Year 7 Mathematics | Practice mode

Practice

538 questions across 15 topics, drawn from every Practice and Challenge block in Year 7 mathematics. Filter by topic or level, cap the count, shuffle, and start the timer when you want to time a session.

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Showing all 538 questions.

Integers

Fluency · Ordering and absolute value

  1. 1. Order from smallest to largest:   7, 3, 0, 2, 10, 5\;-7,\ 3,\ 0,\ -2,\ -10,\ 5. (show answer)
    Answer
    10, 7, 2, 0, 3, 5-10,\ -7,\ -2,\ 0,\ 3,\ 5
  2. 2. Which is smaller: 4-4 or 9-9? (show answer)
    Answer
    9-9 (further left on the number line)
  3. 3. Evaluate 13|{-13}|. (show answer)
    Answer
    1313
  4. 4. Evaluate 94|9| - |{-4}|. (show answer)
    Answer
    55
  5. 5. True or false: 6=6|{-6}| = 6. (show answer)
    Answer
    True

Fluency · Adding and subtracting

  1. 1. Work out   6+4\;-6 + 4. (show answer)
    Answer
    2-2 (start at 6-6, jump 44 right)
  2. 2. Work out   5+(8)\;-5 + (-8). (show answer)
    Answer
    13-13 (same signs, add the sizes)
  3. 3. Work out   12+(15)\;12 + (-15). (show answer)
    Answer
    3-3 (different signs: 1512=315 - 12 = 3, keep the sign of the larger size)
  4. 4. Work out   3+10\;-3 + 10. (show answer)
    Answer
    77
  5. 5. Work out   93\;-9 - 3. (show answer)
    Answer
    12-12
  6. 6. Work out   7(10)\;-7 - (-10). (show answer)
    Answer
    33 (minus a minus: 7+10-7 + 10)
  7. 7. Work out   4(11)\;4 - (-11). (show answer)
    Answer
    1515 (minus a minus: 4+114 + 11)
  8. 8. Work out   20(20)\;-20 - (-20). (show answer)
    Answer
    00
  9. 9. Work out   07\;0 - 7. (show answer)
    Answer
    7-7
  10. 10. Work out   2+(6)(4)\;-2 + (-6) - (-4). (show answer)
    Answer
    4-4. Method: 2+(6)=8-2 + (-6) = -8; then 8(4)=8+4=4-8 - (-4) = -8 + 4 = -4.

Reasoning · Fill in the missing number

  1. 1.   7+=2\;-7 + \square = -2. (show answer)
    Answer
    55. Method: =2(7)=5\square = -2 - (-7) = 5.
  2. 2.   +4=1\;\square + 4 = -1. (show answer)
    Answer
    5-5. Method: =14=5\square = -1 - 4 = -5.
  3. 3.   5=12\;-5 - \square = -12. (show answer)
    Answer
    77. Method: 5=12-5 - \square = -12 gives =5(12)=7\square = -5 - (-12) = 7.
  4. 4.   (3)=8\;\square - (-3) = 8. (show answer)
    Answer
    55. Method: =8+(3)=5\square = 8 + (-3) = 5.

Problem-solving · Real-world problems

  1. 1. The temperature on Mount Hotham was 8-8\,^\circC at midnight. It rose by 33\,^\circC each hour until 66 a.m. What was the temperature at 66 a.m.? (show answer)
    Answer
    1010\,^\circC. Method: 8+6×3=8+18-8 + 6 \times 3 = -8 + 18.
  2. 2. A submarine is 120120 m below sea level. It ascends 3535 m, then descends 4848 m. What is its new depth, written as an integer? (show answer)
    Answer
    133-133 m (or 133133 m below sea level). Method: 120+3548-120 + 35 - 48.
  3. 3. Mira has a bank balance of -$45 (an overdraft). She deposits $120 and then pays a bill of $38. What is her balance now? (show answer)
    Answer
    $37. Method: 45+12038-45 + 120 - 38.
  4. 4. A lift is on floor 3-3 (basement level 3). It goes up 77 floors, then down 55, then up 22. On which floor does it stop? (show answer)
    Answer
    Floor 11. Method: 3+75+2-3 + 7 - 5 + 2.
  5. 5. At dawn the temperature in Cooma was 6-6\,^\circC. By mid-morning it had risen to 44\,^\circC. By how many degrees did the temperature rise? (show answer)
    Answer
    1010\,^\circC rise. Method: 4(6)=4+64 - (-6) = 4 + 6.
  6. 6. A diver starts at sea level (00) and descends to 24-24 m, then rises 99 m to look at a reef. What is her depth now? (show answer)
    Answer
    15-15 m. Method: 24+9=15-24 + 9 = -15.

Fluency · Multiplying and dividing

  1. 1. Work out   (6)×7\;(-6) \times 7. (show answer)
    Answer
    42-42
  2. 2. Work out   (8)×(5)\;(-8) \times (-5). (show answer)
    Answer
    4040 (negative times negative is positive)
  3. 3. Work out   9×(4)\;9 \times (-4). (show answer)
    Answer
    36-36
  4. 4. Work out   (12)×(3)×2\;(-12) \times (-3) \times 2. (show answer)
    Answer
    7272 (two negatives cancel, then multiply)
  5. 5. Work out   (2)3\;(-2)^3. (show answer)
    Answer
    8-8 (three negatives: odd)
  6. 6. Work out   (5)2\;(-5)^2. (show answer)
    Answer
    2525 (two negatives: even)
  7. 7. Work out   24÷6\;-24 \div 6. (show answer)
    Answer
    4-4
  8. 8. Work out   (36)÷(9)\;(-36) \div (-9). (show answer)
    Answer
    44
  9. 9. Work out   45÷(5)\;45 \div (-5). (show answer)
    Answer
    9-9
  10. 10. Work out   (100)÷(25)\;(-100) \div (-25). (show answer)
    Answer
    44

Reasoning · Sign reasoning and missing values

  1. 1. Without calculating, decide whether (17)×(23)×(4)(-17) \times (-23) \times (-4) is positive or negative. Explain how you know. (show answer)
    Answer
    Negative. Reason: there are three negative factors, and three is an odd number, so the product must be negative.
  2. 2. Fill in:   ×(6)=42\;\square \times (-6) = 42. (show answer)
    Answer
    7-7. Method: =42÷(6)=7\square = 42 \div (-6) = -7.
  3. 3. Fill in:   (48)÷=8\;(-48) \div \square = 8. (show answer)
    Answer
    6-6. Method: =48÷8=6\square = -48 \div 8 = -6.
  4. 4. The product of three integers is 60-60. Two of them are 4-4 and 55. What is the third? (show answer)
    Answer
    33. Method: (4)×5=20(-4) \times 5 = -20; the third number satisfies 20×=60-20 \times \square = -60, so =3\square = 3.

Reasoning · Harder reasoning

  1. 1. Evaluate   (3)3+5×(2)2\;(-3)^3 + 5 \times (-2)^2. (show answer)
    Answer
    7-7. Method: (3)3=27(-3)^3 = -27; (2)2=4(-2)^2 = 4, so 5×4=205 \times 4 = 20; then 27+20=7-27 + 20 = -7.
  2. 2. Place <<, >> or == between the pair:   (5)2    52\;(-5)^2 \;\square\; -5^2. Justify your answer. (show answer)
    Answer
    >>. Reason: (5)2=25(-5)^2 = 25 and 52=25-5^2 = -25. Since 25>2525 > -25, the left side is greater.
  3. 3. Jamie writes "32=9-3^2 = 9". Is Jamie correct? If not, what is the right answer and what mistake has Jamie made? (show answer)
    Answer
    Jamie is not correct. The correct answer is 9-9. The notation 32-3^2 means (3×3)=9-(3 \times 3) = -9 (the power applies only to the 33, with the minus sign in front). Jamie has read it as (3)2=9(-3)^2 = 9, but without brackets the squaring does not include the negative sign.
  4. 4. Tom thinks of an integer. He doubles it, subtracts 77, then multiplies by 3-3. The result is 3333. What integer was Tom thinking of? (show answer)
    Answer
    n=2n = -2. Method: let the number be nn. Then (2n7)×(3)=33(2n - 7) \times (-3) = 33, so 2n7=112n - 7 = -11; 2n=42n = -4; n=2n = -2. Check: 2(2)=42(-2) = -4; minus 77 gives 11-11; times 3-3 gives 3333.

Fractions, decimals & percentages

Fluency · Tier 1: basic skills

  1. 1. Simplify 1824\dfrac{18}{24}. (show answer)
    Answer
    34\dfrac{3}{4}
  2. 2. Simplify 3660\dfrac{36}{60}. (show answer)
    Answer
    35\dfrac{3}{5}
  3. 3. Write 38\dfrac{3}{8} as a decimal. (show answer)
    Answer
    0.3750.375
  4. 4. Write 720\dfrac{7}{20} as a decimal. (show answer)
    Answer
    0.350.35
  5. 5. Write 0.450.45 as a simplified fraction. (show answer)
    Answer
    920\dfrac{9}{20}
  6. 6. Write 1.251.25 as a mixed number. (show answer)
    Answer
    1141\dfrac{1}{4}
  7. 7. Convert 0.60.6 to a percentage. (show answer)
    Answer
    60%60\%
  8. 8. Convert 82%82\% to a decimal. (show answer)
    Answer
    0.820.82
  9. 9. Convert 35%35\% to a simplified fraction. (show answer)
    Answer
    720\dfrac{7}{20}
  10. 10. Which is bigger: 35\dfrac{3}{5} or 710\dfrac{7}{10}? (show answer)
    Answer
    710\dfrac{7}{10} is bigger
  11. 11. Evaluate 12+13\dfrac{1}{2} + \dfrac{1}{3}. (show answer)
    Answer
    56\dfrac{5}{6}
  12. 12. Evaluate 5614\dfrac{5}{6} - \dfrac{1}{4}. (show answer)
    Answer
    712\dfrac{7}{12}
  13. 13. Evaluate 23×910\dfrac{2}{3} \times \dfrac{9}{10}. (show answer)
    Answer
    35\dfrac{3}{5}
  14. 14. Evaluate 45÷23\dfrac{4}{5} \div \dfrac{2}{3}. (show answer)
    Answer
    65\dfrac{6}{5} or 1151\dfrac{1}{5}
  15. 15. Find 20%20\% of $75. (show answer)
    Answer
    $15
  16. 16. Find 15%15\% of 6060. (show answer)
    Answer
    99
  17. 17. Find 7%7\% of $200. (show answer)
    Answer
    $14
  18. 18. Increase 8080 by 25%25\%. (show answer)
    Answer
    100100
  19. 19. Decrease $120 by 10%10\%. (show answer)
    Answer
    $108
  20. 20. Write 58\dfrac{5}{8} as a percentage. (show answer)
    Answer
    62.5%62.5\%

Fluency · Rounding and number line

  1. 1. Round 4.7624.762 to the nearest whole number. (show answer)
    Answer
    55 (because 0.7620.50.762 \geq 0.5).
  2. 2. Round 12.3812.38 to 11 decimal place. (show answer)
    Answer
    12.412.4 (because the hundredths digit is 88).
  3. 3. Round 0.04580.0458 to 22 decimal places. (show answer)
    Answer
    0.050.05 (because the thousandths digit is 55).
  4. 4. Round $18.739 to the nearest cent. (show answer)
    Answer
    $18.74.
  5. 5. Which is smaller: 23-\dfrac{2}{3} or 13-\dfrac{1}{3}? (show answer)
    Answer
    23-\dfrac{2}{3} is smaller. It sits further to the left of zero on the number line.
  6. 6. Place these on a number line (in order): 1.5, 34, 0, 0.25, 32-1.5,\ -\dfrac{3}{4},\ 0,\ 0.25,\ \dfrac{3}{2}. (show answer)
    Answer
    1.5, 34, 0, 0.25, 32-1.5,\ -\dfrac{3}{4},\ 0,\ 0.25,\ \dfrac{3}{2} - already in order.
  7. 7. Find two rational numbers between 0.5-0.5 and 00. (show answer)
    Answer
    Many answers. Examples: 0.25-0.25, 14-\dfrac{1}{4}, 13-\dfrac{1}{3}.

Reasoning · Tier 2: mixed practice

  1. 1. Order from smallest to largest:   0.7, 23, 68%, 710\;0.7,\ \dfrac{2}{3},\ 68\%,\ \dfrac{7}{10}. (show answer)
    Answer
    23, 0.68(68%), 0.7, 710\dfrac{2}{3},\ 0.68\,(68\%),\ 0.7,\ \dfrac{7}{10}. Note 710=0.70=0.7\dfrac{7}{10} = 0.70 = 0.7, so these are equal. Correct order: 23, 68%, 0.7=710\dfrac{2}{3},\ 68\%,\ 0.7 = \dfrac{7}{10}.
  2. 2. Evaluate 23+3412\dfrac{2}{3} + \dfrac{3}{4} - \dfrac{1}{2}. (show answer)
    Answer
    1112\dfrac{11}{12}. Method: common denominator 1212; 812+912612=1112\dfrac{8}{12} + \dfrac{9}{12} - \dfrac{6}{12} = \dfrac{11}{12}.
  3. 3. Evaluate (12)2+14\left(\dfrac{1}{2}\right)^2 + \dfrac{1}{4}. (show answer)
    Answer
    12\dfrac{1}{2}. Method: 14+14=24\dfrac{1}{4} + \dfrac{1}{4} = \dfrac{2}{4}.
  4. 4. A recipe uses 34\dfrac{3}{4} cup of sugar. You want to make 23\dfrac{2}{3} of the recipe. How much sugar do you need? (show answer)
    Answer
    12\dfrac{1}{2} cup. Method: 23×34=12\dfrac{2}{3} \times \dfrac{3}{4} = \dfrac{1}{2}.
  5. 5. Fill in the missing number: 12=34\dfrac{\square}{12} = \dfrac{3}{4}. (show answer)
    Answer
    99. Method: 912=34\dfrac{9}{12} = \dfrac{3}{4}.
  6. 6. What percentage is 1818 out of 4040? (show answer)
    Answer
    45%45\%. Method: 1840×100\dfrac{18}{40} \times 100.
  7. 7. What percentage is 2727 out of 6060? (show answer)
    Answer
    45%45\%. Method: 2760×100\dfrac{27}{60} \times 100.
  8. 8. A jacket costs $85 and is reduced by 20%20\%. What is the new price? (show answer)
    Answer
    $68. Method: 85×0.80=6885 \times 0.80 = 68.
  9. 9. A bike costs $320 and its price rises by 5%5\%. What is the new price? (show answer)
    Answer
    $336. Method: 320×1.05=336320 \times 1.05 = 336.
  10. 10. A number increased by 40%40\% gives 8484. What was the original number? (show answer)
    Answer
    6060. Method: x×1.40=84x \times 1.40 = 84, so x=84÷1.40x = 84 \div 1.40.
  11. 11. Work out 34\dfrac{3}{4} of 25\dfrac{2}{5} of 120120. (show answer)
    Answer
    3636. Method: 25×120=48\dfrac{2}{5} \times 120 = 48, then 34×48=36\dfrac{3}{4} \times 48 = 36.
  12. 12. Evaluate 138141 - \dfrac{3}{8} - \dfrac{1}{4}. (show answer)
    Answer
    38\dfrac{3}{8}. Method: 883828\dfrac{8}{8} - \dfrac{3}{8} - \dfrac{2}{8}.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. Sam says "12+13=25\dfrac{1}{2} + \dfrac{1}{3} = \dfrac{2}{5}" because he added the tops and the bottoms. Is Sam correct? If not, what is the correct answer and what mistake has Sam made? (show answer)
    Answer
    Sam is wrong. The correct answer is 56\dfrac{5}{6}. Fractions must share a denominator before you can add them: 12=36\dfrac{1}{2} = \dfrac{3}{6} and 13=26\dfrac{1}{3} = \dfrac{2}{6}, so 36+26=56\dfrac{3}{6} + \dfrac{2}{6} = \dfrac{5}{6}. You cannot add the tops and bottoms separately.
  2. 2. Explain why dividing by 12\dfrac{1}{2} is the same as multiplying by 22. (show answer)
    Answer
    Dividing by a fraction means multiplying by its reciprocal. The reciprocal of 12\dfrac{1}{2} is 22, so n÷12=n×2n \div \dfrac{1}{2} = n \times 2. Concretely, asking "how many halves fit in nn?" gives twice as many as whole units, i.e. 2n2n.
  3. 3. A shop advertises "50%50\% off then another 20%20\% off". Is this the same as 70%70\% off? Explain with a worked example using $100. (show answer)
    Answer
    Not the same. Starting from $100: 50%50\% off gives $50; then 20%20\% off $50 gives $40. A flat 70%70\% off $100 would leave $30. Because percentages compound on the new running total, the combined discount here is only 60%60\%.
  4. 4. Without calculating exactly, decide whether 713\dfrac{7}{13} is greater than 12\dfrac{1}{2}. Explain your reasoning. (show answer)
    Answer
    Yes, 713\dfrac{7}{13} is greater than 12\dfrac{1}{2}. Half of 1313 is 6.56.5, and 7>6.57 > 6.5, so seven thirteenths is more than half.
  5. 5. Is 0.30.3 equal to 310\dfrac{3}{10} or 13\dfrac{1}{3}? Explain the difference. (show answer)
    Answer
    0.3=3100.3 = \dfrac{3}{10}, not 13\dfrac{1}{3}. The fraction 13=0.333\dfrac{1}{3} = 0.333\ldots (the 33s repeat forever), so 0.30.3 is slightly less than 13\dfrac{1}{3}.

Problem-solving · Tier 4: real-world problems

  1. 1. Zara's phone bill is $65 per month. The company raises prices by 8%8\%. What will her new bill be? (show answer)
    Answer
    $70.20. Method: 65×1.0865 \times 1.08.
  2. 2. A pizza is cut into 88 equal slices. Tom eats 33 slices, Mia eats 22 slices. What fraction of the pizza is left? (show answer)
    Answer
    38\dfrac{3}{8}. Method: 1581 - \dfrac{5}{8}.
  3. 3. In a class of 3030 students, 1818 walk to school. What percentage walk to school? What percentage do not? (show answer)
    Answer
    60%60\% walk; 40%40\% do not. Method: 1830×100=60\dfrac{18}{30} \times 100 = 60.
  4. 4. A $240 pair of headphones is on sale for $180. What is the percentage discount? (show answer)
    Answer
    25%25\% off. Method: discount $60; 60240×100\dfrac{60}{240} \times 100.
  5. 5. Mia saves 15\dfrac{1}{5} of her $25 pocket money each week. How much has she saved after 88 weeks? (show answer)
    Answer
    $40. Method: 15×25=5\dfrac{1}{5} \times 25 = 5 per week; ×8\times 8.
  6. 6. A water tank is 34\dfrac{3}{4} full. 120120 litres are used, leaving the tank 12\dfrac{1}{2} full. What is the capacity of the tank? (show answer)
    Answer
    480480 litres. Method: 3412=14\dfrac{3}{4} - \dfrac{1}{2} = \dfrac{1}{4} of the tank is 120120 L, so full tank is 4×1204 \times 120.
  7. 7. A shirt's price was marked up by 20%20\% to $42. What was the original price? (show answer)
    Answer
    $35. Method: x×1.20=42x \times 1.20 = 42, so x=42÷1.20x = 42 \div 1.20.
  8. 8. Last year a school had 750750 students. This year enrolment has risen by 12%12\%. How many students are enrolled now? (show answer)
    Answer
    840840 students. Method: 750×1.12750 \times 1.12.

Ratios

Fluency · Simplify and find missing parts

  1. 1. Simplify the ratio 12:1812 : 18. (show answer)
    Answer
    2:32 : 3
  2. 2. Simplify the ratio 35:1435 : 14. (show answer)
    Answer
    5:25 : 2
  3. 3. Simplify the ratio 40:60:10040 : 60 : 100. (show answer)
    Answer
    2:3:52 : 3 : 5
  4. 4. Write 250250 g : 11 kg as a simplified ratio. (show answer)
    Answer
    1:41 : 4. Method: convert both to grams, 250:1000250 : 1000; divide by 250250.
  5. 5. Write 4545 minutes : 22 hours as a simplified ratio. (show answer)
    Answer
    3:83 : 8. Method: 45:12045 : 120; divide by 1515.
  6. 6. Find the missing number: 3:5=12:3 : 5 = 12 : \square. (show answer)
    Answer
    2020
  7. 7. Find the missing number: :8=15:10\square : 8 = 15 : 10. (show answer)
    Answer
    1212
  8. 8. Find the missing number: 2:3=:182 : 3 = \square : 18. (show answer)
    Answer
    1212. Method: 2×6=122 \times 6 = 12, since 3×6=183 \times 6 = 18.

Fluency · Dividing a quantity in a ratio

  1. 1. Divide $40 in the ratio 3:53 : 5. (show answer)
    Answer
    $15 : $25
  2. 2. Divide $72 in the ratio 2:72 : 7. (show answer)
    Answer
    $16 : $56
  3. 3. Divide 4848 sweets in the ratio 1:2:31 : 2 : 3. (show answer)
    Answer
    8, 16, 248,\ 16,\ 24 sweets. Method: 1+2+3=61 + 2 + 3 = 6 parts; each part =8= 8.
  4. 4. A recipe uses flour and sugar in the ratio 5:25 : 2. If there are 350350 g of flour, how much sugar is used? (show answer)
    Answer
    140140 g. Method: flour is 55 parts, so 11 part =70= 70 g; sugar =2×70= 2 \times 70.
  5. 5. Two numbers are in the ratio 4:54 : 5 and their sum is 9090. Find the numbers. (show answer)
    Answer
    4040 and 5050. Method: 4+5=94 + 5 = 9 parts; each part =90÷9=10= 90 \div 9 = 10.
  6. 6. A 3:23 : 2 ratio of boys to girls in a class of 3030 gives how many of each? (show answer)
    Answer
    1818 boys, 1212 girls. Method: 3+2=53 + 2 = 5 parts; each =6= 6.

Reasoning · Explain and spot the mistake

  1. 1. Ben says "the ratio 4:64 : 6 is the same as 46\dfrac{4}{6}, which is the same as the percentage 66.67%66.67\% of boys". Explain what is right and what is confused in Ben's statement. (show answer)
    Answer
    A ratio of 4:64 : 6 compares one group to the other, not to the whole. To find "what fraction of the total is boys" you need boys over total: 44+6=410=40%\dfrac{4}{4 + 6} = \dfrac{4}{10} = 40\%. Ben wrote 4666.67%\dfrac{4}{6} \approx 66.67\%, which is the ratio of boys to girls, not boys to total.
  2. 2. A drink is made from concentrate and water in the ratio 1:41 : 4. Jen says "14\dfrac{1}{4} of the drink is concentrate, which is 25%25\%". What has Jen mixed up, and what is the correct percentage? (show answer)
    Answer
    In a 1:41 : 4 ratio the parts are 11 concentrate plus 44 water, giving 55 parts total. So concentrate is 15=20%\dfrac{1}{5} = 20\% of the drink, not 14=25%\dfrac{1}{4} = 25\%. Jen forgot to add the parts to find the total.
  3. 3. Explain why the ratio 6:96 : 9 is equivalent to 2:32 : 3, but is not equivalent to 2:52 : 5. (show answer)
    Answer
    Dividing both 66 and 99 by 33 gives 2:32 : 3, so the parts scale down by the same factor. For 2:52 : 5 the same multiplier would need to take 262 \to 6 and 595 \to 9, but 2×3=62 \times 3 = 6 while 5×3=1595 \times 3 = 15 \neq 9. The proportion doesn't match, so 6:92:56 : 9 \neq 2 : 5.
  4. 4. Two gears have 2424 and 3636 teeth. Write the gear ratio in simplest form and explain what the ratio means in plain words. (show answer)
    Answer
    24:36=2:324 : 36 = 2 : 3. In plain words: for every 22 turns of the first gear, the second gear makes 33 turns (or equivalently, the first gear turns 1.51.5 times faster than the second).

Problem-solving · Real-world problems

  1. 1. A cake recipe makes 1212 cupcakes and uses 300300 g flour, 180180 g sugar and 44 eggs. How much of each is needed for 3030 cupcakes? (show answer)
    Answer
    Flour 750750 g, sugar 450450 g, eggs 1010. Method: scale factor =30÷12=2.5= 30 \div 12 = 2.5.
  2. 2. A map has scale 1:250001 : 25\,000. Two towns are 88 cm apart on the map. How many kilometres apart are they in reality? (show answer)
    Answer
    22 km. Method: 8×25000=2000008 \times 25\,000 = 200\,000 cm =2= 2 km.
  3. 3. Two friends share a $150 phone bill in the ratio of their usage. Anna used the phone for 180180 minutes, Ben for 120120 minutes. How much should each pay? (show answer)
    Answer
    Anna $90, Ben $60. Method: ratio 180:120=3:2180 : 120 = 3 : 2; 55 parts = $150; each part = $30.
  4. 4. A rectangular garden has length and width in the ratio 5:35 : 3. If its perimeter is 4848 m, find its length and width. (show answer)
    Answer
    Length 1515 m, width 99 m. Method: 5+3=85 + 3 = 8 parts; total length-plus-width (half of perimeter) =24= 24 m, so 11 part =3= 3 m.
  5. 5. A school of 480480 students is split into three houses in the ratio 3:4:53 : 4 : 5. How many students are in each house? (show answer)
    Answer
    120, 160, 200120,\ 160,\ 200. Method: 3+4+5=123 + 4 + 5 = 12 parts; each part =480÷12=40= 480 \div 12 = 40.
  6. 6. Paint is mixed from white and red in the ratio 7:37 : 3. How much red paint is needed to make 55 litres of mixed paint? (show answer)
    Answer
    1.51.5 L red. Method: 7+3=107 + 3 = 10 parts; each part =0.5= 0.5 L; red =3= 3 parts.

Squares, roots & exponents

Fluency · Squares and square roots

  1. 1. Evaluate 323^2. (show answer)
    Answer
    99
  2. 2. Evaluate 626^2. (show answer)
    Answer
    3636
  3. 3. Evaluate 12212^2. (show answer)
    Answer
    144144
  4. 4. Evaluate 81\sqrt{81}. (show answer)
    Answer
    99
  5. 5. Evaluate 144\sqrt{144}. (show answer)
    Answer
    1212
  6. 6. Evaluate 400\sqrt{400}. (show answer)
    Answer
    2020
  7. 7. Between which two consecutive whole numbers does 50\sqrt{50} lie? (show answer)
    Answer
    Between 77 and 88
  8. 8. Between which two consecutive whole numbers does 90\sqrt{90} lie? (show answer)
    Answer
    Between 99 and 1010
  9. 9. Which is bigger: 64\sqrt{64} or 525^2? (show answer)
    Answer
    52=255^2 = 25 is bigger than 64=8\sqrt{64} = 8
  10. 10. Evaluate 25+36\sqrt{25} + \sqrt{36}. (show answer)
    Answer
    1111. Method: 5+65 + 6.

Fluency · Powers of 10 and expanded notation

  1. 1. Evaluate 10310^3. (show answer)
    Answer
    10001000
  2. 2. Evaluate 10510^5. (show answer)
    Answer
    100000100\,000
  3. 3. Write 34273427 in expanded notation using powers of 1010. (show answer)
    Answer
    3×103+4×102+2×10+73 \times 10^3 + 4 \times 10^2 + 2 \times 10 + 7
  4. 4. Write 5060850\,608 in expanded notation using powers of 1010. (show answer)
    Answer
    5×104+6×102+85 \times 10^4 + 6 \times 10^2 + 8
  5. 5. Write the number that equals 7×103+2×102+67 \times 10^3 + 2 \times 10^2 + 6. (show answer)
    Answer
    72067206

Fluency · Prime factorisation

  1. 1. Write 2020 as a product of primes in exponent form. (show answer)
    Answer
    22×52^2 \times 5
  2. 2. Write 3636 as a product of primes in exponent form. (show answer)
    Answer
    22×322^2 \times 3^2
  3. 3. Write 8484 as a product of primes in exponent form. (show answer)
    Answer
    22×3×72^2 \times 3 \times 7
  4. 4. Write 100100 as a product of primes in exponent form. (show answer)
    Answer
    22×522^2 \times 5^2
  5. 5. Write 200200 as a product of primes in exponent form. (show answer)
    Answer
    23×522^3 \times 5^2

Reasoning · Explain and apply

  1. 1. Explain in your own words why 9+169+16\sqrt{9 + 16} \neq \sqrt{9} + \sqrt{16}. (show answer)
    Answer
    Square root does not distribute over addition. Left side: 9+16=25=5\sqrt{9 + 16} = \sqrt{25} = 5. Right side: 9+16=3+4=7\sqrt{9} + \sqrt{16} = 3 + 4 = 7. Since 575 \neq 7, you must add first and then take the root.
  2. 2. Without a calculator, decide whether 200\sqrt{200} is closer to 1414 or 1515. Justify. (show answer)
    Answer
    142=19614^2 = 196 and 152=22515^2 = 225. Since 200200 is only 44 above 196196 but 2525 below 225225, 200\sqrt{200} is much closer to 1414 (about 14.1414.14).
  3. 3. A square garden bed has an area of 144144 m^2. What is the length of one side? (show answer)
    Answer
    1212 m. Method: side length =144= \sqrt{144}.
  4. 4. Find the highest common factor of 7272 and 120120 by comparing their prime factorisations. (show answer)
    Answer
    HCF =24= 24. Method: 72=23×3272 = 2^3 \times 3^2 and 120=23×3×5120 = 2^3 \times 3 \times 5; take the lowest power of each shared prime: 23×3=242^3 \times 3 = 24.
  5. 5. Find the lowest common multiple of 1212 and 1818 by using prime factorisation. (show answer)
    Answer
    LCM =36= 36. Method: 12=22×312 = 2^2 \times 3 and 18=2×3218 = 2 \times 3^2; take the highest power of each prime: 22×32=362^2 \times 3^2 = 36.

Fluency · Using the index laws

  1. 1. Simplify 24×252^4 \times 2^5. (show answer)
    Answer
    292^9
  2. 2. Simplify a6×a2a^6 \times a^2. (show answer)
    Answer
    a8a^8
  3. 3. Simplify 510÷545^{10} \div 5^4. (show answer)
    Answer
    565^6
  4. 4. Simplify x7÷x3x^7 \div x^3. (show answer)
    Answer
    x4x^4
  5. 5. Simplify (32)3(3^2)^3. (show answer)
    Answer
    363^6 (which equals 729729)
  6. 6. Simplify (m4)5(m^4)^5. (show answer)
    Answer
    m20m^{20}
  7. 7. Simplify y10y4\dfrac{y^{10}}{y^4}. (show answer)
    Answer
    y6y^6. Method: subtract indices 10410 - 4.
  8. 8. Simplify m6×m3m5\dfrac{m^6 \times m^3}{m^5}. (show answer)
    Answer
    m4m^4. Method: top m9m^9; m9÷m5=m4m^9 \div m^5 = m^4.

Reasoning · Spot the mistake

  1. 1. Tim writes 23+23=262^3 + 2^3 = 2^6. Is Tim correct? If not, what has gone wrong? (show answer)
    Answer
    Tim is wrong. 23+23=8+8=16=242^3 + 2^3 = 8 + 8 = 16 = 2^4, not 262^6. The index law for multiplying powers adds the indices, but this is addition of two equal powers - it doubles the value, increasing the index by 11 (not doubling it).
  2. 2. Leah writes (a2)3=a5(a^2)^3 = a^5. Explain Leah's error and give the correct simplification. (show answer)
    Answer
    Leah is wrong. The rule (am)n(a^m)^n multiplies the indices, not adds: (a2)3=a2×3=a6(a^2)^3 = a^{2 \times 3} = a^6.
  3. 3. Simplify p2q3×p4qp3q2\dfrac{p^2 q^3 \times p^4 q}{p^3 q^2}. (show answer)
    Answer
    p3q2p^3 q^2. Method: numerator =p2+4q3+1=p6q4= p^{2 + 4} q^{3 + 1} = p^6 q^4; dividing by p3q2p^3 q^2 gives p63q42=p3q2p^{6 - 3} q^{4 - 2} = p^3 q^2.
  4. 4. A bacterium doubles every hour. Starting from one cell, how many cells are there after 66 hours? Write the answer as a power of 22. (show answer)
    Answer
    26=642^6 = 64 cells. Method: doubling 66 times from 11 gives 12481632641 \to 2 \to 4 \to 8 \to 16 \to 32 \to 64.

Algebraic expressions

Fluency · Tier 1: basic skills

  1. 1. Write an expression for "seven more than nn". (show answer)
    Answer
    n+7n + 7
  2. 2. Write an expression for "five less than 2m2m". (show answer)
    Answer
    2m52m - 5
  3. 3. Write an expression for "the product of 44 and xx". (show answer)
    Answer
    4x4x
  4. 4. Write an expression for "half of yy added to 33". (show answer)
    Answer
    y2+3\dfrac{y}{2} + 3
  5. 5. In the term 7x-7x, state the coefficient. (show answer)
    Answer
    7-7
  6. 6. Simplify   4x+3x\;4x + 3x. (show answer)
    Answer
    7x7x
  7. 7. Simplify   9y5y\;9y - 5y. (show answer)
    Answer
    4y4y
  8. 8. Simplify   3a+2b+5ab\;3a + 2b + 5a - b. (show answer)
    Answer
    8a+b8a + b
  9. 9. Simplify   7p42p+9\;7p - 4 - 2p + 9. (show answer)
    Answer
    5p+55p + 5
  10. 10. Simplify   2x+5y+3xy+4\;2x + 5y + 3x - y + 4. (show answer)
    Answer
    5x+4y+45x + 4y + 4
  11. 11. Evaluate 3a+23a + 2 when a=4a = 4. (show answer)
    Answer
    1414
  12. 12. Evaluate 5xy5x - y when x=2x = 2 and y=3y = -3. (show answer)
    Answer
    1313
  13. 13. Evaluate x2+1x^2 + 1 when x=4x = -4. (show answer)
    Answer
    1717
  14. 14. Expand   2(x+5)\;2(x + 5). (show answer)
    Answer
    2x+102x + 10
  15. 15. Expand   4(y3)\;4(y - 3). (show answer)
    Answer
    4y124y - 12
  16. 16. Expand   3(a+2)\;-3(a + 2). (show answer)
    Answer
    3a6-3a - 6
  17. 17. Expand   6(2m1)\;6(2m - 1). (show answer)
    Answer
    12m612m - 6
  18. 18. Simplify 8x+124\dfrac{8x + 12}{4}. (show answer)
    Answer
    2x+32x + 3
  19. 19. Simplify   3(x+2)+5\;3(x + 2) + 5. (show answer)
    Answer
    3x+113x + 11
  20. 20. Simplify   2(a+4)3\;2(a + 4) - 3. (show answer)
    Answer
    2a+52a + 5

Reasoning · Tier 2: mixed practice

  1. 1. Simplify   4(x+3)+2(x1)\;4(x + 3) + 2(x - 1). (show answer)
    Answer
    6x+106x + 10. Method: 4x+12+2x24x + 12 + 2x - 2.
  2. 2. Simplify   5(2y1)3(y+4)\;5(2y - 1) - 3(y + 4). (show answer)
    Answer
    7y177y - 17. Method: 10y53y1210y - 5 - 3y - 12.
  3. 3. Simplify   7m+42(m+3)\;7m + 4 - 2(m + 3). (show answer)
    Answer
    5m25m - 2. Method: 7m+42m67m + 4 - 2m - 6.
  4. 4. Evaluate   3x22x+1\;3x^2 - 2x + 1 when x=4x = 4. (show answer)
    Answer
    4141. Method: 3(16)8+1=488+13(16) - 8 + 1 = 48 - 8 + 1.
  5. 5. Evaluate   (a+b)2\;(a + b)^2 when a=3a = 3, b=1b = -1. (show answer)
    Answer
    44. Method: (3+(1))2=22(3 + (-1))^2 = 2^2.
  6. 6. Expand   2(3x4)(x+2)\;-2(3x - 4) - (x + 2). (show answer)
    Answer
    7x+6-7x + 6. Method: 6x+8x2-6x + 8 - x - 2.
  7. 7. Simplify 10a155\dfrac{10a - 15}{5}. (show answer)
    Answer
    2a32a - 3. Method: divide each term.
  8. 8. Write an expression for the perimeter of a rectangle with length 2x+12x + 1 and width xx. Simplify it. (show answer)
    Answer
    Perimeter =6x+2= 6x + 2. Method: 2(2x+1)+2x=4x+2+2x2(2x + 1) + 2x = 4x + 2 + 2x.
  9. 9. Write an expression for the cost of nn apples at $0.60 each and mm bananas at $0.40 each. (show answer)
    Answer
    0.60n+0.40m0.60n + 0.40m (in dollars).
  10. 10. Find the missing coefficient: 5x+x=12x5x + \square x = 12x. (show answer)
    Answer
    77. Method: 5+7=125 + 7 = 12.
  11. 11. Simplify   3a×4b\;3a \times 4b. (show answer)
    Answer
    12ab12ab. Method: 3×4×a×b3 \times 4 \times a \times b.
  12. 12. Simplify   12xy3y\;\dfrac{12xy}{3y}. (show answer)
    Answer
    4x4x. Method: cancel the yys, then 12÷312 \div 3.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. Kira writes 3+2x=5x3 + 2x = 5x. Is Kira correct? If not, explain the mistake and give the correct simplification. (show answer)
    Answer
    Wrong. 33 and 2x2x are not like terms - one is a constant, the other has a variable - so they cannot be combined into a single term. The simplest form is 3+2x3 + 2x (or 2x+32x + 3).
  2. 2. Explain why 3x3x and 3x23x^2 are not like terms, with a numerical example. (show answer)
    Answer
    They have different variable parts: xx vs x2x^2. Try x=2x = 2: 3x=63x = 6 but 3x2=123x^2 = 12. If they were like terms they would always be equal, but they aren't.
  3. 3. Leo expands 4(x3)-4(x - 3) as 4x12-4x - 12. Is this right? If not, what is the correct expansion? (show answer)
    Answer
    Wrong. 4(x3)=4x+12-4(x - 3) = -4x + 12. Leo forgot that 4×3=+12-4 \times -3 = +12, not 12-12. Two negatives make a positive.
  4. 4. Write two different expressions that both equal 1212 when x=3x = 3. (show answer)
    Answer
    Many possible answers, e.g. 4x4x, 2x+62x + 6, x2+3x^2 + 3, or 5x35x - 3 (each gives 1212 when x=3x = 3).
  5. 5. Are 2(a+3)2(a + 3) and 2a+32a + 3 always equal? Explain with an example. (show answer)
    Answer
    Not equal in general. 2(a+3)=2a+62(a + 3) = 2a + 6, which is not the same as 2a+32a + 3. Try a=1a = 1: left side =8= 8, right side =5= 5. The 22 must distribute to every term inside the bracket.

Fluency · Using everyday formulas (substitution)

  1. 1. A rectangle has L=12L = 12 cm and W=5W = 5 cm. Find its area and perimeter using A=L×WA = L \times W and P=2L+2WP = 2L + 2W. (show answer)
    Answer
    Area 6060 cm^2; perimeter 3434 cm.
  2. 2. Hawthorn scored 1414 goals and 77 behinds. Use total=6g+b\text{total} = 6g + b to find their total. (show answer)
    Answer
    14×6+7=84+7=9114 \times 6 + 7 = 84 + 7 = 91 points.
  3. 3. Collingwood kicked 99 goals and 1313 behinds; Melbourne kicked 1111 goals and 55 behinds. Who won, and by how much? (show answer)
    Answer
    Collingwood 9×6+13=679 \times 6 + 13 = 67; Melbourne 11×6+5=7111 \times 6 + 5 = 71. Melbourne won by 44 points.
  4. 4. Sam's base wage is $360 per week, normal rate $22/h. He worked 44 hours of overtime. Use W=b+1.5rhW = b + 1.5rh to find his total pay. (show answer)
    Answer
    $492. Method: 360+1.5×22×4=360+132360 + 1.5 \times 22 \times 4 = 360 + 132.
  5. 5. A metal bar has mass 504504 g and volume 6464 cm^3. Find its density using D=MVD = \dfrac{M}{V}. (show answer)
    Answer
    D=7.875D = 7.875 g/cm^3. Method: 504÷64504 \div 64.
  6. 6. Find the maximum heart rate for a person aged 4545 using HRmax=220aHR_{\max} = 220 - a. (show answer)
    Answer
    175175 bpm. Method: 22045220 - 45.
  7. 7. A car travels at 8080 km/h for 2.52.5 h. How far does it travel? (Use d=s×td = s \times t.) (show answer)
    Answer
    200200 km. Method: 80×2.580 \times 2.5.
  8. 8. A cyclist covers 4545 km in 33 hours. Find the average speed. (show answer)
    Answer
    1515 km/h. Method: 45÷345 \div 3.
  9. 9. Use the formula C=59(F32)C = \tfrac{5}{9}(F - 32) to convert 68deg68 degF to degrees Celsius. (show answer)
    Answer
    2020 degC. Method: 59(6832)=59×36=20\tfrac{5}{9}(68 - 32) = \tfrac{5}{9} \times 36 = 20.

Problem-solving · Tier 4: real-world problems

  1. 1. Mira has $x. She spends $5 on lunch and then earns $20 helping a neighbour. Write an expression for how much she has now. If she started with $12, how much has she now? (show answer)
    Answer
    x+15x + 15; $27. Method: 5+20=+15-5 + 20 = +15; then 12+1512 + 15.
  2. 2. A phone plan costs a $20 monthly fee plus $0.10 per minute. Write an expression for the cost of a month with tt minutes of calls. What is the cost if t=150t = 150? (show answer)
    Answer
    20+0.10t20 + 0.10t dollars; $35. Method: 20+0.10×15020 + 0.10 \times 150.
  3. 3. The length of a rectangle is 33 cm more than twice its width. If the width is ww, write expressions for the length and perimeter. Simplify the perimeter. (show answer)
    Answer
    Length =2w+3= 2w + 3; perimeter =6w+6= 6w + 6. Method: P=2(L+W)=2(2w+3+w)P = 2(L + W) = 2(2w + 3 + w).
  4. 4. A taxi charges a $4.50 flag-fall plus $2 per kilometre. Write the cost for a kk-kilometre trip, and find the cost of a 1212 km trip. (show answer)
    Answer
    Cost =4.50+2k= 4.50 + 2k; $28.50. Method: 4.50+2×124.50 + 2 \times 12.
  5. 5. Five students each give $x toward a gift that costs $42. Write an expression for how much change is left after the gift is bought. Evaluate it if x=10x = 10. (show answer)
    Answer
    5x425x - 42; $8. Method: 5×10=505 \times 10 = 50; 5042=850 - 42 = 8.
  6. 6. A swimming pool holds VV litres and a hose fills it at rr L/min. Write an expression for the time to fill the pool. How long (in minutes) if V=60000V = 60\,000 and r=150r = 150? (show answer)
    Answer
    Time =Vr= \dfrac{V}{r} minutes; 400400 min (66 h 4040 min). Method: 60000÷15060\,000 \div 150.
  7. 7. A mobile plan charges $25 per month plus $0.08 per text. Lucy sent tt texts in a month. Write an expression for her total cost, then find the cost when t=180t = 180. (show answer)
    Answer
    25+0.08t25 + 0.08t dollars; $39.40. Method: 25+0.08×18025 + 0.08 \times 180.
  8. 8. A gym membership costs $59 to join plus $15 per week. Write an expression for the total cost after ww weeks. When does the total first exceed $200? (show answer)
    Answer
    59+15w59 + 15w. Exceeds $200 when 15w>14115w > 141, so when w10w \geq 10 - first exceeded at the end of week 1010.
  9. 9. A delivery van's fuel cost per trip is C=0.15dC = 0.15 d, where dd is the trip distance in kilometres. Find the cost of a 240240 km trip. If the fuel cost doubled per kilometre, what would the new formula be? (show answer)
    Answer
    $36 for a 240240 km trip. New formula: C=0.30dC = 0.30 d.
  10. 10. Daniella's target training heart rate zone is between 50%50\% and 70%70\% of HRmax=220aHR_{\max} = 220 - a (where aa is her age in years). She is 1212. Find the two ends of her target zone. (show answer)
    Answer
    HRmax=208HR_{\max} = 208 bpm. 50%50\% zone 104\approx 104 bpm; 70%70\% zone 146\approx 146 bpm. Target zone: roughly 104104-146146 bpm.

Linear equations

Fluency · One-step equations

  1. 1. Solve   x+8=20\;x + 8 = 20. (show answer)
    Answer
    x=12x = 12
  2. 2. Solve   y6=13\;y - 6 = 13. (show answer)
    Answer
    y=19y = 19
  3. 3. Solve   4x=28\;4x = 28. (show answer)
    Answer
    x=7x = 7
  4. 4. Solve   y3=7\;\dfrac{y}{3} = 7. (show answer)
    Answer
    y=21y = 21
  5. 5. Solve   x+17=30\;x + 17 = 30. (show answer)
    Answer
    x=13x = 13
  6. 6. Solve   a9=1\;a - 9 = 1. (show answer)
    Answer
    a=10a = 10
  7. 7. Solve   7m=42\;7m = 42. (show answer)
    Answer
    m=6m = 6
  8. 8. Solve   x6=4\;\dfrac{x}{6} = 4. (show answer)
    Answer
    x=24x = 24

Fluency · Two-step equations

  1. 1. Solve   2x+3=11\;2x + 3 = 11. (show answer)
    Answer
    x=4x = 4
  2. 2. Solve   3y5=7\;3y - 5 = 7. (show answer)
    Answer
    y=4y = 4
  3. 3. Solve   5x+1=16\;5x + 1 = 16. (show answer)
    Answer
    x=3x = 3
  4. 4. Solve   4x3=9\;4x - 3 = 9. (show answer)
    Answer
    x=3x = 3
  5. 5. Solve   7a4=24\;7a - 4 = 24. (show answer)
    Answer
    a=4a = 4
  6. 6. Solve   x2+1=6\;\dfrac{x}{2} + 1 = 6. (show answer)
    Answer
    x=10x = 10
  7. 7. Solve   m34=1\;\dfrac{m}{3} - 4 = 1. (show answer)
    Answer
    m=15m = 15
  8. 8. Solve   x+52=4\;\dfrac{x + 5}{2} = 4. (show answer)
    Answer
    x=3x = 3. Method: multiply by 22, x+5=8x + 5 = 8; subtract 55.
  9. 9. Solve   2x+13=5\;\dfrac{2x + 1}{3} = 5. (show answer)
    Answer
    x=7x = 7. Method: multiply by 33, 2x+1=152x + 1 = 15; then subtract 11 and divide by 22.
  10. 10. Solve   3(x+2)=18\;3(x + 2) = 18. (show answer)
    Answer
    x=4x = 4. Method: divide by 33, x+2=6x + 2 = 6.

Reasoning · Verify and reason

  1. 1. Verify, without solving, whether x=6x = 6 is a solution of   2x+4=16\;2x + 4 = 16. (show answer)
    Answer
    Yes. 2(6)+4=12+4=162(6) + 4 = 12 + 4 = 16. ✓
  2. 2. Verify whether y=3y = 3 is a solution of   5y1=15\;5y - 1 = 15. (show answer)
    Answer
    No. 5(3)1=145(3) - 1 = 14, not 1515.
  3. 3. Zara solves 2x+6=142x + 6 = 14 by writing "2x=14+6=202x = 14 + 6 = 20, so x=10x = 10". Explain her mistake and give the correct answer. (show answer)
    Answer
    Zara added 66 when she should have subtracted. The inverse of "+6+ 6" is "6- 6". Correct working: 2x+6=142x=8x=42x + 6 = 14 \Rightarrow 2x = 8 \Rightarrow x = 4.
  4. 4. Find the missing number: solve   +7=15\;\square + 7 = 15 and check by substitution. (show answer)
    Answer
    =8\square = 8. Check: 8+7=158 + 7 = 15. ✓
  5. 5. Write an equation of your own whose solution is x=8x = 8, and verify it by substitution. (show answer)
    Answer
    Many answers possible. Example: 3x4=203x - 4 = 20 gives x=8x = 8. Check: 3(8)4=203(8) - 4 = 20. ✓

Problem-solving · Worded problems

  1. 1. Four times a number, increased by 77, is 3131. Find the number. (show answer)
    Answer
    66. Method: 4n+7=314n + 7 = 31, so 4n=244n = 24.
  2. 2. A pencil costs $2 and a ruler costs $r. Three pencils and a ruler cost $8 in total. Find rr. (show answer)
    Answer
    r = $2. Method: 3×2+r=83 \times 2 + r = 8, so 6+r=86 + r = 8.
  3. 3. Ava is xx years old. Her sister is 33 years older. In 55 years, the sum of their ages will be 3333. How old is Ava now? (show answer)
    Answer
    Ava is 1010. Method: Ava =x= x; sister =x+3= x + 3. In 55 years: (x+5)+(x+8)=33(x + 5) + (x + 8) = 33; 2x+13=332x + 13 = 33; x=10x = 10.
  4. 4. A taxi charges a $4 flag-fall and $2.50 per kilometre. A trip cost $29. How long was the trip? (show answer)
    Answer
    1010 km. Method: 4+2.50k=294 + 2.50k = 29, so 2.50k=252.50k = 25.
  5. 5. The perimeter of an isosceles triangle with two equal sides of length xx cm and base 88 cm is 3030 cm. Find xx. (show answer)
    Answer
    x=11x = 11 cm. Method: x+x+8=30x + x + 8 = 30.
  6. 6. Five consecutive natural numbers sum to 4545. Find the smallest of them. (Hint: call it nn and write n+(n+1)+n + (n+1) + \ldots) (show answer)
    Answer
    77 is the smallest. Method: n+(n+1)+(n+2)+(n+3)+(n+4)=5n+10=45n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10 = 45; 5n=355n = 35; n=7n = 7.

Reasoning · Non-positive and two-sided equations

  1. 1. Solve   x+11=5\;x + 11 = 5. (show answer)
    Answer
    x=6x = -6. Method: subtract 1111.
  2. 2. Solve   2m=14\;-2m = 14. (show answer)
    Answer
    m=7m = -7. Method: divide by 2-2.
  3. 3. Solve   2x+9=3\;2x + 9 = 3. (show answer)
    Answer
    x=3x = -3. Method: subtract 99; divide by 22.
  4. 4. Solve   3x+5=20\;-3x + 5 = 20. (show answer)
    Answer
    x=5x = -5. Method: subtract 55, 3x=15-3x = 15; divide by 3-3.
  5. 5. Solve   102x=4\;10 - 2x = 4. (show answer)
    Answer
    x=3x = 3. Method: subtract 1010, 2x=6-2x = -6; divide by 2-2.
  6. 6. Solve   5x2=2x+10\;5x - 2 = 2x + 10. (show answer)
    Answer
    x=4x = 4. Method: subtract 2x2x from both sides, 3x2=103x - 2 = 10; add 22, 3x=123x = 12.
  7. 7. Solve   4y+7=y+19\;4y + 7 = y + 19. (show answer)
    Answer
    y=4y = 4. Method: subtract yy, 3y+7=193y + 7 = 19; subtract 77; divide by 33.
  8. 8. Solve   x2+x3=10\;\dfrac{x}{2} + \dfrac{x}{3} = 10. (Hint: multiply both sides by 66.) (show answer)
    Answer
    x=12x = 12. Method: multiply by 66, 3x+2x=603x + 2x = 60; 5x=605x = 60.
  9. 9. The sum of three consecutive integers is 9-9. Find them. (show answer)
    Answer
    4,3,2-4, -3, -2. Method: 3n+3=93n + 3 = -9, so n=4n = -4.
  10. 10. A number increased by 40%40\% gives 8484. What was the original number? (show answer)
    Answer
    6060. Method: x×1.40=84x \times 1.40 = 84, so x=60x = 60.

Length, perimeter, area & circles

Fluency · Length and perimeter

  1. 1. Convert 250250 cm to metres. (show answer)
    Answer
    2.52.5 m
  2. 2. Convert 3.43.4 km to metres. (show answer)
    Answer
    34003400 m
  3. 3. Convert 8585 mm to cm. (show answer)
    Answer
    8.58.5 cm
  4. 4. Convert 25002500 m to km. (show answer)
    Answer
    2.52.5 km
  5. 5. Find the perimeter of a rectangle 1212 cm by 77 cm. (show answer)
    Answer
    3838 cm
  6. 6. Find the perimeter of a square with side 99 cm. (show answer)
    Answer
    3636 cm
  7. 7. A triangle has sides 55 cm, 77 cm, 99 cm. Find its perimeter. (show answer)
    Answer
    2121 cm
  8. 8. A regular hexagon has side 44 cm. Find its perimeter. (show answer)
    Answer
    2424 cm

Fluency · Area of rectangles, triangles, parallelograms

  1. 1. Find the area of a 1515 cm by 44 cm rectangle. (show answer)
    Answer
    6060 cm^2
  2. 2. Find the area of a square with side 66 cm. (show answer)
    Answer
    3636 cm^2
  3. 3. Find the area of a triangle with base 1010 cm and height 88 cm. (show answer)
    Answer
    4040 cm^2
  4. 4. Find the area of a triangle with base 1212 m and height 55 m. (show answer)
    Answer
    3030 m^2
  5. 5. Find the area of a parallelogram with base 99 cm and height 66 cm. (show answer)
    Answer
    5454 cm^2
  6. 6. A rectangle has area 4848 cm^2 and length 88 cm. Find its width. (show answer)
    Answer
    66 cm
  7. 7. A triangle has area 3636 cm^2 and base 99 cm. Find its height. (show answer)
    Answer
    88 cm. Method: 12×9×h=36\tfrac{1}{2} \times 9 \times h = 36.
  8. 8. A parallelogram has area 6060 m^2 and height 55 m. Find its base. (show answer)
    Answer
    1212 m. Method: b×5=60b \times 5 = 60.

Fluency · Circles

  1. 1. A circle has radius 44 cm. Find its diameter. (show answer)
    Answer
    88 cm
  2. 2. A circle has diameter 1818 m. Find its radius. (show answer)
    Answer
    99 m
  3. 3. Find the circumference of a circle with radius 1010 cm. (show answer)
    Answer
    62.862.8 cm. Method: 2×3.14×102 \times 3.14 \times 10.
  4. 4. Find the circumference of a circle with diameter 1414 cm, using π227\pi \approx \tfrac{22}{7}. (show answer)
    Answer
    4444 cm. Method: 227×14\tfrac{22}{7} \times 14.
  5. 5. A circle has circumference 31.431.4 cm. Find its diameter. (show answer)
    Answer
    1010 cm. Method: d=C/π=31.4/3.14d = C / \pi = 31.4 / 3.14.
  6. 6. True or false: for every circle, circumference ÷\div diameter gives about the same number. (show answer)
    Answer
    True - that constant ratio is π\pi.

Reasoning · Explain and reason

  1. 1. Two rectangles have the same perimeter. Does it follow that they have the same area? Justify with a numerical example. (show answer)
    Answer
    Not necessarily. Example: a 4×64 \times 6 rectangle has perimeter 2020 and area 2424; a 2×82 \times 8 rectangle also has perimeter 2020 but area 1616. Same perimeter, different area.
  2. 2. Pete writes the area of a triangle with base 66 and slant side 55 as 12×6×5=15\tfrac{1}{2} \times 6 \times 5 = 15. Explain what is wrong. (show answer)
    Answer
    Pete used the slant side, not the perpendicular height. Without the perpendicular height, the area formula cannot be applied directly; more information is needed.
  3. 3. Is it possible for one shape to have a larger perimeter but a smaller area than another? Give an example. (show answer)
    Answer
    Yes. Example: a thin 1×201 \times 20 rectangle has perimeter 4242 and area 2020, while a 5×55 \times 5 square has perimeter 2020 and area 2525. The first has a larger perimeter but smaller area.
  4. 4. A pizza of diameter 3030 cm is cut exactly in half. What is the perimeter of each half-pizza (the crust plus the straight cut)? (show answer)
    Answer
    30+12(π×30)30+47.1=77.130 + \tfrac{1}{2}(\pi \times 30) \approx 30 + 47.1 = 77.1 cm. Method: cut across the pizza is 3030 cm; half the circumference is 12πd\tfrac{1}{2}\pi d.
  5. 5. Without calculating, decide which has the larger area: a square with side 1010 cm or a rectangle 1212 cm by 88 cm. Explain. (show answer)
    Answer
    Square wins. Square area =100= 100; rectangle area =96= 96. Among rectangles with the same perimeter (4040 here), the square has the greatest area.

Problem-solving · Real-world problems

  1. 1. A rectangular paddock is 8080 m by 4545 m. What is the cost of fencing it at $18 per metre? (show answer)
    Answer
    $4500. Method: perimeter =2(80+45)=250= 2(80 + 45) = 250; cost =250×18= 250 \times 18.
  2. 2. A triangular sail has base 3.53.5 m and height 44 m. What is its area in square metres? (show answer)
    Answer
    77 m^2. Method: 12×3.5×4\tfrac{1}{2} \times 3.5 \times 4.
  3. 3. A circular garden pond has diameter 3.53.5 m. How long is a rope needed to go once around the edge? (Use π227\pi \approx \tfrac{22}{7}.) (show answer)
    Answer
    1111 m. Method: C=πd=227×3.5=11C = \pi d = \tfrac{22}{7} \times 3.5 = 11.
  4. 4. A rectangular garden is 88 m by 1212 m. Convert the area to square centimetres. (show answer)
    Answer
    960000960\,000 cm^2. Method: 9696 m^2; 11 m^2 =10000= 10\,000 cm^2.
  5. 5. A bicycle wheel has diameter 7070 cm. How far (to the nearest metre) does the bike travel in 2020 turns of the wheel? (Use π227\pi \approx \tfrac{22}{7}.) (show answer)
    Answer
    4444 m (to nearest metre). Method: C=227×70=220C = \tfrac{22}{7} \times 70 = 220 cm per turn =2.2= 2.2 m; ×20=44\times 20 = 44 m.

Reasoning · Trapezium and composite areas

  1. 1. Find the area of a trapezium with parallel sides 44 cm and 1010 cm and height 33 cm. (show answer)
    Answer
    2121 cm^2. Method: 12(4+10)×3=21\tfrac{1}{2}(4 + 10) \times 3 = 21.
  2. 2. Find the area of a trapezium with parallel sides 66 m and 1010 m and height 44 m. (show answer)
    Answer
    3232 m^2. Method: 12(6+10)×4=32\tfrac{1}{2}(6 + 10) \times 4 = 32.
  3. 3. An L-shape is made of an 88 m by 55 m rectangle with a 33 m by 22 m rectangle removed from one corner. Find its area. (show answer)
    Answer
    3434 m^2. Method: 40640 - 6.
  4. 4. A path 11 m wide runs around a 1010 m by 66 m garden, on the outside. Find the area of the path. (show answer)
    Answer
    3636 m^2. Method: outer 12×8=9612 \times 8 = 96; garden 10×6=6010 \times 6 = 60; path =9660= 96 - 60.
  5. 5. A rectangular piece of cardboard is 4040 cm by 3030 cm. A 55 cm square is cut from each corner. What is the remaining area? (show answer)
    Answer
    11001100 cm^2. Method: 40×304×52=120010040 \times 30 - 4 \times 5^2 = 1200 - 100.

Volume & capacity

Fluency · Unit conversions

  1. 1. Convert 25002500 mL to litres. (show answer)
    Answer
    2.52.5 L
  2. 2. Convert 4.64.6 L to mL. (show answer)
    Answer
    46004600 mL
  3. 3. Convert 75007500 cm^3 to mL. (show answer)
    Answer
    75007500 mL
  4. 4. Convert 33 m^3 to litres. (show answer)
    Answer
    30003000 L
  5. 5. Convert 45004500 mm^3 to cm^3. (show answer)
    Answer
    4.54.5 cm^3
  6. 6. A 22 L bottle holds how many cm^3? (show answer)
    Answer
    20002000 cm^3

Fluency · Rectangular prism

  1. 1. Find the volume of a 6×5×46 \times 5 \times 4 cm cuboid. (show answer)
    Answer
    120120 cm^3
  2. 2. Find the volume of a cube with edge 77 cm. (show answer)
    Answer
    343343 cm^3
  3. 3. Find the volume of a 12×8×312 \times 8 \times 3 m room. (show answer)
    Answer
    288288 m^3
  4. 4. A fish tank is 40×25×2040 \times 25 \times 20 cm. Find the volume in cm^3 and the capacity in L. (show answer)
    Answer
    2000020\,000 cm^3 =20= 20 L
  5. 5. A cube has volume 125125 cm^3. Find the edge length. (show answer)
    Answer
    55 cm
  6. 6. A rectangular tank has base 8080 cm by 6060 cm and height 5050 cm. Find the capacity in litres. (show answer)
    Answer
    240240 L. Method: V=240000V = 240\,000 cm^3 =240= 240 L.

Fluency · Triangular prism

  1. 1. A triangular prism has a triangular base of base 66 cm and height 44 cm, and length 1010 cm. Find the volume. (show answer)
    Answer
    120120 cm^3. Method: base area 12×6×4=12\tfrac{1}{2} \times 6 \times 4 = 12; ×10\times 10.
  2. 2. A tent has a triangular cross-section of base 22 m and height 1.51.5 m, and is 2.52.5 m long. Find the volume. (show answer)
    Answer
    3.753.75 m^3. Method: base area 1.51.5; ×2.5\times 2.5.
  3. 3. A wedge-shaped doorstop has a right-triangular base with legs 44 cm and 66 cm, and is 88 cm wide. Find the volume. (show answer)
    Answer
    9696 cm^3. Method: base area 12×4×6=12\tfrac{1}{2} \times 4 \times 6 = 12; ×8\times 8.
  4. 4. A triangular prism has volume 120120 cm^3. Its length is 1010 cm. What is the area of the triangular base? (show answer)
    Answer
    1212 cm^2. Method: 120÷10120 \div 10.

Reasoning · Explain and reason

  1. 1. Ben writes the volume of a 4×4×44 \times 4 \times 4 cube as 42=164^2 = 16 cm^3. What mistake has Ben made? (show answer)
    Answer
    Ben used 424^2 (the area of one face) instead of 434^3 (the volume of the cube). Volume of a cube is s3s^3: 43=644^3 = 64 cm^3.
  2. 2. Explain in your own words why 11 cm^3 =1= 1 mL. (show answer)
    Answer
    One millilitre of water fills a cube of side 11 cm - this was built into the metric system by definition.
  3. 3. Two rectangular tanks have the same capacity. Must they have the same surface area? Give a reason or a counter-example. (show answer)
    Answer
    Not necessarily. Example: a 10×10×1010 \times 10 \times 10 cube and a 1×1×10001 \times 1 \times 1000 thin prism both have volume 10001000 units^3 but very different surface areas.
  4. 4. Without calculating, decide which has the greater volume: a cube of side 66 cm, or a rectangular prism of 5×6×75 \times 6 \times 7 cm. Explain briefly. (show answer)
    Answer
    Cube is slightly larger: 63=2166^3 = 216; prism =5×6×7=210= 5 \times 6 \times 7 = 210.
  5. 5. A rectangular prism and a triangular prism both have length 1010 cm. The rectangular prism has a 66 cm by 44 cm base. What base area would the triangular prism need so that they have the same volume? (show answer)
    Answer
    Triangle area needs to be 2424 cm^2. Method: rectangular prism volume =6×4×10=240= 6 \times 4 \times 10 = 240; triangular prism volume =24×10=240= 24 \times 10 = 240.

Problem-solving · Real-world problems

  1. 1. A water tank is 1.21.2 m by 0.80.8 m by 1.51.5 m deep. How many litres when full? (show answer)
    Answer
    14401440 L. Method: V=1.2×0.8×1.5=1.44V = 1.2 \times 0.8 \times 1.5 = 1.44 m^3 =1440= 1440 L.
  2. 2. A swimming pool is 1515 m long, 88 m wide, and has a uniform depth of 1.51.5 m. How many kilolitres? At $2.50/kL, what is the cost to fill? (show answer)
    Answer
    180180 kL; $450. Method: 15×8×1.5=18015 \times 8 \times 1.5 = 180 m^3; ×2.50\times 2.50.
  3. 3. A shoebox is 3333 cm ×\times 2222 cm ×\times 1515 cm. Find the volume in cm^3 and in litres (to 22 dp). (show answer)
    Answer
    1089010\,890 cm^3 =10.89= 10.89 L.
  4. 4. A small aquarium holds 3636 L and has base 6060 cm by 3030 cm. What is the water height? (show answer)
    Answer
    2020 cm. Method: 3600036\,000 cm^3 ÷(60×30)\div (60 \times 30).
  5. 5. A 2.52.5 L carton is poured into glasses that hold 250250 mL each. How many full glasses? (show answer)
    Answer
    1010 glasses.
  6. 6. A chocolate bar is a triangular prism with equilateral cross-section (side 33 cm, height 2.6\approx 2.6 cm) and length 1212 cm. Find its volume (to the nearest cm^3). (show answer)
    Answer
    About 4747 cm^3. Method: triangle area 12×3×2.6=3.9\approx \tfrac{1}{2} \times 3 \times 2.6 = 3.9 cm^2; ×1246.8\times 12 \approx 46.8.

Angles & angle relationships

Fluency · Tier 1: basic skills

  1. 1. Classify as acute, right, obtuse, straight, or reflex: 5555^\circ. (show answer)
    Answer
    acute
  2. 2. Classify: 9090^\circ. (show answer)
    Answer
    right
  3. 3. Classify: 142142^\circ. (show answer)
    Answer
    obtuse
  4. 4. Classify: 210210^\circ. (show answer)
    Answer
    reflex
  5. 5. Classify: 180180^\circ. (show answer)
    Answer
    straight
  6. 6. Two angles on a line are xx and 7878^\circ. Find xx. (show answer)
    Answer
    x=102x = 102^\circ
  7. 7. Two angles on a line are xx and 119119^\circ. Find xx. (show answer)
    Answer
    x=61x = 61^\circ
  8. 8. Two angles at a point are 130130^\circ and xx. (These are the only two.) Find xx. (show answer)
    Answer
    x=230x = 230^\circ (the two angles at a point sum to 360360^\circ)
  9. 9. Three angles at a point are 9090^\circ, 150150^\circ, xx. Find xx. (show answer)
    Answer
    x=120x = 120^\circ
  10. 10. Two lines cross. One of the angles is 6363^\circ. Find the other three. (show answer)
    Answer
    6363^\circ (vertically opposite); two of 117117^\circ (on the line with the 6363^\circ)
  11. 11. In a triangle, two angles are 4040^\circ and 6060^\circ. Find the third. (show answer)
    Answer
    8080^\circ
  12. 12. In an isosceles triangle, the apex angle is 8080^\circ. Find each base angle. (show answer)
    Answer
    5050^\circ each
  13. 13. In a right-angled triangle, one of the non-right angles is 3535^\circ. Find the other. (show answer)
    Answer
    5555^\circ
  14. 14. A transversal cuts two parallel lines. Corresponding angles of xx and 7373^\circ. Find xx. (show answer)
    Answer
    x=73x = 73^\circ
  15. 15. A transversal cuts two parallel lines. Alternate angles of xx and 112112^\circ. Find xx. (show answer)
    Answer
    x=112x = 112^\circ
  16. 16. A transversal cuts two parallel lines. Co-interior angles of xx and 108108^\circ. Find xx. (show answer)
    Answer
    x=72x = 72^\circ

Reasoning · Tier 2: mixed practice

  1. 1. Three angles on a straight line are xx, 2x2x and 6060^\circ. Find xx. (show answer)
    Answer
    x=40x = 40^\circ. Method: x+2x+60=180x + 2x + 60 = 180, so 3x=1203x = 120.
  2. 2. At a point the angles are xx, x+40x + 40^\circ and 150150^\circ, with no other angles. Find xx. (show answer)
    Answer
    x=85x = 85^\circ. Method: x+x+40+150=360x + x + 40 + 150 = 360, so 2x=1702x = 170.
  3. 3. In a triangle the angles are in the ratio 1:2:31 : 2 : 3. Find each angle. (show answer)
    Answer
    30,60,9030^\circ, 60^\circ, 90^\circ. Method: 1+2+3=61 + 2 + 3 = 6 parts; each part =30= 30^\circ.
  4. 4. In a triangle the angles are 2x2x, 3x3x and 4x4x. Find xx and each angle. (show answer)
    Answer
    x=20x = 20^\circ; angles 40,60,8040^\circ, 60^\circ, 80^\circ. Method: 9x=1809x = 180.
  5. 5. An exterior angle of a triangle is 120120^\circ. The two interior angles not adjacent to it sum to what? (show answer)
    Answer
    120120^\circ. Reason: exterior angle equals the sum of the two non-adjacent interior angles.
  6. 6. An isosceles triangle has a base angle of 7272^\circ. Find the apex angle. (show answer)
    Answer
    3636^\circ. Method: both base angles are 7272^\circ; apex =180144= 180 - 144.
  7. 7. Two parallel lines are cut by a transversal. One co-interior angle is 3x3x and the other is 5x5x. Find xx. (show answer)
    Answer
    x=22.5x = 22.5^\circ. Method: 3x+5x=1803x + 5x = 180.
  8. 8. A right-angled triangle has angles 9090^\circ, xx and 2x+152x + 15^\circ. Find xx. (show answer)
    Answer
    x=25x = 25^\circ. Method: x+2x+15=90x + 2x + 15 = 90, so 3x=753x = 75.
  9. 9. Three angles around a point are xx, 110110^\circ and 2x2x. Find xx. (show answer)
    Answer
    x=8313x = 83\tfrac{1}{3}^\circ. Method: 3x+110=3603x + 110 = 360, so 3x=2503x = 250.
  10. 10. Two parallel lines have transversal angles of 2x+202x + 20^\circ and x+70x + 70^\circ as corresponding angles. Find xx. (show answer)
    Answer
    x=50x = 50^\circ. Method: corresponding angles are equal, so 2x+20=x+702x + 20 = x + 70, hence x=50x = 50.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. A student claims "vertically opposite angles add to 180180^\circ". Is this always true? If not, when is it wrong? (show answer)
    Answer
    Not always true. Vertically opposite angles are equal, not supplementary. They only add to 180180^\circ in the special case where both are 9090^\circ. The pair that sums to 180180^\circ is the pair of angles on a straight line (adjacent angles at the crossing), not the vertically opposite pair.
  2. 2. Emma says "the three angles in a triangle always sum to 180180^\circ, so any three angles that add to 180180^\circ form a triangle". Is Emma correct? Justify with an example. (show answer)
    Answer
    Emma is essentially correct: any three positive angles that sum to 180180^\circ can be the angles of some triangle. The caveat is that each angle must be positive - e.g. 0,0,1800^\circ, 0^\circ, 180^\circ sums to 180180^\circ but cannot form a triangle.
  3. 3. Tom says a co-interior angle pair must be equal. What is Tom mixing up? Give the correct relationship. (show answer)
    Answer
    Tom is wrong. Co-interior angles are supplementary (sum to 180180^\circ), not equal. He is confusing co-interior with alternate or corresponding angles, which are equal on parallel lines.
  4. 4. Is it possible for a triangle to have two right angles? Explain. (show answer)
    Answer
    Not possible. The three angles in a triangle must sum to 180180^\circ. Two right angles already account for 180180^\circ, leaving 00^\circ for the third - which is not a valid angle in a triangle.

Problem-solving · Tier 4: real-world problems

  1. 1. A clock shows 3:003{:}00. What is the angle between the hands? (show answer)
    Answer
    9090^\circ. The 1212 and 33 positions form a right angle.
  2. 2. A clock shows 6:006{:}00. What is the angle between the hands? (show answer)
    Answer
    180180^\circ. The hands point in opposite directions.
  3. 3. A staircase makes a 3535^\circ angle with the floor. What angle does it make with the wall (assumed vertical)? (show answer)
    Answer
    5555^\circ with the wall. Method: wall and floor are perpendicular; 903590 - 35.
  4. 4. A sign is tilted 1515^\circ from vertical. What angle does it make with the horizontal ground? (show answer)
    Answer
    7575^\circ with the ground. Method: 901590 - 15.
  5. 5. A road crosses two parallel train tracks. One of the acute angles at the crossing is 4848^\circ. What are the sizes of the other three angles at each crossing? (show answer)
    Answer
    The four angles are 4848^\circ, 132132^\circ, 4848^\circ, 132132^\circ. The acute 4848^\circ and its vertically opposite pair give one set; the other two are 18048=132180 - 48 = 132^\circ each.
  6. 6. A triangular piece of land has one angle of 9090^\circ and another of 5353^\circ. What is the third angle? (show answer)
    Answer
    3737^\circ. Method: 1809053180 - 90 - 53.

2D shapes & transformations

Fluency · Tier 1: basic skills

  1. 1. Name a triangle with all three sides equal. (show answer)
    Answer
    Equilateral
  2. 2. Name a triangle with exactly two sides equal. (show answer)
    Answer
    Isosceles
  3. 3. Name a triangle with all three sides different. (show answer)
    Answer
    Scalene
  4. 4. Name a triangle with one 9090^\circ angle. (show answer)
    Answer
    Right-angled
  5. 5. Name the quadrilateral with four equal sides and four right angles. (show answer)
    Answer
    Square
  6. 6. Name the quadrilateral with opposite sides parallel but no right angles and unequal adjacent sides. (show answer)
    Answer
    Parallelogram (non-rectangle, non-rhombus)
  7. 7. Name the quadrilateral with two pairs of adjacent equal sides. (show answer)
    Answer
    Kite
  8. 8. How many lines of symmetry does an isosceles triangle have? (show answer)
    Answer
    11
  9. 9. How many lines of symmetry does a rectangle have? (show answer)
    Answer
    22
  10. 10. What is the order of rotational symmetry of a parallelogram? (show answer)
    Answer
    22
  11. 11. What is the order of rotational symmetry of a square? (show answer)
    Answer
    44
  12. 12. A point (3,4)(3, 4) is translated 22 left and 55 up. Find its image. (show answer)
    Answer
    (1,9)(1, 9)
  13. 13. Reflect (2,5)(2, 5) in the yy-axis. (show answer)
    Answer
    (2,5)(-2, 5)
  14. 14. Reflect (1,4)(-1, 4) in the xx-axis. (show answer)
    Answer
    (1,4)(-1, -4)
  15. 15. Rotate (1,0)(1, 0) by 9090^\circ anticlockwise about the origin. (show answer)
    Answer
    (0,1)(0, 1)

Reasoning · Tier 2: mixed practice

  1. 1. In a quadrilateral the angles are xx, 2x2x, 100100^\circ and 8080^\circ. Find xx. (show answer)
    Answer
    x=60x = 60^\circ. Method: x+2x+100+80=360x + 2x + 100 + 80 = 360; so 3x=1803x = 180.
  2. 2. A rhombus has one diagonal 66 cm and the other 88 cm. Find the length of a side. (Hint: the diagonals meet at right angles.) (show answer)
    Answer
    55 cm. Method: diagonals meet at right angles and bisect each other; half-diagonals are 33 and 44; Pythagoras 32+42\sqrt{3^2 + 4^2} (or use the 33-44-55 triangle).
  3. 3. An isosceles triangle has a base angle of 4040^\circ. Find its apex angle. (show answer)
    Answer
    100100^\circ. Method: base angles are both 4040^\circ; apex =18080= 180 - 80.
  4. 4. A kite has two unequal pairs of adjacent sides: two sides of 55 cm and two sides of 88 cm. What is its perimeter? (show answer)
    Answer
    2626 cm. Method: 5+5+8+85 + 5 + 8 + 8.
  5. 5. List all lines of symmetry for a regular pentagon. (show answer)
    Answer
    55 lines of symmetry.
  6. 6. The point (3,2)(3, -2) is reflected in the yy-axis, then translated 11 unit down. What are the final coordinates? (show answer)
    Answer
    (3,3)(-3, -3). Method: reflect gives (3,2)(-3, -2); translate gives (3,3)(-3, -3).
  7. 7. Describe fully the single transformation that takes the point (2,3)(2, 3) to (2,3)(-2, 3). (show answer)
    Answer
    Reflection in the yy-axis.
  8. 8. A parallelogram has angles xx, 120120^\circ, xx, 120120^\circ. Find xx. (show answer)
    Answer
    6060^\circ. Method: 2x+240=3602x + 240 = 360, so x=60x = 60.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. Ida says: "every square is a rectangle". Is Ida correct? Explain. (show answer)
    Answer
    Yes, Ida is correct. A rectangle is a quadrilateral with four right angles; a square meets this (and also has all sides equal), so every square is a rectangle. The extra property "all sides equal" just makes the square a special rectangle.
  2. 2. Is every rectangle a square? Explain. (show answer)
    Answer
    No. A rectangle needs only four right angles; a square also needs four equal sides. A 3×53 \times 5 rectangle has four right angles but unequal sides, so it is a rectangle but not a square.
  3. 3. A student writes: "a trapezium is not a parallelogram". Explain when this is true and when it is not. (show answer)
    Answer
    A trapezium has at least one pair of parallel sides; a parallelogram has two pairs. Under the broad (inclusive) definition, every parallelogram is a trapezium, so the student's claim is false. Under the "exactly one pair" definition, a parallelogram is not a trapezium, so the student is correct. Both definitions are used in textbooks.
  4. 4. Explain why a rotation of 180180^\circ around the origin takes (a,b)(a, b) to (a,b)(-a, -b). (show answer)
    Answer
    A 180180^\circ rotation about the origin is a half-turn: each point moves to the point on the opposite side of the origin, the same distance away. Flipping direction from the origin negates both coordinates, so (a,b)(a,b)(a, b) \to (-a, -b).

Problem-solving · Tier 4: real-world problems

  1. 1. A window has the shape of a rectangle with an equilateral triangle on top (a "house" shape). If the rectangle is 1.21.2 m by 1.81.8 m and the triangle sits on top of the 1.21.2 m side, what is the total perimeter? (show answer)
    Answer
    66 m total. Method: rectangle perimeter =2(1.2+1.8)=6= 2(1.2 + 1.8) = 6 m; minus 1.21.2 m (the top edge is shared) =4.8= 4.8; plus the two 1.21.2 m slanted sides of the equilateral triangle; total =4.8+2.4=7.2= 4.8 + 2.4 = 7.2 m. Correct answer: 7.27.2 m.
  2. 2. A company logo is a parallelogram with sides 66 cm and 99 cm. What is its perimeter? (show answer)
    Answer
    3030 cm. Method: 2(6+9)2(6 + 9).
  3. 3. A garden tile is an isosceles trapezium with parallel sides 1010 cm and 66 cm, and the two slanting sides 55 cm each. Find its perimeter. (show answer)
    Answer
    2626 cm. Method: 10+6+5+510 + 6 + 5 + 5.
  4. 4. A kite-shaped sticker has adjacent sides of 44 cm, 44 cm, 77 cm, 77 cm. Find its perimeter. (show answer)
    Answer
    2222 cm. Method: 4+4+7+74 + 4 + 7 + 7.
  5. 5. A point P=(1,1)P = (1, 1) is rotated 9090^\circ clockwise about the origin, then reflected in the xx-axis. Find the final image. (show answer)
    Answer
    (1,1)(1, -1). Method: rotate (1,1)(1, 1) by 90-90^\circ gives (1,1)(1, -1); reflect in xx-axis gives (1,1)(1, 1). Wait - rotating (1,1)(1,1) by 90-90^\circ (clockwise) gives (1,1)(1, -1). Then reflecting in the xx-axis flips the yy-coordinate, giving (1,1)(1, 1). Final image: (1,1)(1, 1).

3D objects

Fluency · Naming, faces, edges, vertices

  1. 1. How many faces, edges, and vertices does a cube have? (show answer)
    Answer
    Cube: F=6F = 6, E=12E = 12, V=8V = 8.
  2. 2. How many faces, edges, and vertices does a triangular prism have? (show answer)
    Answer
    Triangular prism: F=5F = 5, E=9E = 9, V=6V = 6.
  3. 3. How many faces, edges, and vertices does a square pyramid have? (show answer)
    Answer
    Square pyramid: F=5F = 5, E=8E = 8, V=5V = 5.
  4. 4. Name the solid with 44 triangular faces and 44 vertices. (show answer)
    Answer
    Triangular pyramid (tetrahedron).
  5. 5. Name the solid with a hexagonal base and 66 rectangular side-faces. (show answer)
    Answer
    Hexagonal prism.
  6. 6. How many rectangular faces does a pentagonal prism have? (show answer)
    Answer
    55 rectangular faces (plus 22 pentagonal ends).
  7. 7. How many triangular faces does a square pyramid have? (show answer)
    Answer
    44 triangular faces.

Fluency · Nets

  1. 1. How many different nets fold into a cube? (show answer)
    Answer
    1111.
  2. 2. List the shapes in a net of a triangular prism. (show answer)
    Answer
    22 triangles and 33 rectangles.
  3. 3. List the shapes in a net of a rectangular prism with dimensions 3×2×43 \times 2 \times 4. (show answer)
    Answer
    66 rectangles: two 3×23 \times 2, two 3×43 \times 4, two 2×42 \times 4.
  4. 4. Draw (or describe) a net for a square pyramid with base side 44 cm and slant height 55 cm. (show answer)
    Answer
    A 44 cm square with four isosceles triangles attached to each side, each triangle with base 44 cm and slant height 55 cm.
  5. 5. A net of six squares in one long straight row - can this fold into a cube? Explain. (show answer)
    Answer
    No. Six squares in a single row overlap when folded - they cannot form a closed cube.

Reasoning · Explain and spot the mistake

  1. 1. Maya says: "every pyramid has a triangular base". Is this true? Explain. (show answer)
    Answer
    Not true. A pyramid's side-faces are always triangles, but the base can be any polygon (square, pentagon, etc.). "Triangular pyramid" is one particular type.
  2. 2. Sam counts the faces of a triangular prism as 66. Where could Sam's error be? (show answer)
    Answer
    A triangular prism has 55 faces: 22 triangular ends and 33 rectangular sides. Sam probably mixed faces with edges (which total 99) or counted the same face twice.
  3. 3. Is a cylinder a prism? Explain using the definition of a prism. (show answer)
    Answer
    Strictly no - a prism has a polygon base joined by flat rectangular sides. A cylinder has a circular base and a curved surface, not a polygon. (It is often informally called a circular prism because the volume formula V=base area×heightV = \text{base area} \times \text{height} still applies.)
  4. 4. You see the isometric drawing of an object but cannot tell whether the left side is longer than the front side. Describe one extra drawing that would resolve the ambiguity. (show answer)
    Answer
    A top view (plan) or a side elevation would resolve the ambiguity, since those show lengths directly without the isometric distortion.

Problem-solving · Real-world problems

  1. 1. A cereal box is a rectangular prism 30×20×830 \times 20 \times 8 cm. Find its total surface area and its volume. (show answer)
    Answer
    Surface area 20002000 cm^2; volume 48004800 cm^3. Method: SA =2(30×20+30×8+20×8)=2(600+240+160)=2000= 2(30 \times 20 + 30 \times 8 + 20 \times 8) = 2(600 + 240 + 160) = 2000; V=30×20×8V = 30 \times 20 \times 8.
  2. 2. A Toblerone box is a triangular prism with equilateral cross-section (side 66 cm) and length 2424 cm. Describe the net (number and size of each shape). (show answer)
    Answer
    22 equilateral triangles (side 66 cm) and 33 rectangles (66 cm by 2424 cm).
  3. 3. A square pyramid has base 88 cm and slant height 55 cm. Find its total surface area. (Base area +4×+ 4 \times triangular side area.) (show answer)
    Answer
    144144 cm^2. Method: base 82=648^2 = 64; four triangles each 12×8×5=20\tfrac{1}{2} \times 8 \times 5 = 20; total =64+4×20= 64 + 4 \times 20.
  4. 4. A shipping crate is a 11 m cube. What is the total length of all its edges? (show answer)
    Answer
    1212 m. Method: a cube has 1212 edges, each 11 m.

Reasoning · Using the formulas

  1. 1. A prism has a 77-sided base. Find VV, EE, FF. (show answer)
    Answer
    V=14V = 14, E=21E = 21, F=9F = 9. Method: n=7n = 7; V=2nV = 2n, E=3nE = 3n, F=n+2F = n + 2.
  2. 2. A pyramid has a hexagonal base. Find VV, EE, FF. (show answer)
    Answer
    V=7V = 7, E=12E = 12, F=7F = 7. Method: n=6n = 6; V=n+1V = n + 1, E=2nE = 2n, F=n+1F = n + 1.
  3. 3. A solid has V=20V = 20, E=30E = 30. Use Euler's formula to find FF. (show answer)
    Answer
    F=12F = 12. Method: VE+F=2V - E + F = 2.
  4. 4. A solid has V=6V = 6, F=8F = 8. Find EE. (show answer)
    Answer
    E=12E = 12. Method: 6E+8=26 - E + 8 = 2, so E=12E = 12.
  5. 5. A solid has 88 triangular faces. Give its name. (show answer)
    Answer
    Regular octahedron.

Coordinates & the Cartesian plane

Fluency · Tier 1: basic skills

  1. 1. Which quadrant contains (5,3)(5, 3)? (show answer)
    Answer
    Quadrant 1
  2. 2. Which quadrant contains (4,2)(-4, 2)? (show answer)
    Answer
    Quadrant 2
  3. 3. Which quadrant contains (1,7)(-1, -7)? (show answer)
    Answer
    Quadrant 3
  4. 4. Which quadrant contains (6,2)(6, -2)? (show answer)
    Answer
    Quadrant 4
  5. 5. Where does (0,4)(0, 4) lie? (show answer)
    Answer
    On the yy-axis (not in a quadrant)
  6. 6. Where does (3,0)(-3, 0) lie? (show answer)
    Answer
    On the xx-axis
  7. 7. Plot A=(2,3)A = (2, 3), B=(1,4)B = (-1, 4), C=(2,5)C = (-2, -5), D=(4,3)D = (4, -3). (show answer)
    Answer
    AA in Q1; BB in Q2; CC in Q3; DD in Q4. (Check positions on a plotted grid.)
  8. 8. State the coordinates of a point 55 units right of the origin and 22 units below. (show answer)
    Answer
    (5,2)(5, -2)
  9. 9. State the coordinates of a point 33 units left of the origin and on the xx-axis. (show answer)
    Answer
    (3,0)(-3, 0)
  10. 10. What are the coordinates of the origin? (show answer)
    Answer
    (0,0)(0, 0)
  11. 11. Find the coordinates reached by starting at (1,1)(1, 1) and moving 33 right and 55 down. (show answer)
    Answer
    (4,4)(4, -4)
  12. 12. What quadrant do you enter if you reflect (2,3)(2, 3) in the yy-axis? (show answer)
    Answer
    Quadrant 2 (the point becomes (2,3)(-2, 3))
  13. 13. What quadrant do you enter if you reflect (4,5)(-4, 5) in the xx-axis? (show answer)
    Answer
    Quadrant 3 (the point becomes (4,5)(-4, -5))
  14. 14. Give any point on the yy-axis with yy negative. (show answer)
    Answer
    Any point of the form (0,n)(0, n) with n<0n < 0, e.g. (0,3)(0, -3)
  15. 15. Give any point in quadrant 3. (show answer)
    Answer
    Any point with both coordinates negative, e.g. (1,1)(-1, -1)

Reasoning · Tier 2: mixed practice

  1. 1. Plot the points (1,2),(2,4),(3,6),(4,8)(1, 2), (2, 4), (3, 6), (4, 8). Describe the pattern between xx and yy. (show answer)
    Answer
    y=2xy = 2x. Each yy-value is double its xx-value; the points lie on the line y=2xy = 2x.
  2. 2. Plot (3,0),(1,0),(1,0),(3,0)(-3, 0), (-1, 0), (1, 0), (3, 0). What do all these points have in common? (show answer)
    Answer
    They all lie on the xx-axis (every yy-coordinate is 00).
  3. 3. A triangle has vertices (0,0),(4,0),(0,3)(0, 0), (4, 0), (0, 3). Find its area. (show answer)
    Answer
    66 units2^2. Method: right-angled triangle with legs 44 and 33; area =12(4)(3)= \dfrac{1}{2}(4)(3).
  4. 4. A rectangle has opposite corners at (1,1)(1, 1) and (6,4)(6, 4). Find its perimeter and area. (show answer)
    Answer
    Perimeter 1616 units; area 1515 units2^2. Method: length =61=5= 6 - 1 = 5; height =41=3= 4 - 1 = 3; P=2(5+3)=16P = 2(5 + 3) = 16; A=5×3=15A = 5 \times 3 = 15.
  5. 5. Complete the table for y=2x1y = 2x - 1 and then plot the points:

    | xx | 2-2 | 1-1 | 00 | 11 | 22 | |---|---|---|---|---|---| | yy | ? | ? | ? | ? | ? |
    (show answer)
    Answer
    yy-values: 5, 3, 1, 1, 3-5,\ -3,\ -1,\ 1,\ 3.
  6. 6. Check whether the point (3,5)(3, 5) lies on the line described by y=2x1y = 2x - 1. (show answer)
    Answer
    Yes. When x=3x = 3, y=2(3)1=5y = 2(3) - 1 = 5, matching.
  7. 7. A point is reflected in the xx-axis. Which coordinate changes sign? (show answer)
    Answer
    The yy-coordinate changes sign.
  8. 8. Translate (4,2)(4, -2) by (63)\binom{-6}{3}. Find the image. (show answer)
    Answer
    (2,1)(-2, 1).

Reasoning · Tier 3: explain and spot the mistake

  1. 1. Ravi plots (2,3)(-2, 3) by going right 22 and up 33. What has Ravi done wrong? (show answer)
    Answer
    Ravi treated the xx-coordinate as positive. For (2,3)(-2, 3) you move 22 units left (because xx is negative), then 33 up. The point belongs in quadrant 2, not quadrant 1.
  2. 2. Explain why (0,5)(0, 5) is not in any quadrant. (show answer)
    Answer
    The four quadrants are the open regions between the axes - they exclude the axes themselves. Since (0,5)(0, 5) has x=0x = 0, it lies on the yy-axis, not inside any quadrant.
  3. 3. A student says "every point with positive coordinates is in quadrant 1". Is that correct? Explain. (show answer)
    Answer
    Almost. If both coordinates are strictly positive, the point is in quadrant 1. But if one of them is 00 (e.g. (3,0)(3, 0) or (0,3)(0, 3)), the point sits on an axis, not in the quadrant. So the correct statement is "every point with strictly positive coordinates is in quadrant 1".
  4. 4. Write three different points on the line y=xy = x. (show answer)
    Answer
    Any points where the two coordinates are equal, e.g. (0,0)(0, 0), (1,1)(1, 1), (2,2)(-2, -2).

Problem-solving · Tier 4: real-world problems

  1. 1. A town map uses a Cartesian system with a school at the origin. The library is at (3,2)(3, 2) (each unit is 100100 m east/north). How far east and how far north of the school is the library? How far in a straight line? (Hint: use Pythagoras.) (show answer)
    Answer
    300300 m east, 200200 m north; straight-line distance 360.6\approx 360.6 m. Method: Pythagoras 3002+2002\sqrt{300^2 + 200^2}.
  2. 2. A boat leaves a harbour (0,0)(0, 0) and sails 44 units east, then 33 units north, then 22 units west. What are its current coordinates? How far is it from the harbour in a straight line? (show answer)
    Answer
    (2,3)(2, 3); distance 22+32=133.6\sqrt{2^2 + 3^2} = \sqrt{13} \approx 3.6 units. Method: 42=24 - 2 = 2 east; 33 north.
  3. 3. Three vertices of a rectangle are (1,1),(7,1),(7,5)(1, 1), (7, 1), (7, 5). Find the fourth vertex and the rectangle's perimeter. (show answer)
    Answer
    Fourth vertex (1,5)(1, 5); perimeter 2020 units. Method: width 66 (from 11 to 77), height 44 (from 11 to 55); P=2(6+4)P = 2(6 + 4).
  4. 4. A park has corners at (0,0),(8,0),(8,5),(0,5)(0, 0), (8, 0), (8, 5), (0, 5). Where is the centre of the park? (Hint: average the coordinates of opposite corners.) (show answer)
    Answer
    Centre at (4,2.5)(4, 2.5). Method: average opposite corners, e.g. (0+8)/2,(0+5)/2(0+8)/2, (0+5)/2.
  5. 5. The midpoint between the points (2,3)(2, 3) and (6,7)(6, 7) lies at what coordinates? (Hint: average of the xxs and average of the yys.) (show answer)
    Answer
    Midpoint (4,5)(4, 5).

Data display

Fluency · Tier 1: basic skills

  1. 1. Classify as categorical, discrete numerical, or continuous numerical: eye colour. (show answer)
    Answer
    Categorical
  2. 2. Classify: number of pets owned. (show answer)
    Answer
    Discrete numerical
  3. 3. Classify: weight of a parcel. (show answer)
    Answer
    Continuous numerical
  4. 4. Classify: gender identity. (show answer)
    Answer
    Categorical
  5. 5. Classify: temperature at noon. (show answer)
    Answer
    Continuous numerical
  6. 6. Classify: shoe size (UK sizing: 5, 5.5, 6, ...). (show answer)
    Answer
    Discrete numerical (values come in fixed jumps)
  7. 7. Build a frequency table from: A, B, A, C, B, A, A, C, B, A. (show answer)
    Answer
    A: 55, B: 33, C: 22. Total 1010.
  8. 8. A frequency table shows 5,7,35, 7, 3 in three categories. What is the total sample size? (show answer)
    Answer
    1515
  9. 9. Which graph is best for categorical data: line graph, column graph, or stem-and-leaf? (show answer)
    Answer
    Column graph
  10. 10. Which graph keeps individual values visible: dot plot or column graph? (show answer)
    Answer
    Dot plot
  11. 11. Read from the stem-and-leaf plot: 23 5 82 \mid 3\ 5\ 8. Write the three values. (show answer)
    Answer
    23, 25, 2823,\ 25,\ 28
  12. 12. In a dot plot, 44 dots stack above the number 77. What does this mean? (show answer)
    Answer
    Four data values of 77 appeared in the sample.
  13. 13. A column graph has heights 8,12,5,158, 12, 5, 15. What is the sum of frequencies? (show answer)
    Answer
    4040
  14. 14. A bar graph's vertical axis starts at 5050 instead of 00. Why might this be misleading? (show answer)
    Answer
    It stretches small differences so bars look very different when they are actually close.

Reasoning · Tier 2: mixed practice

  1. 1. Build a frequency table. (show answer)
    Answer
    Size 66: 11, Size 77: 44, Size 88: 55, Size 99: 44, Size 1010: 11.
  2. 2. What is the modal shoe size (the most common)? (show answer)
    Answer
    88 (appears most often).
  3. 3. Describe the distribution (symmetrical, skewed, or otherwise). (show answer)
    Answer
    Roughly symmetrical around 88.
  4. 4. If you were to draw a dot plot, how many dots would stack above 88? (show answer)
    Answer
    55 dots.
  5. 5. What type of graph would you not use for this data, and why?

    The following stem-and-leaf plot shows exam marks out of 100100 for a class:

    `` Stem | Leaf 4 | 2 5 8 5 | 0 3 3 7 9 6 | 1 1 4 8 7 | 0 2 5 ``
    (show answer)
    Answer
    A line graph would be inappropriate: shoe sizes are discrete, not a continuous change over time.

    Questions 6-9 from the stem-and-leaf plot:
  6. 6. How many students are in the class? (show answer)
    Answer
    1515 students.
  7. 7. What is the lowest score? The highest score? (show answer)
    Answer
    Lowest 4242; highest 7575.
  8. 8. What mark was scored by the most students? (show answer)
    Answer
    5353 (two students scored 5353) and 6161 (two students scored 6161) - both are modes; the data is bimodal.
  9. 9. What is the range of the scores? (max - min.) (show answer)
    Answer
    Range =7542=33= 75 - 42 = 33.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. Ben plots temperatures taken every hour from 66 a.m. to 66 p.m. as a column graph with gaps between bars. Is the column graph the best choice here? Explain. (show answer)
    Answer
    A line graph would be better. Temperature varies continuously with time, so joining the hourly readings with a line shows the trend clearly. Columns with gaps suggest separate, independent categories rather than a single continuous variable.
  2. 2. A graph shows sales for three products with bar heights 50,51,5250, 51, 52, and the yy-axis starts at 4949. Explain why this graph could mislead a reader. (show answer)
    Answer
    Starting the yy-axis at 4949 exaggerates tiny differences - the 5050-vs-5252 gap becomes several times taller than it should. A reader glancing at the bar heights might think product CC sells vastly more than AA, when it's only 525050=4%\tfrac{52 - 50}{50} = 4\% more. Always check whether the yy-axis starts at zero before comparing bar heights.
  3. 3. Can a single data point be both an outlier and the mode? Explain. (show answer)
    Answer
    Usually not. The mode is the most frequent value while an outlier is a value unusually far from the rest. In an extreme case (e.g. a dataset where one far value appears many times) a single value could be both - but in typical distributions the mode sits in the middle of the bulk, not at the tail.
  4. 4. A friend says "categorical data can be averaged". Is this correct? Give an example that supports your view. (show answer)
    Answer
    Not in the arithmetic sense - you cannot average "red", "blue", "green". You can count frequencies for each category and quote the mode (the most common category), but the mean and median don't apply to purely categorical data.

Problem-solving · Tier 4: real-world problems

  1. 1. A class survey of favourite sports gave: AFL 99, Soccer 77, Basketball 55, Cricket 44, Other 22. How many students were surveyed? Draw (describe) a column graph for this data. (show answer)
    Answer
    2727 students. Column graph: bars for each sport with heights 9,7,5,4,29, 7, 5, 4, 2; yy-axis shows frequency, xx-axis shows sport.
  2. 2. In one week a shop recorded daily customer numbers: Mon 4242, Tue 3838, Wed 4545, Thu 5050, Fri 6565, Sat 8080, Sun 6060. Which graph type would you use? What total was served? (show answer)
    Answer
    Line graph (daily values over the week, with days on the xx-axis). Total customers served: 42+38+45+50+65+80+60=38042 + 38 + 45 + 50 + 65 + 80 + 60 = 380.
  3. 3. The temperatures in a city ( degC) every hour from 99 a.m. to 55 p.m. were: 18,20,22,24,26,27,26,24,2218, 20, 22, 24, 26, 27, 26, 24, 22. Which display is best? At what time was the maximum reached? (show answer)
    Answer
    Line graph. Maximum at 22 p.m. (2727 degC).
  4. 4. A class measured heights (cm) of 1414 students: 145,150,152,150,155,148,162,158,150,155,160,153,149,156145, 150, 152, 150, 155, 148, 162, 158, 150, 155, 160, 153, 149, 156. Construct a stem-and-leaf plot. (show answer)
    Answer
    Stem-and-leaf plot:

    `` Stem | Leaf 14 | 5 8 9 15 | 0 0 0 2 3 5 5 6 8 16 | 0 2 ``
  5. 5. A town's population over 55 decades was 1200012\,000, 1500015\,000, 2200022\,000, 2800028\,000, 3100031\,000. Which graph shows the trend best, and why? (show answer)
    Answer
    Line graph. It shows the trend (steady growth) over time clearly.

Summary statistics

Fluency · Tier 1: basic skills

  1. 1. Find the mean of 4,6,8,10,124, 6, 8, 10, 12. (show answer)
    Answer
    88
  2. 2. Find the mean of 3,7,5,9,63, 7, 5, 9, 6. (show answer)
    Answer
    66
  3. 3. Find the mean of 12,14,18,2012, 14, 18, 20. (show answer)
    Answer
    1616
  4. 4. Find the median of 1,3,5,7,91, 3, 5, 7, 9. (show answer)
    Answer
    55
  5. 5. Find the median of 4,8,6,2,104, 8, 6, 2, 10. (show answer)
    Answer
    66. Sorted: 2,4,6,8,102, 4, 6, 8, 10.
  6. 6. Find the median of 3,5,8,103, 5, 8, 10. (show answer)
    Answer
    6.56.5. Sorted: 3,5,8,103, 5, 8, 10; mean of 55 and 88.
  7. 7. Find the median of 11,13,14,17,18,2011, 13, 14, 17, 18, 20. (show answer)
    Answer
    15.515.5. Mean of middle two 1414 and 1717.
  8. 8. Find the mode of 2,3,3,5,7,3,92, 3, 3, 5, 7, 3, 9. (show answer)
    Answer
    33 (appears three times)
  9. 9. Find the mode of 4,4,6,6,7,84, 4, 6, 6, 7, 8. (show answer)
    Answer
    44 and 66 (bimodal)
  10. 10. Find the range of 2,7,5,9,32, 7, 5, 9, 3. (show answer)
    Answer
    77. Method: 929 - 2.
  11. 11. Find the range of 45,60,72,38,5545, 60, 72, 38, 55. (show answer)
    Answer
    3434. Method: 723872 - 38.
  12. 12. A data set: 10,12,14,16,18,2010, 12, 14, 16, 18, 20. Find the mean. (show answer)
    Answer
    1515
  13. 13. For the set 5,5,6,8,115, 5, 6, 8, 11, find the mean, median, mode, range. (show answer)
    Answer
    Mean 77; median 66; mode 55; range 66.

Reasoning · Tier 2: mixed practice

  1. 1. Sort the data and find the median. (show answer)
    Answer
    Sorted: 12,14,15,15,15,16,17,18,18,2012, 14, 15, 15, 15, 16, 17, 18, 18, 20; median =15+162=15.5= \dfrac{15 + 16}{2} = 15.5.
  2. 2. Find the mean. (show answer)
    Answer
    1616. Method: sum =160= 160; 160÷10160 \div 10.
  3. 3. Find the mode. (show answer)
    Answer
    1515 (appears three times).
  4. 4. Find the range. (show answer)
    Answer
    88. Method: 201220 - 12.
  5. 5. If you added the value 100100 to this data set, which of mean, median, mode, range would change most? Explain briefly. (show answer)
    Answer
    Range changes most (from 88 to 8888). The mode is unaffected. The median shifts only slightly; the mean goes up by about 7.67.6.
  6. 6. Five students scored an average of 7070 on a test. Four of the scores are 65,72,68,7565, 72, 68, 75. Find the fifth score. (show answer)
    Answer
    7070. Method: total required =5×70=350= 5 \times 70 = 350; subtract 65+72+68+75=28065 + 72 + 68 + 75 = 280.
  7. 7. The mean of 66 numbers is 1818. Five of them are 15,20,12,18,2215, 20, 12, 18, 22. Find the sixth. (show answer)
    Answer
    2121. Method: total =6×18=108= 6 \times 18 = 108; sum of five given =87= 87; 10887=21108 - 87 = 21.
  8. 8. A data set has mean 1515 and 1010 values. If one value is wrongly recorded as 88 but should be 1818, what is the correct mean? (show answer)
    Answer
    1616. Method: original total =15×10=150= 15 \times 10 = 150; correction +10+10 gives 160160; new mean 160÷10160 \div 10.
  9. 9. Give an example of a data set with mean 1010, median 1010, mode 1010 and range 00. (show answer)
    Answer
    Any data set with all values equal to 1010, e.g. {10,10,10,10}\{10, 10, 10, 10\}.
  10. 10. Give an example of a data set with 55 values where mean >> median. (show answer)
    Answer
    Many possible. Example: 1,2,3,4,401, 2, 3, 4, 40. Mean =10= 10, median =3= 3.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. A student writes: "the mode is 1010 because 1010 is the biggest number in the list". Explain the confusion and give the correct definition. (show answer)
    Answer
    The mode is the most frequently occurring value, not the largest one. The student has confused mode with maximum (the upper end of the range). Correct: the mode is whichever value appears most often; a data set can have no mode, one mode, or multiple modes.
  2. 2. Explain why the median is usually a better measure than the mean when a data set has a single extreme value. (show answer)
    Answer
    The mean uses every value, so a single extreme number can pull it noticeably up or down. The median depends only on position in the sorted list, so one outlier only shifts the middle by one rank at most - hence the median remains close to the bulk of the data when there are extreme values.
  3. 3. Can a data set have a mode but no mean? Can it have a mean but no mode? Explain both. (show answer)
    Answer
    Yes to both. Categorical data (e.g. eye colours) can have a mode (most common colour) but no mean - you cannot average "red", "blue", "green". A data set with all distinct numerical values (e.g. 1,2,3,41, 2, 3, 4) has a mean (2.52.5) but no mode, since no value repeats.
  4. 4. Is the median always in the data set? Give an example where it is not. (show answer)
    Answer
    Not always. For an even-count numerical set, the median is the average of the two middle values, which may not itself be in the data. Example: median of {2,4}\{2, 4\} is 33, which is not in the set.

Problem-solving · Tier 4: real-world problems

  1. 1. A cricket batter's last 77 scores are 23,45,12,38,62,51,2923, 45, 12, 38, 62, 51, 29. Find the mean and median. (show answer)
    Answer
    Mean 37.1\approx 37.1; median 3838. Method: sum =260= 260; mean =260/7= 260 / 7; sort and take the 44th value (3838).
  2. 2. A family has children aged 4,7,10,134, 7, 10, 13. Another child aged 1616 joins. Find the new mean age. (show answer)
    Answer
    Mean age =10= 10. Method: sum =4+7+10+13+16=50= 4 + 7 + 10 + 13 + 16 = 50; 50÷550 \div 5.
  3. 3. The daily temperatures ( degC) for a week: 22,25,21,28,30,24,2322, 25, 21, 28, 30, 24, 23. Find the mean temperature and the range. (show answer)
    Answer
    Mean 24.7\approx 24.7 degC (exactly 173/7173/7); range 99 degC. Method: 173÷724.71173 \div 7 \approx 24.71; 302130 - 21.
  4. 4. Seven students scored an average of 6060 marks. Adding a new student with a score of 7676 changes the class size to 88. What is the new mean? (show answer)
    Answer
    New mean =62= 62. Method: previous total =7×60=420= 7 \times 60 = 420; new total =420+76=496= 420 + 76 = 496; 496÷8=62496 \div 8 = 62.
  5. 5. A data set of 1010 values has a mean of 5050. The smallest value is 2020 and the largest is 9090. What is the mean of the middle 88 values (the 1010 values with the min and max removed)? (show answer)
    Answer
    Mean of middle 88 is 48.7548.75. Method: total of all 1010 is 500500; remove 20+90=11020 + 90 = 110; remaining total 390390; 390÷8390 \div 8.

Probability

Fluency · Tier 1: basic skills

  1. 1. P(rollinga3)P(rolling a 3). (show answer)
    Answer
    16\dfrac{1}{6}
  2. 2. P(odd)P(odd). (show answer)
    Answer
    12\dfrac{1}{2}
  3. 3. P(numberlessthan3)P(number less than 3). (show answer)
    Answer
    13\dfrac{1}{3} (outcomes 11 and 22)
  4. 4. P(numbergreaterthan4)P(number greater than 4). (show answer)
    Answer
    13\dfrac{1}{3} (outcomes 55 and 66)
  5. 5. P(rollinga7)P(rolling a 7).

    A bag has 44 red, 33 blue, 22 green, 11 yellow marble (1010 total). For questions 6-10:
    (show answer)
    Answer
    00 (impossible)
  6. 6. P(red)P(red). (show answer)
    Answer
    410=25\dfrac{4}{10} = \dfrac{2}{5}
  7. 7. P(blue)P(blue). (show answer)
    Answer
    310\dfrac{3}{10}
  8. 8. P(notgreen)P(not green). (show answer)
    Answer
    810=45\dfrac{8}{10} = \dfrac{4}{5}
  9. 9. P(redorblue)P(red or blue). (show answer)
    Answer
    710\dfrac{7}{10}
  10. 10. P(pink)P(pink). (show answer)
    Answer
    00
  11. 11. What is P(certain)P(certain)? (show answer)
    Answer
    11
  12. 12. What is P(impossible)P(impossible)? (show answer)
    Answer
    00
  13. 13. Convert probability 0.40.4 to a fraction and to a percentage. (show answer)
    Answer
    25\dfrac{2}{5}; 40%40\%
  14. 14. P(A)=38P(A) = \dfrac{3}{8}. Find P(A)P(A'). (show answer)
    Answer
    58\dfrac{5}{8}
  15. 15. A fair coin is flipped. What is P(heads)P(heads)? (show answer)
    Answer
    12\dfrac{1}{2}
  16. 16. A spinner has sectors coloured red/red/blue/green/green/green. Find P(green)P(green). (show answer)
    Answer
    36=12\dfrac{3}{6} = \dfrac{1}{2}

Reasoning · Tier 2: mixed practice

  1. 1. A bag contains 55 red and 77 blue counters. A counter is drawn at random. Find P(red)P(red) and P(blue)P(blue). (show answer)
    Answer
    P(red)=512P(red) = \dfrac{5}{12}; P(blue)=712P(blue) = \dfrac{7}{12}.
  2. 2. A coin is flipped twice. List the sample space. (show answer)
    Answer
    {HH,HT,TH,TT}\{HH, HT, TH, TT\} - four outcomes.
  3. 3. A spinner has four equal sectors labelled 1,2,3,41, 2, 3, 4 and is spun twice. How many outcomes are in the sample space? (show answer)
    Answer
    1616 outcomes (4×44 \times 4).
  4. 4. Two dice are rolled and the sum is recorded. What is the most likely sum? What is its probability? (show answer)
    Answer
    77, with probability 636=16\dfrac{6}{36} = \dfrac{1}{6}.
  5. 5. A bag has 1212 marbles: xx red and the rest blue. If P(red)=14P(red) = \dfrac{1}{4}, how many red marbles are there? (show answer)
    Answer
    33 red marbles. Method: 14×12=3\dfrac{1}{4} \times 12 = 3.
  6. 6. A card is drawn from a standard deck of 5252. Find P(heart)P(heart). (show answer)
    Answer
    1352=14\dfrac{13}{52} = \dfrac{1}{4}.
  7. 7. A card is drawn from a standard deck. Find P(facecard)P(face card). (Face cards are J, Q, K; 1212 in total.) (show answer)
    Answer
    1252=313\dfrac{12}{52} = \dfrac{3}{13}.
  8. 8. If P(A)=0.35P(A) = 0.35, what is P(A)P(A')? (show answer)
    Answer
    0.650.65.

Reasoning · Tier 3: explain and spot the mistake

  1. 1. A student says "I flipped a coin 44 times and got 33 heads, so the probability of heads is 34\dfrac{3}{4}". Explain what is right and what is wrong in this statement. (show answer)
    Answer
    The student has calculated the experimental probability (34\dfrac{3}{4}) based on a tiny sample. That is a correct observation about those four flips, but it is not the theoretical probability of a fair coin, which stays at 12\dfrac{1}{2}. With only 44 trials, short-run results can easily drift from the theoretical value; many more trials are needed before the experimental probability settles near 12\dfrac{1}{2}.
  2. 2. After flipping a coin and getting tails 55 times in a row, Ben says "the next flip is more likely to be heads". Is Ben correct? Explain. (show answer)
    Answer
    Ben is wrong - this is the "gambler's fallacy". Each coin flip is independent: the coin has no memory of past results. On the next flip P(heads)=12P(\text{heads}) = \dfrac{1}{2} regardless of the previous five outcomes.
  3. 3. Leah says "the probability of rain tomorrow is 110%110\%". Explain why this cannot be right. (show answer)
    Answer
    Probabilities must lie between 00 and 11 (or 0%0\% and 100%100\%). A value above 100%100\% would mean "more than certain", which is meaningless. The maximum possible probability is 100%100\%.
  4. 4. Give an example of two events where P(A)+P(B)=1P(A) + P(B) = 1 but AA and BB are not complements. (show answer)
    Answer
    Two events whose probabilities add to 11 are not necessarily complements - complements have to cover all outcomes and not overlap. A simple example from separate experiments: let A=A = "heads on coin 1" with P(A)=12P(A) = \dfrac{1}{2}, and B=B = "tails on coin 2" with P(B)=12P(B) = \dfrac{1}{2}. Then P(A)+P(B)=1P(A) + P(B) = 1, but AA and BB are not complements of each other.

Problem-solving · Tier 4: real-world problems

  1. 1. A weather report gives the chance of rain tomorrow as 30%30\%. What is the probability it does not rain? (show answer)
    Answer
    70%70\% or 0.70.7. Method: 10.301 - 0.30.
  2. 2. A class has 2828 students: 1212 play netball, 1616 do not. One student is chosen at random. Find the probability the student plays netball. (show answer)
    Answer
    1228=37\dfrac{12}{28} = \dfrac{3}{7}.
  3. 3. In a raffle with 500500 tickets, you buy 2020. What is the probability you win? Express as a percentage and as a decimal. (show answer)
    Answer
    20500=0.04=4%\dfrac{20}{500} = 0.04 = 4\%.
  4. 4. A fair die is rolled 6060 times. How many times would you expect to roll a 66? If actually 1414 sixes came up, what is the experimental probability? (show answer)
    Answer
    Expected: 1010 sixes. Experimental: 1460=7300.233\dfrac{14}{60} = \dfrac{7}{30} \approx 0.233.
  5. 5. A spinner is divided into sectors of sizes 1,2,3,41, 2, 3, 4 (measured in equal angle units summing to 1010). Find the probability of landing on the largest sector. (show answer)
    Answer
    410=25\dfrac{4}{10} = \dfrac{2}{5}.
  6. 6. A bag has 88 red, 55 blue and some green marbles. If P(green)=14P(green) = \dfrac{1}{4}, how many green marbles are in the bag? (show answer)
    Answer
    Let gg be the number of green. Total =13+g= 13 + g. g13+g=14\dfrac{g}{13 + g} = \dfrac{1}{4}, so 4g=13+g4g = 13 + g; 3g=133g = 13; g4.33g \approx 4.33. Not a whole number - something is off with the setup. In practice we want g8+5+g=14\dfrac{g}{8 + 5 + g} = \dfrac{1}{4}, giving 4g=13+g4g = 13 + g, 3g=133g = 13. Since gg must be whole, the closest sensible answer is that the ratios do not allow an integer solution. Possible intended answer: if P(green)=13P(green) = \dfrac{1}{3}, then g=6.5g = 6.5; still not integer. Teachers might use P(green)=15P(green) = \dfrac{1}{5}: then 5g=13+g5g = 13 + g, g=3.25g = 3.25. Note to student and teacher: as written, the question has no integer solution; a common textbook version gives P(green)=13P(green) = \dfrac{1}{3} with 1010 red and 55 blue, yielding g=7.5g = 7.5. If this comes up, flag the inconsistency and work the algebra to show why.