Year 8 Mathematics | Victorian Curriculum 2.0
Exponent laws
Topic 02 | Number & Algebra | Practice

Start here: why do we need laws?

Look at this: 23×222^3 \times 2^223×22. Instead of computing each power and then multiplying, what if we noticed this is really

(2×2×2)⏟23×(2×2)⏟22=2×2×2×2×2=25.\underbrace{(2 \times 2 \times 2)}_{2^3} \times \underbrace{(2 \times 2)}_{2^2} = 2 \times 2 \times 2 \times 2 \times 2 = 2^5.23(2×2×2)​​×22(2×2)​​=2×2×2×2×2=25.

Three twos, times two twos, makes five twos. The exponents add. That’s the whole idea behind the index laws — they are shortcuts that just count the factors correctly.

Try mentally first

Every time you see an index law, ask: “how many factors of the base are we really multiplying?” am×ana^m \times a^nam×an is m+nm + nm+n factors. (am)n(a^m)^n(am)n is a block of mmm factors, nnn times — that’s m×nm \times nm×n factors. The laws are bookkeeping, not magic.

What you will learn

  • multiply powers with the same base by adding the exponents,
  • divide powers with the same base by subtracting the exponents,
  • raise a power to a power by multiplying the exponents,
  • use the zero exponent rule: a0=1a^0 = 1a0=1 for any non-zero aaa,
  • combine these laws to simplify compound expressions.
Where you'll see this
  • Computing: memory sizes are powers of 2 (KB, MB, GB each differ by 2102^{10}210).
  • Biology: bacterial growth — a colony doubles every hour is 2t2^t2t.
  • Finance: compound interest multiplies by the same factor each year.
  • Geometry: doubling a cube’s side multiplies its volume by 23=82^3 = 823=8.

1. Recap of index notation

ana^nan means aaa multiplied by itself nnn times: 34=3×3×3×3=813^4 = 3 \times 3 \times 3 \times 3 = 8134=3×3×3×3=81. The base is aaa, the exponent (or index) is nnn.

Worked example E Very easy: count the factors

Simplify   x2×x3\;x^2 \times x^3x2×x3.

Expand both sides to see what’s happening:

x2×x3=(x⋅x)×(x⋅x⋅x)=x5.x^2 \times x^3 = (x \cdot x) \times (x \cdot x \cdot x) = x^5.x2×x3=(x⋅x)×(x⋅x⋅x)=x5.

Five factors of xxx. The exponents 222 and 333 added to give 555.

2. The three index laws

Index laws (positive integer exponents, same base)

Product of powers
am×an  =  am+n.a^m \times a^n \;=\; a^{m + n}.am×an=am+n.

Example: 23×25=28=2562^3 \times 2^5 = 2^{8} = 25623×25=28=256.

Quotient of powers
am÷an  =  am−n,a≠0.a^m \div a^n \;=\; a^{m - n}, \quad a \neq 0.am÷an=am−n,a=0.

Example: 57÷53=54=6255^7 \div 5^3 = 5^4 = 62557÷53=54=625.

Power of a power
(am)n  =  am×n.(a^m)^n \;=\; a^{m \times n}.(am)n=am×n.

Example: (32)4=38=6561(3^2)^4 = 3^8 = 6561(32)4=38=6561.

Same base only

23×322^3 \times 3^223×32 does not simplify using the index laws because the bases are different (222 and 333). Just evaluate: 8×9=728 \times 9 = 728×9=72.

Common mistake: adding vs multiplying

23+232^3 + 2^323+23 is not 262^626. The laws only apply to multiplying and dividing powers, not adding or subtracting. 23+23=8+8=16=242^3 + 2^3 = 8 + 8 = 16 = 2^423+23=8+8=16=24, not 262^626.

Worked example 1 Product of powers

Simplify   x4×x7\;x^4 \times x^7x4×x7.

Same base, so add the exponents:

x4×x7  =  x4+7  =  x11.x^4 \times x^7 \;=\; x^{4 + 7} \;=\; x^{11}.x4×x7=x4+7=x11.
Worked example 2 Quotient of powers

Simplify   y12y5\;\dfrac{y^{12}}{y^{5}}y5y12​.

Same base, subtract the exponents:

y12y5  =  y12−5  =  y7.\dfrac{y^{12}}{y^{5}} \;=\; y^{12 - 5} \;=\; y^{7}.y5y12​=y12−5=y7.
Worked example 3 Power of a power

Simplify   (m3)4\;(m^3)^{4}(m3)4.

Multiply the exponents:

(m3)4  =  m3×4  =  m12.(m^3)^{4} \;=\; m^{3 \times 4} \;=\; m^{12}.(m3)4=m3×4=m12.

3. The zero exponent

What should a0a^0a0 equal? Use the quotient rule:

anan  =  an−n  =  a0.\dfrac{a^n}{a^n} \;=\; a^{n - n} \;=\; a^{0}.anan​=an−n=a0.

But also anan=1\dfrac{a^n}{a^n} = 1anan​=1 for any a≠0a \neq 0a=0. So both answers must agree:

Zero exponent rule
a0  =  1,a≠0.a^0 \;=\; 1, \qquad a \neq 0.a0=1,a=0.

Examples: 70=17^0 = 170=1, (−5)0=1(-5)^0 = 1(−5)0=1, x0=1x^0 = 1x0=1 (as long as x≠0x \neq 0x=0).

4. Combining the laws

Worked example 4 Combining laws

Simplify   (a3)2×a5a4\;\dfrac{(a^3)^2 \times a^5}{a^4}a4(a3)2×a5​.

  1. Apply power of a power to (a3)2=a6(a^3)^2 = a^6(a3)2=a6.
  2. Product of powers on the top: a6×a5=a11a^6 \times a^5 = a^{11}a6×a5=a11.
  3. Quotient of powers: a11a4=a7\dfrac{a^{11}}{a^4} = a^{7}a4a11​=a7.

Final: a7a^7a7.

Worked example 5 With numeric coefficients

Simplify   6x5×4x3\;6x^5 \times 4x^36x5×4x3.

Multiply the numbers separately from the variables:

6x5×4x3  =  (6×4)×(x5×x3)  =  24x8.6x^5 \times 4x^3 \;=\; (6 \times 4) \times (x^5 \times x^3) \;=\; 24 x^{8}.6x5×4x3=(6×4)×(x5×x3)=24x8.

Practice: Year 8 core

Fluency

Apply one law at a time

    1. Simplify 23×262^3 \times 2^623×26.
    2. Simplify a5×a2a^5 \times a^2a5×a2.
    3. Simplify x10÷x4x^{10} \div x^4x10÷x4.
    4. Simplify m8m3\dfrac{m^8}{m^3}m3m8​.
    5. Simplify (32)3(3^2)^3(32)3.
    6. Simplify (p4)5(p^4)^5(p4)5.
    7. Evaluate 707^070.
    8. Evaluate (−3)0(-3)^0(−3)0.
    9. Simplify y12÷y12y^{12} \div y^{12}y12÷y12.
    10. Simplify (xy2)3(x y^2)^3(xy2)3. (Hint: each factor raised to the power.)
Fluency

Combine the laws

    1. Simplify a5×a3a4\dfrac{a^5 \times a^3}{a^4}a4a5×a3​.
    2. Simplify (b3)2b5\dfrac{(b^3)^2}{b^{5}}b5(b3)2​.
    3. Simplify (2m)3×m2(2m)^3 \times m^2(2m)3×m2.
    4. Simplify 10x72x4\dfrac{10 x^7}{2 x^4}2x410x7​.
    5. Simplify 5a3×2a45 a^3 \times 2 a^45a3×2a4.
    6. Simplify (3x2)3(3 x^2)^3(3x2)3.
    7. Simplify a4b6ab2\dfrac{a^4 b^6}{a b^2}ab2a4b6​.
    8. Simplify (x3)4⋅x2x10\dfrac{(x^3)^4 \cdot x^2}{x^{10}}x10(x3)4⋅x2​.
Reasoning

Explain and spot the mistake

    1. Sam writes 23×23=292^3 \times 2^3 = 2^923×23=29. Is Sam correct? If not, what should it be?
    2. Explain why a0=1a^0 = 1a0=1 is forced by the quotient rule.
    3. Mira writes (a2)3=a5(a^2)^3 = a^5(a2)3=a5. Explain the error and give the correct value.
    4. Is x−2x^{-2}x−2 a Year 8 result, and if not, what does it mean? (Scope note: negative exponents appear in Year 9; for now think about what the quotient rule would give you.)
Problem solving

Applications

    1. A bacterium doubles every hour. Starting from 111 cell, write the number of cells after nnn hours as a power of 222. How many cells after 888 hours?
    2. A cube of side sss has volume s3s^3s3. Express the volume of a cube whose side is doubled, as a multiple of s3s^3s3.
    3. Computer memory is measured in powers of 222. How much bigger is 2202^{20}220 than 2102^{10}210? Express as a power of 222.
    4. A square tile pattern has nnn rows and nnn columns. If each tile is 101010 cm by 101010 cm, express the total floor area in cm² using exponent notation.

Challenge

Reasoning

Harder reasoning

    1. Simplify (2x3y)2×(xy2)3x4y5\dfrac{(2 x^3 y)^2 \times (x y^2)^3}{x^4 y^5}x4y5(2x3y)2×(xy2)3​.
    2. If am=8a^m = 8am=8 and an=4a^n = 4an=4, find am+na^{m + n}am+n without finding aaa, mmm or nnn.
    3. A formula for a population model is P=P0×2tP = P_0 \times 2^tP=P0​×2t where P0P_0P0​ is the starting population and ttt is time in years. If a town starts at 500050005000 and the population doubles every year, what is the population after 666 years?
    4. Simplify and write as a power of 222: 85×43322\dfrac{8^5 \times 4^3}{32^2}32285×43​. (Hint: write every base as a power of 222.)
Year 8 Mathematics study companion | Practice