Year 7 Mathematics | Victorian Curriculum 2.0
Length, perimeter, area & circles
Topic 07 | Measurement & Space | Practice
How this topic is organised

Year 7 core covers: length conversion, perimeter, area formulas for rectangles, triangles and parallelograms (VC2M7M01), and the circle relationships between π\piπ, radius, diameter and circumference (VC2M7M03).

Extension adds the trapezium area and composite areas - these appear in Year 8 (VC2M8M01).

Year 7 core

By the end of this topic you should be able to:

  • convert between metric length units (mm, cm, m, km),
  • calculate the perimeter of any polygon,
  • find the area of a rectangle, a triangle, and a parallelogram,
  • name the parts of a circle (centre, radius, diameter, circumference),
  • use π\piπ to relate the circumference of a circle to its radius and diameter.
Where you'll see this
  • Fencing: the perimeter of a yard gives the length of fence needed.
  • Paint & carpet: the area of a wall or floor decides how much to buy.
  • Gardening: seed spread rates are per square metre.
  • Round things: the circumference of a bike wheel tells you how far you travel per turn.

1. Metric length units

Length conversions

Metric ladder (each step is x10 or /10 between adjacent units)
1 cm=10 mm,1 m=100 cm,1 km=1000 m.1 \text{ cm} = 10 \text{ mm}, \quad 1 \text{ m} = 100 \text{ cm}, \quad 1 \text{ km} = 1000 \text{ m}.1 cm=10 mm,1 m=100 cm,1 km=1000 m.
Converting

Bigger -> smaller unit: multiply. Smaller -> bigger unit: divide.

  • 3.53.53.5 m =3.5×100=350= 3.5 \times 100 = 350=3.5×100=350 cm
  • 840084008400 mm =8400÷10=840= 8400 \div 10 = 840=8400÷10=840 cm

2. Perimeter

The perimeter is the total distance around the outside of a shape. Add up every side length.

Worked example 1 Perimeter of an irregular polygon

A pentagon has sides 444 cm, 666 cm, 555 cm, 777 cm, 444 cm. Find the perimeter.

P=4+6+5+7+4=26 cm.P = 4 + 6 + 5 + 7 + 4 = 26 \text{ cm}.P=4+6+5+7+4=26 cm.
Perimeter of a rectangle

P=2L+2WP = 2L + 2WP=2L+2W. So a 6×46 \times 46×4 rectangle has perimeter 2(6+4)=202(6 + 4) = 202(6+4)=20 units.

3. Area of standard shapes

Area measures the amount of surface a shape covers. Units are squared: mm^2, cm^2, m^2, km^2.

Area formulas (Year 7 core)

Rectangle
A=L×W.A = L \times W.A=L×W.
Triangle
A=12×b×h,A = \tfrac{1}{2} \times b \times h,A=21​×b×h,

where bbb is the base and hhh is the perpendicular height from the base to the opposite vertex.

Parallelogram
A=b×h,A = b \times h,A=b×h,

where hhh is the perpendicular height - the same as for a triangle on the same base.

Square (special case of rectangle)
A=s2.A = s^{2}.A=s2.
bhbh
Triangle and parallelogram with base b and perpendicular height h.
Worked example 2 Triangle area

A triangle has base 888 cm and perpendicular height 555 cm. Find its area.

A=12×8×5=20 cm2.A = \tfrac{1}{2} \times 8 \times 5 = 20 \text{ cm}^{2}.A=21​×8×5=20 cm2.
Worked example 3 Parallelogram area

A parallelogram has base 121212 m and perpendicular height 777 m. Find its area.

A=12×7=84 m2.A = 12 \times 7 = 84 \text{ m}^2.A=12×7=84 m2.

4. Circles: parts and the role of pi

rdC
Parts of a circle: centre, radius r, diameter d, circumference C.
  • The centre is the point in the middle.
  • The radius (rrr) is the distance from the centre to any point on the circle.
  • The diameter (ddd) is the distance straight across, through the centre; it equals 2r2r2r.
  • The circumference (CCC) is the total distance around the circle.

Circle relationships

Diameter and radius
d=2r.d = 2r.d=2r.
Circumference in terms of pi
C=π×d  =  2πr.C = \pi \times d \;=\; 2 \pi r.C=π×d=2πr.

The symbol π\piπ (pi) is the constant ratio of circumference to diameter. π≈3.14159≈227\pi \approx 3.14159 \approx \tfrac{22}{7}π≈3.14159≈722​.

What exactly is pi?

If you measure the circumference of any circle and divide by its diameter, you always get the same number - approximately 3.143.143.14. That constant is π\piπ. It’s irrational, so its decimal doesn’t terminate or repeat.

Worked example 4 Circumference from a radius

A circle has radius 555 cm. Find its circumference, using π≈3.14\pi \approx 3.14π≈3.14.

C=2πr=2×3.14×5=31.4 cm.C = 2 \pi r = 2 \times 3.14 \times 5 = 31.4 \text{ cm}.C=2πr=2×3.14×5=31.4 cm.
Worked example 5 Diameter from a circumference

A circle has circumference 444444 m. Find its diameter, using π≈227\pi \approx \tfrac{22}{7}π≈722​.

d=Cπ=44÷227=44×722=14 m.d = \frac{C}{\pi} = 44 \div \frac{22}{7} = 44 \times \frac{7}{22} = 14 \text{ m}.d=πC​=44÷722​=44×227​=14 m.

Practice: Year 7 core

Fluency

Length and perimeter

    1. Convert 250250250 cm to metres.
    2. Convert 3.43.43.4 km to metres.
    3. Convert 858585 mm to cm.
    4. Convert 250025002500 m to km.
    5. Find the perimeter of a rectangle 121212 cm by 777 cm.
    6. Find the perimeter of a square with side 999 cm.
    7. A triangle has sides 555 cm, 777 cm, 999 cm. Find its perimeter.
    8. A regular hexagon has side 444 cm. Find its perimeter.
Fluency

Area of rectangles, triangles, parallelograms

    1. Find the area of a 151515 cm by 444 cm rectangle.
    2. Find the area of a square with side 666 cm.
    3. Find the area of a triangle with base 101010 cm and height 888 cm.
    4. Find the area of a triangle with base 121212 m and height 555 m.
    5. Find the area of a parallelogram with base 999 cm and height 666 cm.
    6. A rectangle has area 484848 cm^2 and length 888 cm. Find its width.
    7. A triangle has area 363636 cm^2 and base 999 cm. Find its height.
    8. A parallelogram has area 606060 m^2 and height 555 m. Find its base.
Fluency

Circles

    Use π≈3.14\pi \approx 3.14π≈3.14 unless another value is given.

    1. A circle has radius 444 cm. Find its diameter.
    2. A circle has diameter 181818 m. Find its radius.
    3. Find the circumference of a circle with radius 101010 cm.
    4. Find the circumference of a circle with diameter 141414 cm, using π≈227\pi \approx \tfrac{22}{7}π≈722​.
    5. A circle has circumference 31.431.431.4 cm. Find its diameter.
    6. True or false: for every circle, circumference ÷\div÷ diameter gives about the same number.
Reasoning

Explain and reason

    1. Two rectangles have the same perimeter. Does it follow that they have the same area? Justify with a numerical example.
    2. Pete writes the area of a triangle with base 666 and slant side 555 as 12×6×5=15\tfrac{1}{2} \times 6 \times 5 = 1521​×6×5=15. Explain what is wrong.
    3. Is it possible for one shape to have a larger perimeter but a smaller area than another? Give an example.
    4. A pizza of diameter 303030 cm is cut exactly in half. What is the perimeter of each half-pizza (the crust plus the straight cut)?
    5. Without calculating, decide which has the larger area: a square with side 101010 cm or a rectangle 121212 cm by 888 cm. Explain.
Problem solving

Real-world problems

    1. A rectangular paddock is 808080 m by 454545 m. What is the cost of fencing it at $18 per metre?
    2. A triangular sail has base 3.53.53.5 m and height 444 m. What is its area in square metres?
    3. A circular garden pond has diameter 3.53.53.5 m. How long is a rope needed to go once around the edge? (Use π≈227\pi \approx \tfrac{22}{7}π≈722​.)
    4. A rectangular garden is 888 m by 121212 m. Convert the area to square centimetres.
    5. A bicycle wheel has diameter 707070 cm. How far (to the nearest metre) does the bike travel in 202020 turns of the wheel? (Use π≈227\pi \approx \tfrac{22}{7}π≈722​.)

Extension

Beyond Year 7 core

Trapezium areas and composite figures formally appear at Year 8 (VC2M8M01). They use the rectangle, triangle, and parallelogram formulas you already know.

More area formulas (extension)

Trapezium
A=12(a+b)×h,A = \tfrac{1}{2}(a + b) \times h,A=21​(a+b)×h,

where aaa and bbb are the parallel sides and hhh is the perpendicular distance between them.

Composite shapes

Break the shape into rectangles and triangles (or start with a big rectangle and subtract the missing piece).

Practice: Extension

Reasoning

Trapezium and composite areas

    1. Find the area of a trapezium with parallel sides 444 cm and 101010 cm and height 333 cm.
    2. Find the area of a trapezium with parallel sides 666 m and 101010 m and height 444 m.
    3. An L-shape is made of an 888 m by 555 m rectangle with a 333 m by 222 m rectangle removed from one corner. Find its area.
    4. A path 111 m wide runs around a 101010 m by 666 m garden, on the outside. Find the area of the path.
    5. A rectangular piece of cardboard is 404040 cm by 303030 cm. A 555 cm square is cut from each corner. What is the remaining area?
Year 7 Mathematics study companion | Practice