Year 8 Mathematics | Victorian Curriculum 2.0
Circles: circumference & area
Topic 10 | Measurement & Space | Practice

What you will learn

  • use C=2πrC = 2\pi rC=2πr (or C=πdC = \pi dC=πd) to find the circumference,
  • use A=πr2A = \pi r^2A=πr2 to find the area of a circle,
  • solve reverse problems: given circumference or area, find the radius,
  • combine circles with other shapes (semicircles, sectors, composite circle shapes).
What makes π special?

Draw any circle — tiny or enormous — and divide its circumference by its diameter. You always get the same number: 3.14159…3.14159\ldots3.14159…, which we call π\piπ. This is not a coincidence or an invention; it is a property of every circle in the universe. Because π\piπ is irrational (its decimal never ends or repeats), we keep the symbol and only round at the final step — the same reason we use surds.

Where you'll see this
  • Wheels & gears: circumference tells you how far one wheel rotation travels.
  • Pizza & pie sizing: area per dollar comparisons use πr2\pi r^2πr2.
  • Sports fields: the centre circle and penalty arcs are sectors of a circle.
  • Engineering: pipe cross-section area controls water flow capacity.
Worked example 0 Real-world example: how far does a bike travel per wheel turn?

A bike wheel has a diameter of 666666 cm. How far does the bike move in one full rotation?

r = 33 cmC = 207 cm
  1. Radius r=66÷2=33r = 66 \div 2 = 33r=66÷2=33 cm.
  2. Circumference C=2πr=2×π×33=66π≈207.3C = 2\pi r = 2 \times \pi \times 33 = 66\pi \approx 207.3C=2πr=2×π×33=66π≈207.3 cm.
  3. One full rotation moves the bike about 2.072.072.07 m forward.
  4. Bonus: in a 111 km ride, the wheel turns 10002.073≈483\dfrac{1000}{2.073} \approx 4832.0731000​≈483 times.

Key idea: the circumference formula converts a rotation (something you can see) into a straight-line distance (something you can measure).

1. Recap: parts of a circle

rdCcentre
Parts of a circle: centre, radius r, diameter d (through the centre), and circumference C (the whole distance around).
  • Centre: the point in the middle.
  • Radius (rrr): from centre to any point on the edge.
  • Diameter (ddd): straight across through the centre; d=2rd = 2rd=2r.
  • Circumference (CCC): the total distance around the circle.
  • π≈3.14159\pi \approx 3.14159π≈3.14159 (irrational). Common approximations: 3.143.143.14 and 227\tfrac{22}{7}722​.
d=dddC = π × d ≈ 3.14 × da bit more than 3 diameters
Why C = πd: if you 'unroll' a circle's edge into a straight line, that line is exactly π times the diameter. It takes just over 3 diameters to wrap around.

2. The two formulas

Circle formulas

Circumference
C=2πr  =  πd.C = 2 \pi r \;=\; \pi d.C=2πr=πd.
Area
A=πr2.A = \pi r^2.A=πr2.
Exact vs approximate answers

If the answer has π\piπ in it, writing C=10πC = 10\piC=10π or A=25πA = 25\piA=25π is exact. To get a decimal, multiply by an approximation of π\piπ. Use the exact form unless the question asks for a number.

Worked example 1 Circumference

A circle has radius 777 cm. Find its circumference using π≈227\pi \approx \tfrac{22}{7}π≈722​.

C=2πr=2×227×7=44 cm.C = 2 \pi r = 2 \times \tfrac{22}{7} \times 7 = 44 \text{ cm}.C=2πr=2×722​×7=44 cm.
Worked example 2 Area

A circle has diameter 202020 cm. Find its area using π≈3.14\pi \approx 3.14π≈3.14.

  1. Radius: r=202=10r = \tfrac{20}{2} = 10r=220​=10 cm.
  2. Area: A=πr2=3.14×100=314A = \pi r^2 = 3.14 \times 100 = 314A=πr2=3.14×100=314 cm2^22.

3. Reverse problems

Worked example 3 Find the radius from circumference

A circle has circumference 31.431.431.4 cm. Find its radius (using π≈3.14\pi \approx 3.14π≈3.14).

r=C2π=31.46.28=5 cm.r = \dfrac{C}{2\pi} = \dfrac{31.4}{6.28} = 5 \text{ cm}.r=2πC​=6.2831.4​=5 cm.
Worked example 4 Find the radius from area

A circle has area 154154154 cm2^22. Find its radius (using π≈227\pi \approx \tfrac{22}{7}π≈722​).

  1. A=πr2A = \pi r^2A=πr2, so r2=Aπ=15422/7=154×722=49r^2 = \dfrac{A}{\pi} = \dfrac{154}{22/7} = 154 \times \dfrac{7}{22} = 49r2=πA​=22/7154​=154×227​=49.
  2. r=49=7r = \sqrt{49} = 7r=49​=7 cm.

4. Semicircles and sectors

A semicircle is half a circle. A sector is a pie-slice fraction of a circle.

  • Semicircle area: 12πr2\tfrac{1}{2} \pi r^221​πr2.
  • Quarter-circle area: 14πr2\tfrac{1}{4} \pi r^241​πr2.

For the perimeter of a semicircle, remember the straight edge (the diameter): P=πr+2rP = \pi r + 2rP=πr+2r.

Worked example 5 Semicircle perimeter and area

A semicircle has radius 555 cm. Find its area and perimeter (use π≈3.14\pi \approx 3.14π≈3.14).

  • Area: 12×3.14×25=39.25\tfrac{1}{2} \times 3.14 \times 25 = 39.2521​×3.14×25=39.25 cm2^22.
  • Perimeter: 3.14×5+2×5=15.7+10=25.73.14 \times 5 + 2 \times 5 = 15.7 + 10 = 25.73.14×5+2×5=15.7+10=25.7 cm.

Practice: Year 8 core

Where a value of π\piπ is not given, use π≈3.14\pi \approx 3.14π≈3.14.

Fluency

Circumference and area

    1. A circle has radius 444 cm. Find its circumference.
    2. A circle has diameter 101010 m. Find its circumference.
    3. A circle has radius 999 cm. Find its area.
    4. A circle has diameter 141414 cm. Find its area (use π≈227\pi \approx \tfrac{22}{7}π≈722​).
    5. A circle has radius 2.52.52.5 m. Find its circumference.
    6. A circle has radius 555 cm. Find its area.
Fluency

Reverse problems

    1. A circle’s circumference is 62.862.862.8 cm. Find its radius.
    2. A circle’s area is 50.2450.2450.24 m2^22. Find its radius.
    3. A wheel has circumference 1.571.571.57 m. Find its diameter.
    4. A round plate has area 314314314 cm2^22. Find its diameter.
Fluency

Semicircles and sectors

    1. A semicircle has radius 666 cm. Find its area and perimeter.
    2. A quarter-circle has radius 444 m. Find its area.
    3. A half-moon window is a semicircle of diameter 111 m. Find its area.
    4. A pizza slice is a sector making 18\tfrac{1}{8}81​ of a pizza of radius 121212 cm. Find its area.
Reasoning

Explain and spot the mistake

    1. Kira writes C=πrC = \pi rC=πr for a circle’s circumference. Is Kira correct? If not, what should it be?
    2. Without calculating, decide which changes more: doubling the radius doubles or quadruples the area? Justify.
    3. A student writes the area of a circle with radius 555 cm as π×10\pi \times 10π×10 cm2^22. Explain the mistake.
    4. Explain why the circumference of any circle divided by its diameter always gives the same number (which we call π\piπ).
Problem solving

Real contexts

    1. A round pool has radius 3.53.53.5 m. A fence is to be built around it, 0.50.50.5 m from the edge. How long is the fence?
    2. A pizza has diameter 323232 cm. Find its area, then the area of one slice if cut into 888 equal pieces.
    3. A circular lawn has diameter 101010 m. A mower cuts 0.50.50.5 m2^22 per second. How long to mow (seconds, then minutes)?
    4. A running track is 400400400 m around, consisting of two straights of 100100100 m each and two semicircular ends. Find the radius of the semicircles (use π≈3.14\pi \approx 3.14π≈3.14).

Challenge

Reasoning

Harder circles

    1. A rectangle 666 cm by 444 cm has a semicircle attached to each short side (so the two semicircles form one full circle). Find the total perimeter and area.
    2. Two circles: small has radius 333 cm, large has radius 555 cm. Find the area of the ring between them (the annulus).
    3. A running track sector is 14\tfrac{1}{4}41​ of a circle with radius 505050 m. Find its arc length.
    4. A pizza shop offers a 303030 cm diameter pizza for $14 or a 404040 cm diameter pizza for $22. Which is better value per cm2^22?
Year 8 Mathematics study companion | Practice