Year 7 Mathematics | Victorian Curriculum 2.0
Squares, roots & exponents
Topic 04 | Number & Algebra | Practice
How this topic is organised

The Year 7 core covers squares and their square roots (VC2M7N01), powers of 10 and prime factorisation using exponent notation (VC2M7N02).

Extension introduces the index laws am×an=am+na^m \times a^n = a^{m+n}am×an=am+n etc.; these formally belong to Year 8 (VC2M8N03) and are included here for students ready to push on.

Start here: powers are a shorthand

Writing 5×5×5×55 \times 5 \times 5 \times 55×5×5×5 gets long. So we write 545^454 — read as “five to the fourth” — meaning “five multiplied by itself four times”.

Squaring is the most common case. 5×55 \times 55×5 is written 525^252 — “five squared”. The word “squared” comes from the fact that a 5×55 \times 55×5 square has area 252525:

3 squared=32=9,4 squared=42=16,7 squared=72=49.3 \text{ squared} = 3^2 = 9, \qquad 4 \text{ squared} = 4^2 = 16, \qquad 7 \text{ squared} = 7^2 = 49.3 squared=32=9,4 squared=42=16,7 squared=72=49.

A square root reverses the squaring. 49\sqrt{49}49​ asks “what number squared gives 494949?” Answer: 777.

Year 7 core

By the end of this topic you should be able to:

  • recognise square numbers and take the square root of a perfect square,
  • solve problems involving squares and square roots,
  • write a natural number as a product of prime factors using exponent notation,
  • use powers of 101010 to write numbers in expanded notation.
Why invent a new notation?

Writing 5×5×5×55 \times 5 \times 5 \times 55×5×5×5 is awkward. Writing 5205^{20}520 without exponent notation would take an entire line. Powers are shorthand — but they are more than shorthand. Once you have the notation, patterns appear (like the index laws) that would be invisible in long-form multiplication. The notation doesn’t just save space; it reveals structure.

Try mentally first

Memorising the first ten squares makes this topic much easier. 1,4,9,16,25,36,49,64,81,1001, 4, 9, 16, 25, 36, 49, 64, 81, 1001,4,9,16,25,36,49,64,81,100. If a number is on this list, its square root is a whole number — you don’t need to calculate.

Worked example 0 Real-world example: tiling a square patio

You buy 363636 square tiles, each 111 m ×\times× 111 m. You want to lay them in a square. How many tiles fit along each side?

6 tiles6 tilesArea = 36 tiles
  1. The area is 363636 tiles (a square number).
  2. Side length =36=6= \sqrt{36} = 6=36​=6.
  3. You lay 666 tiles along each side: 6×6=366 \times 6 = 366×6=36. ✓

Key idea: the square root “undoes” squaring — it takes you from the area back to the side length.

1. Index notation

Index form is shorthand for repeated multiplication. The number being multiplied is the base; the small raised number is the index (or exponent, or power).

5×5×5×5  =  54.5 \times 5 \times 5 \times 5 \;=\; 5^{4}.5×5×5×5=54.

Here 555 is the base and 444 is the index. We read 545^454 as “five to the fourth” or “five to the power of four”.

2. Square numbers

A square number is the result of multiplying a whole number by itself:

12=1,  22=4,  32=9,  42=16,  52=25,  62=36,  72=49,  82=64,  92=81,  102=100.1^2 = 1, \; 2^2 = 4, \; 3^2 = 9, \; 4^2 = 16, \; 5^2 = 25, \; 6^2 = 36, \; 7^2 = 49, \; 8^2 = 64, \; 9^2 = 81, \; 10^2 = 100.12=1,22=4,32=9,42=16,52=25,62=36,72=49,82=64,92=81,102=100.

Square numbers take their name from a visual pattern: 32=93^2 = 932=9 is the number of dots in a 3×33 \times 33×3 square.

3. Square roots of perfect squares

The square root asks “what number, multiplied by itself, gives this value?”

Square root
a  =  bmeansb≥0 and b2=a.\sqrt{a} \;=\; b \quad \text{means} \quad b \geq 0 \text{ and } b^{2} = a.a​=bmeansb≥0 and b2=a.

49=7\sqrt{49} = 749​=7 because 72=497^2 = 4972=49.

Between which two whole numbers?

Most numbers are not perfect squares, so their square root is not a whole number. You can still squeeze it between two known perfect squares: 50\sqrt{50}50​ lies between 49=7\sqrt{49} = 749​=7 and 64=8\sqrt{64} = 864​=8, and is closer to 777 than to 888.

4. Powers of 10 and expanded notation

Powers of 101010 match the place-value columns:

101=10,  102=100,  103=1000,  104=10 000.10^1 = 10, \; 10^2 = 100, \; 10^3 = 1000, \; 10^4 = 10\,000.101=10,102=100,103=1000,104=10000.

Any natural number can be written in expanded notation using these powers:

4528  =  4×103+5×102+2×101+8.4528 \;=\; 4 \times 10^3 + 5 \times 10^2 + 2 \times 10^1 + 8.4528=4×103+5×102+2×101+8.

5. Prime factorisation using exponents

Every natural number greater than 111 can be written as a product of prime factors. When a prime appears more than once, use exponent notation for brevity.

Worked example E Very easy: prime factorise 12

What primes (building-block numbers) multiply to give 121212?

12=2×6=2×2×3.12 = 2 \times 6 = 2 \times 2 \times 3.12=2×6=2×2×3.

Two 222s and one 333. In exponent form: 12=22×312 = 2^2 \times 312=22×3.

Worked example 1 Prime factorise 72

Break 727272 down into primes using a factor tree:

722362182933
Factor tree for 72. At each step, split into two factors until every leaf is prime (circled). Reading the leaves: 72 = 2 × 2 × 2 × 3 × 3.

In exponent form:

72=23×32.72 = 2^3 \times 3^2.72=23×32.
Worked example 2 Squaring a two-digit number using place value

Calculate 24224^2242.

242=(20+4)2=20×20+2×20×4+4×4=400+160+16=576.24^2 = (20 + 4)^2 = 20 \times 20 + 2 \times 20 \times 4 + 4 \times 4 = 400 + 160 + 16 = 576.242=(20+4)2=20×20+2×20×4+4×4=400+160+16=576.

(This uses an area-diagram approach rather than a calculator.)


Practice: Year 7 core

Fluency

Squares and square roots

    1. Evaluate 323^232.
    2. Evaluate 626^262.
    3. Evaluate 12212^2122.
    4. Evaluate 81\sqrt{81}81​.
    5. Evaluate 144\sqrt{144}144​.
    6. Evaluate 400\sqrt{400}400​.
    7. Between which two consecutive whole numbers does 50\sqrt{50}50​ lie?
    8. Between which two consecutive whole numbers does 90\sqrt{90}90​ lie?
    9. Which is bigger: 64\sqrt{64}64​ or 525^252?
    10. Evaluate 25+36\sqrt{25} + \sqrt{36}25​+36​.
Fluency

Powers of 10 and expanded notation

    1. Evaluate 10310^3103.
    2. Evaluate 10510^5105.
    3. Write 342734273427 in expanded notation using powers of 101010.
    4. Write 50 60850\,60850608 in expanded notation using powers of 101010.
    5. Write the number that equals 7×103+2×102+67 \times 10^3 + 2 \times 10^2 + 67×103+2×102+6.
Fluency

Prime factorisation

    1. Write 202020 as a product of primes in exponent form.
    2. Write 363636 as a product of primes in exponent form.
    3. Write 848484 as a product of primes in exponent form.
    4. Write 100100100 as a product of primes in exponent form.
    5. Write 200200200 as a product of primes in exponent form.
Reasoning

Explain and apply

    1. Explain in your own words why 9+16≠9+16\sqrt{9 + 16} \neq \sqrt{9} + \sqrt{16}9+16​=9​+16​.
    2. Without a calculator, decide whether 200\sqrt{200}200​ is closer to 141414 or 151515. Justify.
    3. A square garden bed has an area of 144144144 m^2. What is the length of one side?
    4. Find the highest common factor of 727272 and 120120120 by comparing their prime factorisations.
    5. Find the lowest common multiple of 121212 and 181818 by using prime factorisation.

Extension - index laws

Beyond Year 7 core

The index laws below formally belong to Year 8 (VC2M8N03). They are included here for students who find the patterns easy and want to push on.

Index laws (positive whole-number indices)

Multiplying: add the indices
am×an  =  am+n.Example: 23×25=28.a^m \times a^n \;=\; a^{m+n}. \qquad \text{Example: } 2^3 \times 2^5 = 2^8.am×an=am+n.Example: 23×25=28.
Dividing: subtract the indices
am÷an  =  am−n,a≠0.Example: 57÷53=54.a^m \div a^n \;=\; a^{m-n}, \quad a \neq 0. \qquad \text{Example: } 5^7 \div 5^3 = 5^4.am÷an=am−n,a=0.Example: 57÷53=54.
Power of a power: multiply the indices
(am)n  =  am×n.Example: (32)4=38.(a^m)^n \;=\; a^{m \times n}. \qquad \text{Example: } (3^2)^4 = 3^8.(am)n=am×n.Example: (32)4=38.
Common mistake: squaring vs doubling

525^252 is not 101010. Squaring means multiplying by itself (so 5×5=255 \times 5 = 255×5=25). Doubling would be 2×5=102 \times 5 = 102×5=10. Students confuse these because they look similar; say the word “squared” aloud while writing it to lock the idea in.

Laws need the same base

23×322^3 \times 3^223×32 cannot be simplified with the index laws, because the bases (222 and 333) are different. Just evaluate: 8×9=728 \times 9 = 728×9=72.

Practice: Extension

Fluency

Using the index laws

    1. Simplify 24×252^4 \times 2^524×25.
    2. Simplify a6×a2a^6 \times a^2a6×a2.
    3. Simplify 510÷545^{10} \div 5^4510÷54.
    4. Simplify x7÷x3x^7 \div x^3x7÷x3.
    5. Simplify (32)3(3^2)^3(32)3.
    6. Simplify (m4)5(m^4)^5(m4)5.
    7. Simplify y10y4\dfrac{y^{10}}{y^4}y4y10​.
    8. Simplify m6×m3m5\dfrac{m^6 \times m^3}{m^5}m5m6×m3​.
Reasoning

Spot the mistake

    1. Tim writes 23+23=262^3 + 2^3 = 2^623+23=26. Is Tim correct? If not, what has gone wrong?
    2. Leah writes (a2)3=a5(a^2)^3 = a^5(a2)3=a5. Explain Leah’s error and give the correct simplification.
    3. Simplify p2q3×p4qp3q2\dfrac{p^2 q^3 \times p^4 q}{p^3 q^2}p3q2p2q3×p4q​.
    4. A bacterium doubles every hour. Starting from one cell, how many cells are there after 666 hours? Write the answer as a power of 222.
Year 7 Mathematics study companion | Practice