Matrix reasoning (3x3 grids)

Each answer shows the rule (row, column, or both) that fits the two complete rows, then the value.

Timed drill

(b) 9. Each row counts up by 1: $7, 8, 9$ .
(b) 13. Right $=$ left $+$ middle. $6 + 7 = 13$ .
(c) 10. Right $=$ left $\times$ middle. $2 \times 5 = 10$ .
(c) 5. Right $=$ left $-$ middle. $9 - 4 = 5$ .
(c) 16. Each row doubles. $4, 8, 16$ .
(c) 11. Each column goes up by $1$ : column 3 reads $9, 10, 11$ .
(b) 10. Each row has gap $+2$ . $6, 8, 10$ .
(b) 6. Row 3 has gap $-6$ : $18, 12, 6$ .
(c) 10. Right $=$ left $\times$ middle. $5 \times 2 = 10$ .
(c) 10. Right $=$ left $\times$ middle. $5 \times 2 = 10$ .
(c) 12. Right $=$ left $+$ middle. $8 + 4 = 12$ .
(b) 4. Right $=$ left $-$ middle. $12 - 8 = 4$ .
(b) 6. Each column increases by $1$ going down: column 3 reads $4, 5, 6$ .
(a) 2. Right $=$ left $\div$ middle. $30 \div 15 = 2$ .
(b) 8. Right $=$ left $+$ middle. $3 + 5 = 8$ .
(c) 13. Right $=$ left $+$ middle. $8 + 5 = 13$ .
(b) 7. Middle $= \sqrt{\text{left}}$ , and right equals middle. $\sqrt{49} = 7$ .
(c) 4. Right $=$ middle $-$ left. $10 - 6 = 4$ .
(d) 48. Right $=$ left $\times$ middle. $4 \times 12 = 48$ .
(c) 11. Each column goes up by $1$ : column 3 reads $9, 10, 11$ .