Year 7 Science | Victorian Curriculum 2.0
Mixtures & separating techniques
Topic 04 | Chemical sciences | Practice

What you will learn

  • the difference between a pure substance and a mixture,
  • homogeneous (uniform) vs heterogeneous (non-uniform) mixtures, including solutions and suspensions,
  • which property each separating technique exploits (particle size, boiling point, magnetism, solubility),
  • how filtration, evaporation, distillation, chromatography, decantation and magnetic separation work,
  • how to calculate concentration as a percentage by mass.
Why does this matter?

Almost nothing you meet in daily life is pure. Air, tap water, steel, blood, cooking oil and petrol are all mixtures. Chemistry works because we can take a messy mixture and separate it into its pure components using the differences in their properties. Pick the right technique and you can purify sea water, test an athlete’s urine, or produce aviation fuel from crude oil. Pick the wrong one and nothing happens.

Where you'll see this
  • Kitchen: straining pasta, separating butter from buttermilk, freeze-drying herbs.
  • Drinking water: sand filters, UV treatment, desalination by distillation.
  • Forensics: chromatography of inks on a ransom note, blood testing.
  • Industry: crude oil is split into petrol, diesel and kerosene by fractional distillation.
  • Recycling: magnetic separation pulls steel cans from mixed waste.
Worked example 0 Real-world example: purifying a salty, sandy mixture

You are given a beaker of seawater mixed with sand. The goal is to recover pure salt and pure water.

  1. Filter the mixture through filter paper. Sand stays in the paper (residue); salty water passes through (filtrate).
  2. Rinse the sand with distilled water and dry it.
  3. Distil the salty water: heat it in a flask with a condenser. Pure water boils off, condenses, and collects. Salt stays behind.
  4. After all the water has distilled off, solid salt remains in the original flask.

Key idea: always ask — what physical property is different between the components? Here: sand is not dissolved (so filter), then salt and water have very different boiling points (so distil).

1. Pure substances, mixtures and solutions

  • Pure substance: one kind of particle only (e.g. pure water, pure copper, pure oxygen).
  • Mixture: two or more substances mixed but not chemically joined. Each keeps its own properties.
  • Solution: a homogeneous mixture of a solute dissolved in a solvent. Salt dissolved in water.
  • Suspension: a heterogeneous mixture where undissolved particles are dispersed (muddy water).

Homogeneous: uniform throughout; you cannot see separate components (air, salt water, brass). Heterogeneous: non-uniform; you can see separate regions (sand in water, oil in vinegar, granola).

Worked example 1 Classifying common mixtures

Classify: (a) air, (b) a cup of tea with a teabag, (c) bronze, (d) soil, (e) petrol.

  • Air — homogeneous mixture (solution of gases).
  • Tea with the bag in — heterogeneous (solid bag plus liquid).
  • Bronze — homogeneous mixture of copper and tin (an alloy).
  • Soil — heterogeneous (visibly different grains and organic matter).
  • Petrol — homogeneous mixture of many hydrocarbons.

Key idea: “you can see the separate bits” is a quick test for heterogeneity.

2. Choosing a separating technique

Every technique uses one property that differs between the components.

TechniqueProperty usedTypical use
FiltrationParticle size (solid vs liquid/gas)Sand from water, tea leaves
DecantationSettling rate (denser solid sinks)Pouring clear water off sediment
EvaporationVolatility of solventRecovering solid from solution (salt from brine)
DistillationBoiling pointWater from salt, alcohol from wine
ChromatographyAttraction to paper vs solventSeparating ink pigments
MagneticMagnetism (iron/steel)Removing iron from recycling
SievingParticle size (solid from solid)Flour from lumps
CentrifugationDensitySeparating blood cells from plasma
Worked example 2 Matching method to mixture

Pick a method for each: (a) iron filings mixed with sand, (b) red dye in water, (c) copper sulfate dissolved in water, (d) two inks on a pen mark.

  • (a) Magnetic separation — iron is magnetic, sand is not.
  • (b) Distillation — boiling points differ; water boils first, leaves dye behind.
  • (c) Evaporation or crystallisation — boil off water to recover copper sulfate crystals.
  • (d) Chromatography — different pigments travel different distances up paper.

3. Filtration

mixture poured infilter paperfiltrate
Filtration setup. Filter paper traps insoluble solid (residue); liquid (filtrate) passes through.

The mixture is poured into a funnel lined with filter paper. Solid particles too large to pass through stay in the paper (residue); the liquid (filtrate) collects in the flask below.

4. Distillation

Used when you want to recover the solvent (usually water) from a solution. The solution is heated; solvent vapour rises, passes through a cooled condenser, and liquefies into a separate flask. The solute stays behind.

5. Chromatography

A small spot of mixture (e.g. ink) is placed near the bottom of filter paper. The paper sits in a solvent. The solvent rises by capillary action, carrying different pigments different distances — those attracted more to the solvent rise further; those attracted more to the paper rise less.

Worked example 3 Identifying a mystery ink

Four known inks (A, B, C, D) and one mystery ink (X) are spotted on chromatography paper. After running, X produces two spots at the same heights as the spots from ink B.

  1. Ink X contains the same two pigments as ink B.
  2. The distances match — so the chemistry matches.

Therefore, the mystery ink is (or shares the pigments of) ink B.

Key idea: chromatography is a pattern-match test. Police use it on forged cheques, and drug-testers use it on athletes.

6. Concentration

A common measure of concentration is percentage by mass:

Percentage concentration
concentration (% m/m)=mass of solutemass of solution×100.\text{concentration (\% m/m)} = \dfrac{\text{mass of solute}}{\text{mass of solution}} \times 100.concentration (% m/m)=mass of solutionmass of solute​×100.
Worked example 4 Making a brine

Dissolve 202020 g of salt in 180180180 g of water. What is the concentration?

  1. Mass of solution =20+180=200= 20 + 180 = 200=20+180=200 g.
  2. Concentration =20200×100=10%= \dfrac{20}{200} \times 100 = 10\%=20020​×100=10%.

So this is a 10%10\%10% salt solution by mass.

Solution ≠ pure

A cup of sugar water looks clear, but it is a mixture — two substances dissolved together. A solution is uniform, but not pure.


Practice: Year 7

Fluency

Tier 1: recall and identify

    1. Define: pure substance, mixture, solution, suspension.
    2. Classify as homogeneous or heterogeneous: (a) milk, (b) vinegar, (c) muesli, (d) salt water, (e) concrete.
    3. What property does filtration exploit? What property does distillation exploit?
    4. Name the technique for each: (a) separating iron nails from sawdust, (b) getting sugar from sugary water, (c) separating the inks in a felt-tip pen, (d) separating water from salt.
    5. In filtration, what are the residue and the filtrate?
    6. A solution has 151515 g of solute in 858585 g of solvent. What is the concentration (% m/m)?
    7. Give one everyday example each of filtration and evaporation.
    8. Why does distillation require both heating and cooling?
    9. Explain the difference between evaporation and distillation.
    10. Give an example of a heterogeneous mixture from the kitchen.
Reasoning

Tier 2: explain and reason

    1. Explain why filtration will not separate sugar from water.
    2. Why must chromatography use a solvent in which at least some of the pigments are soluble?
    3. A student filters muddy river water and drinks it. Is it safe? Explain using what filtration can and cannot remove.
    4. Explain how you would separate a mixture of sand, salt and iron filings using three techniques in order.
    5. Why does a chromatography spot of a pure substance produce only one mark, while a spot of a mixture produces several?
    6. A student sets up a distillation of wine (water plus ethanol). Ethanol boils at 787878°C, water at 100100100°C. Which liquid collects first? Why?
Problem solving

Tier 3: apply to a novel context

    1. A pharmacist must separate ground pills (insoluble) from their coating solution (dissolved sugar and colouring). Describe a three-step procedure.
    2. Sea water is about 3.5%3.5\%3.5% salt by mass. How much salt is in 2.02.02.0 kg of sea water?
    3. A forensic scientist has a blue ink stain from a crime scene and six suspect pens. Explain how chromatography could identify (or eliminate) the source.
    4. In industry, crude oil is separated into petrol, diesel and kerosene by fractional distillation. Using what you know about boiling points, explain why this process works.

Challenge

Reasoning

Harder reasoning

    1. A student wants to recover pure water from sea water using only the Sun’s heat and a plastic sheet (a “solar still”). Describe the setup, which physical process is used, and why it mimics distillation without a heater.
    2. A mixture contains salt, sand, iron filings, and sawdust. Design a step-by-step separation procedure that recovers all four components, stating the property each step exploits.
    3. Air is a homogeneous mixture of oxygen (≈21%\approx 21\%≈21%), nitrogen (≈78%\approx 78\%≈78%), and minor gases. Industrial oxygen is made by cooling air to around −200-200−200°C and distilling it. Explain using the particle model why this works and why it is not done at room temperature.
    4. Blood is a mixture of plasma (liquid), red and white cells, and platelets. Explain why centrifugation — not filtration — is used to separate blood, and what property it exploits.
Year 7 Science study companion | Practice