. A jacket is $85, discounted by 20%20\%20%. Find the sale price.
    6. A subscription is $120 and rises 8%8\%8%. Find the new price.
Fluency

Reverse problems

    1. After a 15%15\%15% increase, a price is $46. Find the original.
    2. After a 25%25\%25% discount, a shirt costs $36. Find the original price.
    3. A salary increased by 5%5\%5% to $63,000. Find the old salary.
    4. A population fell by 8%8\%8% to 920092009200. Find the original population.
Fluency

Profit, loss, GST

    1. Buy at $60, sell at $75. Percentage profit?
    2. Buy at $200, sell at $170. Percentage loss?
    3. A price is $49 before GST (10%10\%10%). What is the GST-included price?
    4. A total (GST-inc.) is $77. How much GST is in it?
    5. A meal costs $55 GST-inc. How much is the pre-GST price?
Reasoning

Percentage error & explain

    1. A scientist measures a rod as 12.312.312.3 cm; the true length is 12.012.012.0 cm. Find the percentage error.
    2. A shop advertises “was $100, now $75”. What percentage discount is this?
    3. Sam says a 30%30\%30% rise then a 30%30\%30% fall brings the price back to the start. Show with a worked example whether this is true.
    4. Explain the difference between ”20%20\%20% off then 10%10\%10% off” and a single ”30%30\%30% off”.
Problem solving

Real contexts

    1. A laptop’s sticker price is $1400. In a sale it is reduced 15%15\%15%. After the sale the shop also adds GST (10%10\%10%). What does the customer pay?
    2. Mira earns $800 per week. She gets a 4%4\%4% rise, then six months later a further 3%3\%3% rise. What does she earn per week now?
    3. A town’s population rose from 12 50012\,50012500 to 14 00014\,00014000 over five years. What was the percentage increase?
    4. A phone’s retail price includes 10%10\%10% GST and is $1089. How much GST is included in the price?
    5. A supermarket sells a 500500500 g jar for $5.50 and a 750750750 g jar for $7.70. Which is better value, and by what percentage is the better-value jar cheaper per gram?

Challenge

Reasoning

Harder reasoning

    1. A value rises by r%r\%r% and then falls by r%r\%r%. Show that the end value is always less than the starting value (for r>0r > 0r>0), and find a formula for the net percentage change.
    2. A shop marks up cost by 25%25\%25% and then gives a 20%20\%20% discount from the marked price. Is the final price above or below cost? By how much?
    3. The true area of a rectangle is 242424 cm². A student estimates the area as 272727 cm² by rounding the sides up. What is the percentage error?
    4. A bank account earns 6%6\%6% interest per year, compounded yearly. If the starting balance is $500, find the balance after 333 years.
Year 8 Mathematics study companion | Practice