Year 7 Mathematics | Victorian Curriculum 2.0
Integers
Topic 01 | Number & Algebra | Answer key

This answer key follows the three sections of the practice: Year 7 core, Extension, and Challenge. Each answer gives the final result and a short method hint where the work is more than one step.

Year 7 core - answers

Fluency

Ordering and absolute value

    1. −10, −7, −2, 0, 3, 5-10,\ -7,\ -2,\ 0,\ 3,\ 5−10, −7, −2, 0, 3, 5
    2. −9-9−9 (further left on the number line)
    3. 131313
    4. 555
    5. True
Fluency

Adding and subtracting

    1. −2-2−2 (start at −6-6−6, jump 444 right)
    2. −13-13−13 (same signs, add the sizes)
    3. −3-3−3 (different signs: 15−12=315 - 12 = 315−12=3, keep the sign of the larger size)
    4. 777
    5. −12-12−12
    6. 333 (minus a minus: −7+10-7 + 10−7+10)
    7. 151515 (minus a minus: 4+114 + 114+11)
    8. 000
    9. −7-7−7
    10. −4-4−4. Method: −2+(−6)=−8-2 + (-6) = -8−2+(−6)=−8; then −8−(−4)=−8+4=−4-8 - (-4) = -8 + 4 = -4−8−(−4)=−8+4=−4.
Reasoning

Fill in the missing number

    1. 555. Method: □=−2−(−7)=5\square = -2 - (-7) = 5□=−2−(−7)=5.
    2. −5-5−5. Method: □=−1−4=−5\square = -1 - 4 = -5□=−1−4=−5.
    3. 777. Method: −5−□=−12-5 - \square = -12−5−□=−12 gives □=−5−(−12)=7\square = -5 - (-12) = 7□=−5−(−12)=7.
    4. 555. Method: □=8+(−3)=5\square = 8 + (-3) = 5□=8+(−3)=5.
Problem solving

Real-world problems

    1. 10 ∘10\,^\circ10∘C. Method: −8+6×3=−8+18-8 + 6 \times 3 = -8 + 18−8+6×3=−8+18.
    2. −133-133−133 m (or 133133133 m below sea level). Method: −120+35−48-120 + 35 - 48−120+35−48.
    3. $37. Method: −45+120−38-45 + 120 - 38−45+120−38.
    4. Floor 111. Method: −3+7−5+2-3 + 7 - 5 + 2−3+7−5+2.
    5. 10 ∘10\,^\circ10∘C rise. Method: 4−(−6)=4+64 - (-6) = 4 + 64−(−6)=4+6.
    6. −15-15−15 m. Method: −24+9=−15-24 + 9 = -15−24+9=−15.

Extension - answers

Fluency

Multiplying and dividing

    1. −42-42−42
    2. 404040 (negative times negative is positive)
    3. −36-36−36
    4. 727272 (two negatives cancel, then multiply)
    5. −8-8−8 (three negatives: odd)
    6. 252525 (two negatives: even)
    7. −4-4−4
    8. 444
    9. −9-9−9
    10. 444
Reasoning

Sign reasoning and missing values

    1. Negative. Reason: there are three negative factors, and three is an odd number, so the product must be negative.
    2. −7-7−7. Method: □=42÷(−6)=−7\square = 42 \div (-6) = -7□=42÷(−6)=−7.
    3. −6-6−6. Method: □=−48÷8=−6\square = -48 \div 8 = -6□=−48÷8=−6.
    4. 333. Method: (−4)×5=−20(-4) \times 5 = -20(−4)×5=−20; the third number satisfies −20×□=−60-20 \times \square = -60−20×□=−60, so □=3\square = 3□=3.

Challenge - answers

How to mark the reasoning

Any explanation that catches the key idea is fine. Sample answers are below.

Reasoning

Harder reasoning

    1. −7-7−7. Method: (−3)3=−27(-3)^3 = -27(−3)3=−27; (−2)2=4(-2)^2 = 4(−2)2=4, so 5×4=205 \times 4 = 205×4=20; then −27+20=−7-27 + 20 = -7−27+20=−7.
    2. >>>. Reason: (−5)2=25(-5)^2 = 25(−5)2=25 and −52=−25-5^2 = -25−52=−25. Since 25>−2525 > -2525>−25, the left side is greater.
    3. Jamie is not correct. The correct answer is −9-9−9. The notation −32-3^2−32 means −(3×3)=−9-(3 \times 3) = -9−(3×3)=−9 (the power applies only to the 333, with the minus sign in front). Jamie has read it as (−3)2=9(-3)^2 = 9(−3)2=9, but without brackets the squaring does not include the negative sign.
    4. n=−2n = -2n=−2. Method: let the number be nnn. Then (2n−7)×(−3)=33(2n - 7) \times (-3) = 33(2n−7)×(−3)=33, so 2n−7=−112n - 7 = -112n−7=−11; 2n=−42n = -42n=−4; n=−2n = -2n=−2. Check: 2(−2)=−42(-2) = -42(−2)=−4; minus 777 gives −11-11−11; times −3-3−3 gives 333333.
Year 7 Mathematics study companion | Answer key